...Unit 9 – P3 – M2 This assignment will describe the role of advertising agencies and the media in development of a promotional campaign. P3: An advertisement agency is a service that is dedicated to creating, planning and handling advertisement and other forms of promotion for its clients. The President (CEO): The CEO is the main chairman of the company, usually the person who founded the company. Account services: In this particular campaign the Agency appointed the account executive to liaise with the clients. The account executives need to be sufficiently aware of the client's needs and desires that can be instructed to the agency's personnel and should get approval from the clients on the agency's recommendations to the clients. The account manager will develop a creative brief, usually about a page that gives direction to the creative team. The creative brief often includes information about the target audience and their attitudes and behaviours. The creative team will take the brief and, aware of their parameters; develop original copy and graphics depending on media strategy. Media Services: In this particular campaign the media services department may not be so well known, but its employees are the people who have contacts with the suppliers of various creative media. For example, they advised upon and negotiate with printers because the agency is producing flyers for the client. However, when dealing with the major media (broadcast media, outdoor, and the press)...
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...Length Length | Name of unit | Symbol | Definition | Relation to SI units | angstrom | Å | ≡ 1×10−10 m | ≡ 0.1 nm | astronomical unit | AU | ≈ Distance from Earth to Sun | ≈ 149597871464 m [1] | barleycorn (H) | | = ⅓ in (see note above about rounding) | ≈ 8.46×10−3 m | bohr, atomic unit of length | a0 | ≡ Bohr radius of hydrogen | ≈ 5.2917720859×10−11 ± 3.6×10−20 m[2] | cable length (imperial) | | ≡ 608 ft | ≈ 185.3184 m | cable length (International) | | ≡ 1/10 nmi | ≡ 185.2 m | cable length (US) | | ≡ 720 ft | = 219.456 m | chain (Gunter's; Surveyor's) | ch | ≡ 66 ft(US) ≡ 4 rods [3] | ≈ 20.11684 m | cubit (H) | | ≡ Distance from fingers to elbow ≈ 18 in | ≈ 0.5 m | ell (H) | ell | ≡ 45 in [4] (In England usually) | = 1.143 m | fathom | fm | ≡ 6 ft [4] | = 1.8288 m | fermi | fm | ≡ 1×10−15 m[4] | ≡ 1×10−15 m | finger | | ≡ 7/8 in | = 0.022225 m | finger (cloth) | | ≡ 4½ in | = 0.1143 m | foot (Benoît) (H) | ft (Ben) | | ≈ 0.304799735 m | foot (Cape) (H) | | Legally defined as 1.033 English feet in 1859 | ≈ 0.314858 m | foot (Clarke's) (H) | ft (Cla) | | ≈ 0.3047972654 m | foot (Indian) (H) | ft Ind | | ≈ 0.304799514 m | foot (International) | ft | ≡ 1/3 yd ≡ 0.3048 m ≡ 12 inches | ≡ 0.3048 m | foot (Sear's) (H) | ft (Sear) | | ≈ 0.30479947 m | foot (US Survey) | ft (US) | ≡ 1200⁄3937 m [5] | ≈ 0.304800610 m | french; charriere | F | ≡ 1⁄3 mm | = 0.3 ×10−3 m | furlong | fur | ≡ 10 chains = 660 ft = 220 yd [4]...
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...income is a flow. C) there is no differencemoney and income are both stocks. D) there is no differencemoney and income are both flows. Answer: B 5) It is true that A) income and wealth are both stocks. B) money and income are both stocks. C) income is a flow and wealth is a stock. D) money and wealth are both flows. Answer: C 6) An individual's annual salary is her A) money. B) income. C) wealth. D) liabilities. Answer: B 7) A person's house is part of her A) money. B) income. C) liabilities. D) wealth. Answer: D 8) Money is A) anything that is generally accepted in payment for goods and services or in the repayment of debt. B) a flow of earnings per unit of time. C) the total collection of pieces of property that are a store of value. D) always based on a precious metal like gold or silver. Answer: A 9) Which of the following are true statements? A) Wealth is a stock variable. B) Money is a flow variable. C) Income is a stock variable. D) Wealth is a flow variable. Answer: A 10) ________ is used to...
