The question we’re being asked is how can we neutralize acids and bases stop that the PH is 7. There are more than one variable that can told, but we’re going to say a few. One variable is the PH of the acid or base. If the acid is 1 and the base is 8, it’ll be harder to neutralize than something like 8 and 6. Another variable is the amount of acid and bases there are. If you have 20 ml of acid and 60 ml of base it’ll be harder to neutralize. That’ll also mess up your hypothesis. My hypothesis is that it’ll take 25 ml of acid and 30 ml of base to neutralize. I think so because the is weaker than the acid. I also think so because the procedure will make it easier if you have a starting point. Materials: 6 beakers 2 cylinders 2 stirring straws 100 ml of an acid (Vinegar) 100 ml of a base (Ammonia) 100 ml of an insulator Picture of how each PH color should be I. Put 100 ml of vinegar (acid) in one beaker and the other 100 ml of ammonia in the next beaker II. Have a starting point (with at least 20 ml of each) and mix the 2 with 10 ml of insulator III. Look at the picture and compare IV. If it isn’t the color of a PH of 7 repeat ll. And repeat V. Analyze once the PH Is 7

My analysis is that with the more vinegar you add and less ammonia, the PH will be less the 7. If you add more base and little to no vinegar, you’ll have a PH over 7. I think that you should at least 20 ml of vinegar and over 25 ml of ammonia to neutralize. My conclusion was not correct because the base was too small. My data shows that with the more base there is, the more close you get with the PH. There are some errors though.
Some possible errors could be what acid you use and the base you use. Another error is the amount of insulator you use and the type.