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Two-Variable Inequalities

MAT222: Intermediate Algebra

November 03, 2014

This week assignment has to do with solving two variable equalities that have to do with practical situations. The main problem on this assignment is objects that would have to be shipped together that would need to fit in an eighteen wheeler trailer. “The accompanying graph shows all of the possibilities for the number of refrigerators and the number of TVs that will fit into an 18-wheeler. a) Write an inequality to describe this region. b) Will the truck hold 71 refrigerators and 118 TVs? c) Will the truck holds 51 refrigerators and 176 TVs?” Dugopolski, M (2012). I will now start out to solve problem 68 on page 539 in our textbook of Elementary and Intermediate Algebra. The graph is going to show a triangle region that would be shaded. This is where I would have to write the inequality to describe the region. When looking at the graph it will show the number of refrigerators. This will be shown on the graph as “x” axis and the number will be “p” for television for the “y” axis. The points on the graph are going to show on the graph as (0,330) and (110, 0) these numbers are given to determine on how the slope is going to be placed on the graph in which will be known as the slope form.
(Part A.) p = y1-y2 / X1-x2 = 330 – 0 / 0-110 = -3/1 the slope is -3/1 or -3 Y – y1 = p(x – x1)
Y – 330 = - 3 / 1(x-0)
Y = - 3x/1 + 330
-3x/1 +330 = y expression switch by place the y on the right hand side -3x/-3 = y/-3 – 330/ -3 divide each equation by -3 and cancel out like terms -3y = 1x + 110
-3y + 1x < 110
330 – 0 = -3 This will be known as the Point Slope Form.
110 – 01 This would be the slope -3/1. (0,330)

(110, 0)

Having these calculations will give me the point slope form for the linear equation. Down below I will start to show the steps of the linear inequality, y starting with the point slope.
This is where I will have to substitute the slope for “m” and (333, 0) for the “x” and “y”. y- 330=-3/1 (x, o) This is where I would use he distributive property and would have to add 330 to both sides of the equation.
+330 + 330 (1) y=-3/1x+3(1) Here is where I had to multiply both sides of the equation by (1). (+3) y=3x+330(+3) Here is where I had to add the 3x onto both sides order in having to cancel out the like terms. 3x+y<330 This is going to be the final inequality.
Seeing that the graph is going to have a good solid line, in which this will mean that the points will become the part of the solution. Now I will continue to the second and third part of the solution and equation “B” and “C”. Here is where I see that the test points will be given to prove if the inequities are going to be true or not.
(Part B). I need to figure out if the 18 wheeler is able to hold the 118 television sets and the 71 refrigerators. In order for me to solve this equation I have to figure out if the order pair is going to be substituted for it to go into the inequality that I calculated in “Part A” of the equation. I would need to see if the calculations are true and work out to where the television sets and refrigerators will show in graph area of the equation.
3x+y <330 This is going to be the Linear Inequality.
3(71) + 118< 330 This is where is where I had to substitute the ‘x” an “y” values.
213+118 <330
331< 330 This calculation proves that this is not going to work as for the televisions and refrigerators will be able to fit in the eighteen wheeler. This is going to be a false statement showing that the truck is not capable having this kind of capacity.
(Part C.) This will be my third step where I would need to calculate if the 18 wheeler with be able to carry both television sets and refrigerators. Here I am ng to calculate if the 18 wheeler will be able to hold 176 television sets and 51 refrigerators.
3x+y < 330 Here I will be using the same step as before where I will be substituting “’x” and “y” values into a linear inequality.
3 (51) +176 <330
153+176 < 330
329 < 330 In conclusion here I have calculated that the equation came to be true as for the 18 wheeler, being able to have the capacity to hold the given amount of refrigerators and television sets. In my next problem consist of trying to calculate the maximum or minimum range that would need to be found. “The Burbank Buy More store is going to make an order which will include, at most, 60 refrigerators. What is the maximum number of TVs that could also be delivered on the same 18-wheeler?” Dugopolski, M (2012). This is what steps I took to solve “y”
1(60) + -3y < 110 Beginning of the equation
-3y < -60 + 110 Here I added the 110 to -60 to get 50
-3y < 50 Here I had to divide both terms by -3
-3y/-3 > 50/-3 This is where the signs flip.
Y > -50/3 or y = 16 Here there will be no added restrictions this is because the max allowance has been met for the number of TV’s. Continuing the problem “The next day, the Burbank Buy More decides they will have a television sale so they change their order to include at least 200 TVs. What is the maximum number of refrigerators that could also be delivered in the same truck?” Dugopolski, M (2012).

1x + -3 (200) < 110 This is the equation I will work with.
X < 600 + 100 Here is where I simplified both sides of the equation for the inequality. x−600+600<110+600 Here I added 600 to both sides of the equation.
X = < 710 In conclusion this will be my final answer.
This will the way it will be mapped out in the line graph.
|--------|-----------|-------|--------|--------|-------O-------|---------|
-400 -200 0 200 400 600 800 1000 In conclusion calculating all of the equations given in this assignment there were some negative and positive results. Having the majority of the equation and graphing all calculations all seem to come together in the correct form. There was one surprising result in my calculation as in problem “B” it did result that it was not going to work out. But in the end the other solutions did work out in all furniture able to fit into the space of the 18 wheeler.

Reference
Dugopolski, M. (2012). Elementary and intermediate algebra (4th ed.). New York, NY: McGraw-Hill Publishing.

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