It 255

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    Assignment

    192.168.254.37/25 Octet | 1 | 2 | 3 | 4 | Mask | 255 | 255 | 255 | 128 | Magic Number | | | | 128 | Classful Network/Subnet Zero | 192 | 168 | 254 | 0 | First Nonzero Subnet | 192 | 168 | 254 | 128 | Next Subnet | | | | | Next Subnet | | | | | Next Subnet | | | | | Next Subnet | | | | | Next Subnet | | | | | Next Subnet | | | | | Next Subnet | | | | | Broadcast Subnet | 192 | 168 | 254 | 255 | Invalid—Used by Process | 192 | 168 | 254 | 256

    Words: 553 - Pages: 3

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    Netw202 Wk4 Lab Worksheet

    | 2 | 1 | Binary | 255 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 1 |   | 255 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 1 |   | 240 | 1 | 1 | 1 | 1 | 0 | 0 | 0 | 0 |   | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |   | 3. /20 12 bits in host portion. (2n-2) 212-2=4094 4. /21 11111111.00000000.00000000.00000000 11111111.11111111.11111000.00000000 255.255.248.0 base2 | 2^7 | 2^6 | 2^5 | 2^4 | 2^3 | 2^2 | 2^1 | 2^0 |   | decimal | 128 | 64 | 32 | 16 | 8 | 4 | 2 | 1 | Binary | 255 | 1 | 1 | 1 | 1 | 1 |

    Words: 1815 - Pages: 8

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    Ip Addressing Subnetting

    11010011 10011000 IP Addressing and Subnetting Workbook Version 2.0 Instructor’s Edition 11111110 10010101 00011011 10000110 IP Address Classes Class A Class B Class C Class D Class E 1 – 127 128 – 191 192 – 223 224 – 239 240 – 255 (Network 127 is reserved for loopback and internal testing) 00000000.00000000.00000000.00000000 Leading bit pattern 0 Network . Host . Host . Host Leading bit pattern Leading bit pattern 10 110 10000000.00000000.00000000.00000000 Network . Network

    Words: 18750 - Pages: 75

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    Vlsm Workbook

    Version 2.0 Version 1.0 Variable-Length Subnet Mask Workbook 192.168.10.0 192.168.10.96 Student Name: 192.168.10.126 172.31.15.0 IP Address Classes Class A Class B Class C Class D Class E 1 – 127 128 – 191 192 – 223 224 – 239 240 – 255 (Network 127 is reserved for loopback and internal testing) 00000000.00000000.00000000.00000000 Leading bit pattern 0 Network . Host . Host . Host Leading bit pattern Leading bit pattern 10 110 10000000.00000000.00000000.00000000 Network . Network

    Words: 19905 - Pages: 80

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    How to Calculate Subnets

    2 bits = 128 + 64 = 192 Range of hosts = 26 = 64 TT Range Useable Range Network ID 0 – 63 64 – 127 65 - 126 128 – 191 129 - 190 Broadcast 192 – 255 Address Borrow 3 bits S S S H H H H H # of subnets = 23 = 8 Subnet mask = 3 bits = 128 + 64 + 32 = 224 Range of hosts = 25 = 32 Range 0 – 31 32 – 63 64 – 95 96 – 127 128 – 159 160 – 191 192 – 223 224 – 255 Useable Range 33 - 62 65 - 94 97 -126 129 -158 161 -190 193 -222 Network ID Broadcast Address ©1999 Dan Foss How to Calculate Subnets

    Words: 942 - Pages: 4

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    Case Question

    = (4*60 + 15)*3 = 255*3 = 765 min The number of follow-up patients = 80*60% = 48 people The number of new patients = 80*40% = 32 people The total time for follow-up patients = 48*4 + 48*0.85*2 = 273.6 min The total verification time for new patients = 32*(9+2) = 352 min The total verification time = 273.6 + 352 = 625.6 min The utilization of Verification = 625.6/765 = 81.78% iii. Direct patients / filing / exam room preparation Total available time = 4*60 + 15 = 255 min The total time

    Words: 406 - Pages: 2

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    Pediatric Clinic

    Patients | Time needed | Utilization10 | | | /Staff | Total | N | F | N | F | N | F | Total | | 1. Front Desk | | | | | | | | | | | | a. Registration | 3 | 180 | 540 | 5 | 5 | 32 | 48 | 160 | 240 | 400 | 74 % | b. Verification | 3 | 255 | 765 | 9 | 4 | 32 | 48 | 288 | 192 | 480 | 63 % | 2. Radiology Department | | | | | | | | | | | | a. X-ray imaging | 6 | 240 | 9603 | 11 | 11 | 32 | 40.8 | 352 | 448.8 | 800.8 | 83 % | b. Development of X-rat | -1 | 240 | 9604 |

    Words: 282 - Pages: 2

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    Subnetting Assistiance

    0bits = 24 total bits out of 32 possible bits Each 1 in the subnet equals a bit and each octet is a field of potentially 8 bits Each placement of a bit indicates a numeric value. Picture the following table as one octet. Let’s see how we can make 255 as a value: Bit value | Bit value | Bit value | Bit value | Bit value | Bit value | Bit value | Bit value | 128 How? (64x2) | 64 How? (32x2) | 32 How? (16x2) | 16 How? (8x2) | 8 How? (4x2) | 4 How? (2x2) | 2 How? (1x2) | 1 | 1 | 1 | 1 | 1 |

    Words: 1080 - Pages: 5

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    Aspen Assignment

    IBM® Sterling B2B Integrator Map Editor INPUT Branching Diagram C:\Users\tmpdbohrer\Documents\IBM\Customers\Varroc Lighting\vTrac_AUD_APP_CMMS_CIF_856_OB.map.map Input Standards Association Agency : Version : Transaction Set : Release : Functional Group : INPUT* Group* 856HD* 856A* Temp* M C C C C 1 0 0 0 0 1 9999 1 1 1 Output Standards Association Agency : Version : Transaction Set : Release : Functional Group : Routing Header Primary Control Record Wed Oct 31 22:41:04 2012 Page 1 IBM®

    Words: 1494 - Pages: 6

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    Codes in Java Netbeans

    Database connection /* * To change this license header, choose License Headers in Project Properties. * To change this template file, choose Tools | Templates * and open the template in the editor. */ package scholapaymentsystem; import com.mysql.jdbc.Connection; import java.sql.DriverManager; import java.sql.SQLException; /** * * @author ferdie_amy */ public class DBConnection { private Connection DBConnection; public Connection connect(){ try{

    Words: 36130 - Pages: 145

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