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Sydney Bristow is a delightful woman who surrounds herself with peaceful people. Her community as a fiancée, grad student, friend, and bank worker involves her fiancé Daniel, her roommate Francie, her friend Will, and her fellow classmates and Professor. Being a part of this community shows loyalty and honesty. She has an excellent relationship with them all because they communicate often, they reveal secrets to one another, and they give advice when it is necessary. All of them live the life of an average person; they work and or go to school and volunteer in their community. For the most part they are happy people. Their world is rather sweet; they do not face many issues while being a part of this “Sunny Subculture”. Sydney’s life is wonderful from this perspective, she really do not have to worry about besides school. She has a loving fiancé who is ready to marry her and start a family with her very soon. This is the life many people would love to live without the CIA involvement issues. The environment is colorful from Sydney’s red wig, to the bright sunlight shining on her and Will while they run on the track. It is full of color everywhere they go. This is a bright environment with delightful people.

Sydney is loyal to everyone around her and her job also. She is too loyal and honest in a way because her honesty leads to the death of Danny. Sydney was determined to keep Danny and her co-workers happy at the same time. She reveals her secret to Danny because she loved him and she trusted him more than anyone else. Danny did not purposely expose Sydney he was only trying to express to her the way he felt about her to her through a voicemail. Also, her loyalty to Danny is proven when Will offers to take her to the movies and she denies him because she previously arranged to take Danny dinner at the hospital. Will suggests a later show and she still declines. She loved Danny and felt terrible after he was murdered. She was given a month off from the agency, but she ended up being off much longer than that. Once he was murdered and she found out the truth about the agency she no longer wanted to be a part of it. She began to work against the agency and more for the “real” CIA. Sydney was loyal to the agency and she would have continued to be that way if she was not made aware of their actual role, they were the enemy all alone. I can relate to Sydney’s loyalty in my own life in many different ways.

Sydney’s loyalty, honesty, and trust closely relates to my own identity because I am loyal to my family, friends, and loved ones. There are secrets passed between us all the time and no one has to ever worry about being exposed. I will do whatever it takes to make sure a loved one is taken care of. I am the type of person who worries more about others happiness then my own. For example, if I had something that one of my loved ones needed more than I did I would give it to them. I have never been selfish and I never will be; I really believe “sharing is caring”. I do for others as much as possible because there may be a time in my life when I need to count on one of my loved ones for help or support. There are not many people I trust in my life, but the few who have showed me trustworthy characteristics are the ones I cherish the most. It is always good to have a trustworthy, honest, and loyal individual by your side when things get tough. Taking those three characteristics seriously will guarantee successful friendships and relationships in life. Many people take these things for granted and that is how bonds are broken after hard work is put into building them. Growing up I have learned not to take anyone or anything for granted because there will more than likely be a point in time when I need that person more than I ever thought I would need them. I value honesty more than any other characteristic because it does not take much for a person to lie, but it takes courage and wisdom for a person to be real enough to tell you their honest opinion. Honesty and loyalty go hand in hand; you really cannot have without the other.

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...Relationships in Alias Grace The truth may not always be as black and white as it seems. In Margaret Atwood’s Alias Grace, the main character is immediately judged and harboured as a criminal. The book is about a woman, who, at the age of sixteen is tried in the court as an accomplice to a double murder. It is a true story that happened in Canada in the 1850`s. A lot of mystery surrounds the role she actually played in the murders because some of the facts do not add up. There are competing versions of the story, and Grace herself has no memory of the event. She confesses, but the story quickly reveals that her lawyer coerced her into giving the version of the story that he liked best. Meanwhile, Grace is prone to mental fits that no one understands, so countless doctors and clergymen examine her and come to differing conclusions; some are convinced that she is guilty, and others are convinced that she is innocent. One of the only things keeping Grace strong is her ability to connect with certain characters that are introduced into her life. The use of her qualities and strengths as a woman allows Grace the ability to hold onto certain relationships longer than others. Grace not only has the ability to draw people into her life, like Doctor Simon Jordan and Mary Whitney, but she is able to entice the reader in ways that others cannot and bring them in as her fascinated audience. To begin with, one of the main characters in Atwood’s novel, Alias Grace, is Doctor......