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...High Performance Teams Waseem AL Rousan J3 M2 Assessment1 30675904 Waseem Al Rousan High Performance Teams Content J3 M2 Assessment1 30675904 Waseem Al Rousan Contents Introduction: ................................................................................................................................................. 2 What is a group ............................................................................................................................................. 2 Team Development Stages: Group Formation Theory (Tuckman’s 4/5 Stage Model) ................................. 3 Group performance theories ........................................................................................................................ 3 The T7 Model of Team Effectiveness ........................................................................................................ 3 Rubin, Plovnick, and Fry Model—The GRPI Model of Team Effectiveness .............................................. 4 Katzenbach and Smith Model—Focusing on Team Basics........................................................................ 6 High performing team case study/Umniah’s IT Infrastructure team ........................................................... 6 Team Performance Measurement and Management .............................................................................. 8 Team Behaviors and Values ...........................................................................
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...generally accepted in payment for goods and services or in the repayment of debt. 1) _______ A) credit B) money C) wealth D) income 2) Money is 2) _______ A) a flow of earnings per unit of time. B) anything that is generally accepted in payment for goods and services or in the repayment of debt. C) always based on a precious metal like gold or silver. D) the total collection of pieces of property that are a store of value. 3) Currency includes 3) _______ A) paper money, coins, checks, and savings deposits. B) paper money and coins. C) paper money and checks. D) paper money, coins, and checks. 4) The total collection of pieces of property that serve to store value is a person's 4) _______ A) wealth. B) money. C) credit. D) income. 5) A person's house is part of her 5) _______ A) money. B) income. C) wealth. D) liabilities. 6) ________ is used to make purchases while ________ is the total collection of pieces of property that serve to store value. 6) _______ A) Money; wealth B) Income; money C) Money; income D) Wealth; income 7) ________ is a flow of earnings per unit of time. 7) _______ A) Money B) Income C) Wealth D) Currency 8) An individual's annual salary is her 8) _______ A) income. B) money. C) liabilities. D) wealth. 9) When we say that money is a stock variable, we mean that 9) _______ A) the quantity of money is measured at a given point in time. B) money never loses purchasing power. C) we must attach a time period to the measure. D) it is sold in the equity...
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...BIDWISER – Preliminary Round Contents Getting Started ....................................................................................................................................................................... 1 Stage 1: Procure Land & Machinery ............................................................................................................................ 1 Stage 2: Make your Production Plan ........................................................................................................................... 2 Judging Criteria ..................................................................................................................................................................... 2 Relevant Data ......................................................................................................................................................................... 3 Illustration ............................................................................................................................................................................... 4 Getting Started You’re an entrepreneur and are setting up your company’s first manufacturing plant. First of all, you need to bid for land and machinery (“mandatory inputs”). Once you get the land and machinery you wanted (or got stuck with), you’ll need to buy trucks to transport your output to the market (revenue will be realized only if your output reaches the market). Additionally...
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...Ironmongery Steel and Metal Works Plastering and Paving Plumbing and Water Supply Systems Glazing Painting Landscaping External Works Electrical Installation Air Conditioning Installation Fire Service Installation Low Voltage Cubicle Switchboards Installation Diesel Generating Sets Installation Uninterruptible Power Supply System Broadcast Reception Installation Compressed Air System Steam Boiler System Liquefied Petroleum Gas Installation Fuel Supply System Swimming Pool Water Treatment Installation MODBQ.1/1 MODBQ.2/1 MODBQ.3/1 MODBQ.4/1 MODBQ.5/1 MODBQ.6/1 MODBQ.7/1 MODBQ.8/1 MODBQ.9/1 MODBQ.10/1 MODBQ.11/1 MODBQ.12/1 MODBQ.13/1 MODBQ.14/1 MODBQ.15/1 MODBQ.16/1 MODBQ.17/1 MODBQ.18/1 MODBQ.19/1 MODBQ.20/1 MODBQ.21/1 MODBQ.22/1 MODBQ.23/1 MODBQ.24/1 MODBQ.25/1 MODBQ.26/1 MODBQ.27/1 MODBQ.28/1 MODBQ.29/1 MODBQ.30/1 MODBQ.31/1 MODBQ.32/1 6 22 3 8 4 18 7 12 10 7 3 23 8 22 30 19 5 10 7 19 27 55 30 9 5 4 10 6 10 9 7 14 Bill Nr. MODBQ.1 DEMOLITIONS AND ALTERATIONS DEMOLITIONS Demolishing or taking down to ground level Individual structures A * x * x * high to parapet ; * storeys ; reinforced concrete framed building ; as delineated on drawing nr. * ; shoring and scaffolding ( ACCD) * x * x * high to ridge ; * storeys ; steel framed building ; located at * ; materials remaining the property of Employer ; setting aside and storing materials on site ; shoring and...
