6l | 034 | |

6h | 667899 | |

7l | 00122244 | |

7h | | Stem=Tens |

8l | 001111122344 | Leaf=Ones |

8h | 5557899 | |

9l | 03 | |

9h | 58 | |

This display brings out the gap in the data: There are no scores in the high 70's.

13.

a.

| | | |

12 | 2 | Leaf = ones |

12 | 445 | Stem = tens | |

12 | 6667777 | | |

12 | 889999 | | |

13 | 00011111111 | | |

13 | 2222222222333333333333333 | | |

13 | 44444444444444444455555555555555555555 |

13 | 6666666666667777777777 | | |

13 | 888888888888999999 | | |

14 | 0000001111 | | |

14 | 2333333 | | |

14 | 444 | | |

14 | 77 | | |

The observations are highly concentrated at 134 – 135, where the display suggests the typical value falls.

b.

The histogram is symmetric and unimodal, with the point of symmetry at approximately 135.

15

Crunchy | | Creamy |

| 2 | 2 |

644 | 3 | 69 |

77220 | 4 | 145 |

6320 | 5 | 3666 |

222 | 6 | 258 |

55 | 7 | |

0 | 8 | |

Both sets of scores are reasonably spread out. There appear to be no outliers. The three highest scores are for the crunchy peanut butter, the three lowest for the creamy peanut butter.

17

a

Number

Nonconforming Frequency RelativeFrequency(Freq/60)

0 7 0.117

1 12 0.200

2 13 0.217

3 14 0.233

4 6 0.100

5 3 0.050

6 3 0.050

7 1 0.017

8 1 0.017

doesn't add exactly to 1 because relative frequencies have been rounded 1.001

b The number of batches with at most 5 nonconforming items is 7+12+13+14+6+3 = 55, which is a proportion of 55/60 = .917. The proportion of batches with (strictly) fewer than 5 nonconforming items is 52/60 = .867. Notice that these proportions could also have been computed by using the relative frequencies:...