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...Metamorphoses in Dune Alexandru Maniu In Dune, people can be both men and animals. For purely artistic reasons, the coexistence of different life forms under the same mask is a constant in Ovid’s Metamorphoses. In Orphism, nothing is immutable and everything is subject to change. For Ovid, this postulate must have had some limits generated by the artistic process: “nor can the arts that cure others cure their lord”. Transformed characters – so punished for ill behavior or challenging the gods – eventually acquire immortality, just like the poet himself. Deities can be either anthropomorphic or theriomorphic, yet they can change according to their own will and they don’t lose their divinity in the process. Ovid’s metamorphoses are usually final and the poor misfortunate loses some of his humanity forever. By far the cruelest fate is for one to lose his power of speech or his free-speech, as in the case of Acteon, changed into a stag, Callisto, changed into a bear or Lycon, who becomes a wolf. On a more subtle level, the nymph Echo is left only with the power of speech, but her words are not her own, as she is forced to repeat whatever she hears. All these stories cover a more complex level of understanding that deals with religion and ritual, and should not be taken as mere parables of morality. The myth of Artemis and Acteon encapsulates the confrontation between crude human conscience and the mystery of life, epitomized by the maternal deity (Isis, Artemis, Diana),......

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...replace=TRUE) > table(rolls2) rolls2 1 2 3 4 5 6 8166 8027 8068 7868 7912 7959 (b) Next we form this into a 2-column matrix (thus with 24,000 rows): > two.rolls=matrix(rolls2,nrow=24000,ncol=2) (c) Here we compute the sum of each (2-roll) row: > sum.rolls=apply(two.rolls,1,sum) > table(sum.rolls) sum.rolls 2 3 4 5 6 7 8 9 10 11 742 1339 2006 2570 3409 4013 3423 2651 1913 1291 1 12 643 Note table() gives us the frequency table for the 24,000 row sums. (d) Next we form the vector of sums into a 24-row matrix (thus with 1,000 columns): > twodozen=matrix(sum.rolls,nrow=24,ncol=1000,byrow=TRUE) (e) To ﬁnd the 1,000 column minima use > min.pair=apply(twodozen,2,min) (f) Finally compute the number of columns whose minimum is 2, that is the number of series of 24 rolls of two dice with at least one sum of 2: > sum(min.pair==2) [1] 518 6. > p1.est=sum(min.roll==1)/4000 > p2.est=sum(min.pair==2)/48000 7. Here we repeat the above procedure 25 times, keeping track of the sums in both cases each time: > > > + + + + + + + + + + + + + + results1=0 results2=0 for (i in 25){...

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...April 8, 2016 1 Contents 1 Algebra 1.1 Rules of Basic Operations . . . . . . . . . . . . . . . . . . . . . 1.2 Rules of Roots . . . . . . . . . . . . . . . . . . . . . . . . . . . 1.3 Rules of Exponents . . . . . . . . . . . . . . . . . . . . . . . . . 1.4 Allowed and Disallowed Calculator Functions During the Exam 1.5 Sequences and Series . . . . . . . . . . . . . . . . . . . . . . . . 1.6 Arithmetic Sequences and Series . . . . . . . . . . . . . . . . . 1.7 Sum of Finite Arithmetic Series (u1 + · · · + un ) . . . . . . . . . 1.8 Partial Sum of Finite Arithmetic Series (uj + · · · + un ) . . . . . 1.9 Geometric Sequences and Series . . . . . . . . . . . . . . . . . . 1.10 Sum of Finite Geometric Series . . . . . . . . . . . . . . . . . . 1.11 Sum of Inﬁnite Geometric Series . . . . . . . . . . . . . . . . . 1.11.1 Example Involving Sum of Inﬁnite Geometric Series . . 1.12 Sigma Notation . . . . . . . . . . . . . . . . . . . . . . . . . . . 1.12.1 Sigma Notation for Arithmetic Series . . . . . . . . . . . 1.12.2 Sigma Notation for Geometric Series . . . . . . . . . . . 1.12.3 Sigma Notation for Inﬁnite Geometric Series . . ....

