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Write-Up for Lab 11.2: Popper Physics

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Write-Up for Lab 11.2: Popper Physics
SCI121 Week 4

Notes: To figure out the average height for the table below, add up the three heights and divide by 3. To figure out the average time add the 4 time measurements and divide by 4.

Table 1: Popper physics data

Trial Number Maximum Height (m)
1 1.1
2 1.3
3 1.32
Average: 1.24
Trial Number Time in Air (s)
1 0.90
2 1.18
3 0.97
4 1.03
Average: 1.02

Questions:

1. What is the gravitational potential energy your popper has at its maximum height you measured? Use g = 9.8 m/s2, and a mass of 0.01 kg.

Note: For question 1, use the equation for Potential Energy listed below; your potential energy is equal to 0.01 kg times 9.8 m/sec squared times the average height (in meters) The answer is in the units of joules.

PE = mgh = PE mgh (0 .01 kg x 9 .8 m /s2 x 1 .24 m)
PE 0 .12152 Joules

2. Use the following kinematics equation to calculate the initial velocity of the popper based on how long it is in the air:

H = h0 + v0t – ½ gt2

where the final height h = 0 and initial height ho = 0 after the popper travels the total time up and down over your measured time t.

Note: For question 2, use the equation initial velocity = ½ gt - this is how the equation rearranges when the two heights = zero. So, multiple ½ times 9.8 (the value for g) times your average time is seconds from Table 1. Your answer will be in m/sec)

3. Use this value for the initial velocity to find the kinetic energy of the popper right as it “pops” up.

Note: For question 3, you need to use the calculated velocity in question 2 to solve for the kinetic energy of the popper. Locate the equation for the kinetic energy in your textbook to do so.)

4. Compare your answers for potential energy and kinetic energy? Are they the same, or close to the same?

Note: the answers

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