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...Geometry III Unit Test I. Fill in the blanks. 1. A plane is determined by _______________ non collinear points. 2. Points lie on one line are__________________. 3. __________________ points determine a line. 4. _______________points that lie in one plane. 5. Three or more points are _____________ if they lie in one line. 6. Line segment has______________ endpoints. 7. A portion of the line with only one end and which extends endlessly in only one direction is called _____________ 8. __________ has no length no width and no thickness and is represented by a dot. 9. __________ can be represented by the edge of the table. 10. ____________ has infinite length and width but no thickness. 1. Find the surface area of a rectangular prism with base length 10 cm, width 7 cm and height is 9 cm. 2. Find the volume of the square pyramid, the base side is 8 cm and the height is 12 cm? 3. The angles of a triangle have the ratio 2:5:8. What is the measure of the largest angle? a. 60 b. 72 c. 84 d.96 4. The perimeter of a regular hexagon with side length of 4.5cm. a. 22.5 cm b. 27 cm c. 31.50cm d. 40.5 cm 5. A rectangle has a width of 9cm and a length of 19cm. What is the perimeter? a. 40 cm ...
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...NATIONAL UNIVERSITY OF SCIENCE AND TECHNOLOGY PAKISTAN NAVY ENGINEERING COLLEGE HEAT & MASS TRANSFER LAB MANUAL ENGINEERING SCIENCES DEPARTMENT HEAT & MASS TRANSFER LAB MANUAL ENGINEERING SCIENCES DEPARTMENT LAB INSTRUCTIONS 1. No late submissions 2. If you miss the submission time, you will be marked zero in that lab 3. If cheating or plagiarism is observed in the lab report, zero will be marked in that lab. 4. Detailed calculations should be shown. 5. Neat work will earn good marks. 6. Graphs should be made by hands. MS excel graphs will not be accepted. LAB MARKS DISTRIBUTION LAB REPORT/ ATTENDENCE | 50% | LAB PERFORMANCE | 10% | MID TERM ASSESMENT/QUIZES | 10% | FINAL LAB ASSESMENT | 30 % | TOTAL | 100% | TABLE OF CONTENTS S.NO | DATE | OBJECTIVE | PAGE NO | SIGNATURE | 1. | | To show that the intensity of radiation on a surface is inversely proportional to the square of the distance of the surface from the source of radiation | | | 2. | | To show the intensity of radiation various as fourth power of source. | | | 3. | | Determination of barrier temperature gradient between two different metals in end to end pressure contact. | | | 4. | | To perform energy balance on air flowing throw a duct heated by cylindrical rod | | | 5. | | To perform energy balance on air flowing throw a duct heated by cylindrical rod using DAQ | | | 6. | | Determination...
