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Hejsa

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Submitted By kauff
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Grgrgrg hey jehfe hebhef ehbfehebfe ehhebfheb hf f f f f f f f f f f f f f f f f f f f f f f f f f f f f f f f f f f f f f f f f f f f ffbjhfbf ebhef enbef e fne fnf en fn fen fn enf ne fne fne nef ne efn enf enf enf ne fne fne fne fne fen fne fnef en fne fen fnef enf fenf en nf nef nef nfe nef nf fn fen fn wef FE EF EFEF EF E FE EFEF EF EF EF EF FE ES FDD FS FD SF DSF D FS DF DFD SFDF DS FD SF DF D F E TRR GR G RG RG F D FD S SDD DS D F DF E F R RT G G D S S FE F E D D GG R R W SS F E F D SF SF E F EF RT R TTR D DS SF E FE E F DS DF E F EEF E S SE ESF EW FE S SD F DS F E SE E FE F ER FR G G GR S SJFEFEJ J U EJF B BF EFB SBSUS BJSBSJFB UEFBJ BE BUEFJEBE BUFB EJBFJ BE UFJ FJEFBJE BEJFBEJFB JEFBEJFB JBFEJBFEJEBFEE E E F EF FEJ J J NJBEFJ JFEJFB EJ JEJFEFJEHJFHEJF NF EJNF NEJFNN FEJFNJEN FJNE JFNJ ENFJENFJ NFEJ NF JENFJE NEF JEFN EJN JFENFJENF JEN JENFEJ NFEJ

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Hejsa

...Aflevering – Ensvinklede trekanter Opgave 1 a) Bestem flagstangens højde. Opgave 2 a) Beregn de resterende sider. Ved at finde forstørrelsesfaktoren kan jeg beregne de resterende sider. Jeg får af vide at min mindste side i den ukendte trekant er 18. Og da den mindste side er 12, må 12 altså være forstørret til 18. Så kan jeg sige 18/12 = 1,5 og dermed har jeg fundet ud af at min forstørrelsesfaktor er 1,5 a = 12*1,5 = 18 b = 18*1,5 = 27 c = 27*1,5 = 40,5 Opgave 3 a) For at finde ud af hvor meget længere skyggen er, skal jeg finde forstørrelsesfaktoren. Det gør jeg ved at sige 16/12. Det giver 1,33 og dermed har vi vores forstørrelsesfaktor. Vi har fundet den første, så for at finde den næste gør vi sådan: 20*1,33=26,67 Altså kaster det 16 meter høje hus, 26,67 meter skygge. Opgave 4 7) 5p-2q-r+3p-q+2r=5p-10q-5r+3p-3q+6r=2p-13q+1r 8) 2a+2b+a-b=2a+4b+a-b=3a+5b 9) 4c-d-3c+2d=4c-4d-3c+6d=7c-2d 10) 4a+5b+73a+b=4a+20b+21a+7b=25a+27b Opgave 5 a) 3(x-1)=6 3x-3=6 3x=3+6 3x3=93 x=3 b) 3-2x=4x 3=4x+3x 3=6x 36=6x6 0,5=x c) 2(1-2x)+5x=7 2-4x+5x=7 -4x+5x=7-2 x=5 d) -0,52x-4=2 -x+2=2 -x=2-2 Jeg ændrer nu fortegnet på begge, da x skal være positiv x=2+2 x=4 Opgave 6 a) Eftersom at F1 er opadgående må den jo være positiv b) Da F2 er nedadgående må den være negativ c) F3 er konstant og er derfor hverken negativ eller...

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...The only one And then it happened. She looked at me. She looked me deep in the eyes. It was one of those days she had her beautiful yellow dress on and had untied her gorgeous dark brown hair. I remember that day they had teased her, and she had sat on my bed, at my home and cried. They can be really silly sometimes. She didn’t do anything, yet she got her hair clipped off on the left side. And even when she was half bald, she looked like she always do, perfect! But now, she stands here and looks at me. It’s like all the things she did to me just disappears. All the bitter words she had been standing and shouted at me, they all just disappear. Her eyes are shining as if there were several million stars in them. So what if she was one of them? They think they know her. They think she is like them, but they don’t know that once she was mine. Maybe she’s handing around with them, and maybe her new boyfriend is one of them, but they do not know her. They do not know that she prays every night. They do not know why she wears a necklace I gave her. They don’t even know that I gave her that necklace. I know what she sees every time she closes her eyes. She looked down, and then up at me again. I know she will do it all over for the last time. But how cans a broken heart broke again? I would do anything to see her smile, just one more time. She thinks they are her friends because they are sitting around her. But she believes in everything. She believes in the three words no matter...

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