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Enzyme Reaction Lab Report

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Introduction:
This report will talk about the experiment that was conducted to see what percent of hydrogen peroxide had the greatest reaction with the potato cube. The enzyme in this experiment was catalase, which could be found inside of the potato cube. The substrate was the hydrogen peroxide. The role of the potato cube was to react with the hydrogen peroxide causing it to break down at a quicker rate which released oxygen (O₂). Three factors that could influence the enzyme’s activity is the temperature, the acidity level and the amount of substrate that was present. The goal of this experiment was to determine the effect of varying percentages of hydrogen peroxide on the oxygen production. The hypothesis was, the greater the concentration of hydrogen peroxide, the faster of a reaction it will have with a 1 inch by 1 inch potato cube. This would be due to the greater substrate concentration.

Methods: …show more content…
The catalase within the potato cube acted as the enzyme throughout the experiment. The potato cubes were placed inside of centrifuge tubes with perforated caps with different concentrations of hydrogen peroxide. During the experiment 1.5%, 3%, 9% and 12% of hydrogen peroxide was used. Each experiment was conducted 5 times and an average was found to get the best data possible. Each potato cube was exposed to the hydrogen peroxide for three minutes. At the end of the three minutes the oxygen production was measured in milliliters. The independent variable for this experiment was the concentration that the potato cubes were exposed during the experiment. The dependent variable in this experiment was the production of oxygen (O₂) which is a product of enzyme

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