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...Part A: Basic Nuclear Concepts and Calculations 1. NU235=(2)e(-.693*4.5X10^9)/7.10*10^8=-4.455 NU238=(100)e(-.693*4.5X10^9)/4.5X10^9=-.693 Now to find the ratio: -4.445/-.693=6.43 2. 1kg235U= 1 kg x 1000g/1 kg x gmol/235g x(6.022 x 1023)atoms/gmol x 3.2 x 10-11J/atom= 8.2x 1013J/kg=8200 x 1010kJ/kg=82 TJ/kg235U 1kg CH4= 802 kJ/1 mol CH4x 1 mol CH4/16.0 g CH4= 50 kJ/g CH4x 1000 = 50,000kJ/kg CH4=50,000kJ/ 1,000,000,000kJ= 0.0005 TJ/ g CH4 82 TJ/ kg235U/0.00005 TJ/kg CH4= 1.64 x 106TJ/1 3.What is the ratio of the energy released by the fusion of 1.0 kg of hydrogen to that released by fission of 1.0 kg of Uranium-235? Energy released by U-235 = 3.2 x 10-11J/atom x 2.56 x 1024atoms = 8.2 x 1014J/kg U-235 or 82 TJ/ kg U-235 Energy released by 1000 g of hydrogen = 1000 g H – 993 g He= 7 g of matter converted into energy using Einstein’s energy equation E = mc2. Convert the grams to kilograms= 7 g/1000g = .007 kg = 7.0 x 10-3kg E = (7.0 x 10-3kg) x (9.0 x 1016m2/s2) = 6.3 x 1014kg *m2/s2 The ratio of energy of U-235/H = (8.2 x 1014J/kg)/ (6.3 x 1014kg*m2/s2) The unit kg*m2/s2= one joule so convert the ratio to this: 1 kg*m2/s2x (8.2 x 1014J) / (6.3 x 1014J) = 1.3016 J/1 Given the obvious advantage in energy production, briefly describe some of the difficulties in designing and operating a fusion power plant to explain why there are no commercial fusion power plants in operation today. Nuclear fusion has often been hailed as the silver bullet solution to the...
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...UNIVERSITI TUNKU ABDUL RAHMAN |Centre |: Centre for Foundation Studies (CFS) |Unit Code |: FHSC1014 | |Course |: Foundation in Science |Unit Title |: Mechanics | |Year/ Trimester |: Year 1 / Trimester 2 & 3 |Lecturer |: Kevin Chin | |Session |: 201605 | | | Additional Tutorial 4: Work and Energy. 1. A push of 120 N is applied along the handle of a lawn mower producing a horizontal displacement of 14.0 m. If the handle makes an angle of 30.0o with the ground, what work was done by the 120 N force? [1.45×103 J] 2. A box of mass 5.0 kg is accelerated by a force across a floor at a rate of 2.0 m/s2 for 7.0 s. Find the net work done on the box. [490 J] 3. What is the minimum work needed to push a 950-kg car 810 m up along a 9.0º incline? (a) Ignore friction. (b) Assume the effective coefficient of friction retarding the car is 0.25. [(a) 1.2×106 J, (b) 3.0×106 J] 4. The net force exerted on a particle acts in the +x direction. Its magnitude increases linearly from zero at x = 0 to 24.0 N at x = 3.0 m. It remains constant at 24.0 N from x = 3.0 m to x = 8.0 m and then decreases linearly to zero at...
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...1 33 2 2 = 10 35 4221 21 735 14 28 + 10 50 400 10 3030 20 20 = 24 85 8221 31 3765 34 48 B) I. Matrix inverse method: 2x1 + 3x2 + 4x3 = 29 X1 + x2 + 2x3 = 13 3x1 + 2x2 + x3 = 16 1) Matrix form ,A: A =211 312 413121 122 223331 232 133 XX1 X2 X3 b291316 Ax = b ; x = A-1b A-1 =1A - A djoint A 2) Determine ( Row 2 as sample) A = (1) (-1)2+13421 + (1) (-1)2+2 2431 + 2(1)2+32332 = (-1) [(3)(1) – (4)(2)] + (1) [(2)(1)-(4)(3)] + (-2) [(2)(2)-(3)(3)] = (-1)(3-8) + (1)(2-12) + (-2)(4-9) = 5 – 10 + 10 A=5 3) Minor A A11 = 1221 = 1(1) – (2)(2) = 1 – 4 = -3 A12 = 1231 = 1(1) – (2)(3) = 1 – 6 = -5 A13 = 1232 = 1(1) – (1)(3) = 2 – 3 = -1 A21 = 3421 = 3(1) – (4)(2) = 3 – 8 = -5 A22 = 2431 = 2(1) – (4)(3) = 2 – 12 = -10 A23 = 2332 = 2(2) –(3)(3) = 4 – 9 = -5 A31 = 3412 = 3(2) – (4)(1) = 6 – 4 = 2 A33 = 2311 = 2(1) – (3)(1) = 2 – 3 = -1 Minor A = -3-5-1-5-10-520-1 4) Cofactor A = +-3--5+-1--5+-10--5+2-0+-1 = -35-15-10520-1 5) Ad-joint A = [Cofactor A] T = -35-15-10520-1T = -3525-100-15-1 6) Inverse A, A-1 A-1 = 1A – Ad-Joint A = 15-3525-100-15-1 = -3/512/51-20-1/55-1/5 7) Find X1 , X2 , X3 I) X1X2 X3 = -3/512/51-20-1/51-1/5291316 = -3529+113+(25)(16)129+-213+(0)(16)-1529+113+(-15)(16) = 234 * ...
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...Assignment front sheet Qualification Unit number and title Pearson BTEC Level 4/5HNC/D Diploma Health and Social Care Unit 9: Empowering Users of Health and Social Care Services https://www.netessays.net/viewpaper/130575.html http://hndassignments.co.uk/courses/unit-9-empowering-users-health-social-care/ Student name Assessor name Fidelia Chukwuenweniwe Date issued Submission date Re-assessment date 17/02/2016 Task 1 and Task 2 Thursday 14th April 2016 Task 3 and Task 4 Thursday 28th April 2016 Assignment title Empowering Users of Health and Social Care Services Learning Outcome Learning Outcome Assessment Criteria In this assessment you will have the opportunity to present evidence that shows you are able to: Task no. LO1 Understand how the design and review of services promotes and maximises the rights of users of health and social care services 1.1 Explain how the current legislation and sector skills standards influence organisational policies and practices for promoting and maximizing the rights of users of health and social care services 1 1.2 Analyse factors that may affect the achievement of promoting and maximising the rights of users of health and social care services 1 1.3 Analyse how communication between care workers and individuals contribute to promoting and maximizing the rights of users of health and social care services 1 LO2 Understand how to promote the participation and independence of users of health...
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...DEPARTMENT OF CHEMICAL ENGINEERING INDIAN INSTITUTE OF TECHNOLOGY KANPUR Che492-Unit Operations Laboratory II Experiment no. 5 Calandria Evaporator Instructors: Dr. Siddhartha Panda Dr. Deepak Kunzru Name of TA: Abir Ghosh Date of experiment: 23/9/2013 Date of submission: 30/9/2013 Group No: 2 Roll no. 10059 10062 10067 Name Akshay Bansal Akshit Gupta Aman Jain 1 Index Introduction Objective Theory and formulae Apparatus required Details required Observations and Calculations Sample calculation Results and Discussion Conclusion Precautions Sources of error Nomenclature Reference 3 4 4 6 6 6 8 8 8 9 9 9 9 2 Introduction The functional requirement of an evaporator is to vaporize a chemical liquid in order to achieve certain industrial benchmarks such as concentrating a solution, purification or retaining a number of useful solvents or to carry out crystallization on an industrial scale by achieving the limiting concentration. The fundamental working principle of an evaporator is characterized by heating the solution up to the boiling point of the solvent (in case of solid solute) or to the dew point of the solution (in case of liquid solute). The various types of industrially applicable evaporators are described as under: 1.) Direct heating evaporators-In these units, direct heating of the solution is carried out using solar energy or the heat energy of the gases which are brought to very high temperature using natural gas combustion. These are mainly used to extract salt...
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... | |Assessor’s Name: | | |Assessor’s Signature: | |Date: | | |Date Issued: |3rd February 2014 |Submission Date: |17th March 2014 | |Feedback Date: |In class 17th March 2014 | Final Submission date |12th May 2014 | List of criteria for this Assignment |Unit 9...
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