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...#include <stdio.h> //Declare Prototype float getavg(int ageSum, int n); int main() { //Define variable family as number of loops and i as counter int family, i; printf("Enter the number of family members being submitted:"); scanf("%d", &family); //Declare rest of variables to hold the family names,states, ages, the sum of their ages, and the average of their ages char familynames[family][30], familystate[family][30]; int familymemberages[family], sum = 0; float averageAge; //Start loop and counter for (i=0; i < family; i++) { printf("\nPlease enter the following details for family member: \n" ); //Ask user to input first name printf("First name: "); scanf("%s", familynames[i]); //Store name in familynames //Ask user to input age printf("Age (in years): "); scanf("%d", &familymemberages[i]); //Store age in familymemberages //Ask user to input state they reside in printf("State of residence (by Abbreviation; Pa,Ny, Tx, etc...): "); scanf("%s", familystate[i]); //Store state in familystate //Sum of ages adding of all familymemberages sum += familymemberages[i]; } //Define the average age averageAge = getavg(sum, family); //Display the average age printf("\n\nThe average age among your family members is %.2f years\n", averageAge); //Display the list of members in Tx printf("List of members who live in Texas are: \n"); //Compare each charactors in string for Tx ...

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...A Taylor series for the function arctan The integral If we invert y = arctan(x) to obtain x = tan y, then, by diﬀerentiating with respect to y, we ﬁnd dx/dy = sec2 y = 1 + tan2 y = 1 + x2 . Thus we have (ignoring the constant of integration) y = arctan(x) = dx . 1 + x2 (1) If we now diﬀerentiate y = arctan(x/a) with respect to x, where a is a constant, we have, by the chain rule, y = 1 a 1 a = 2 . 1 + (x/a)2 x + a2 (2) Thus we obtain the indeﬁnite integral 1 dx = arctan(x/a). x 2 + a2 a (3) The Taylor Series By expanding the integrand in (3) as a geometric series 1/(1 − r) = 1 + r + r 2 + . . ., |r| < 1, and then integrating, we can obtain a series to represent the function arctan(x/a). We use the dummy variable t for the integration on [0, x] and we ﬁrst write x x arctan(x/a) = a 0 dt 1 = t2 + a 2 a 0 dt 1 + (t/a)2 (4) Substituting the geometric series with r = −(t/a)2 , we ﬁnd 1 arctan(x/a) = a x ∞ (−t2 /a2 )n dt = 0 n=0 (−1)n x 2n + 1 a n=0 ∞ 2n+1 . (5) The radius of convergence of this series is the same as that of the original geometric series, namely R = 1, or, in terms of x, |x/a| < 1. The series is a convergent alternating series at the right-hand end point x = a; and it can be shown that sum equals the value of arctan(1) = π/4 (as we might hope). Thus we have the nice (but slowly converging) series for π given by π 1 1 1 = 1 − + − + .... (6) 4 3 5 7 By choosing partial sums of (5) we obtain a sequence of Taylor......

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...CMSC 131 Summer 2005 Quiz 2 Worksheet The second Quiz of the course will be on Friday, Jun 17. The following list provides more information about the quiz: • You will have 25 minutes to complete the quiz. • It will be a written quiz (not using any computer). • It will be closed-book, closed-notes, and no calculator is allowed. • Answers must be neat and legible. We recommend that you use pencil and eraser. • The quiz will be based on the exercises you will find below. The quiz will ask you to write pseudocode for a particular problem. • We have provided previous semesters’ quizzes at the end. Take a look at them so you get an idea of the pseudocode we expect. The following exercises cover the material to be covered in Quiz #2. Solutions to these exercises will not be provided, but you are welcome to discuss your solutions with the TA and the instructor during office hours. Keep in mind that in the following exercises you are being asked to provide only pseudocode. 1. Write pseudocode for a program that computes the average of a set of values after the highest and lowest scores have been removed. 2. Write pseudocode for a program that reads a sequence of integer values and determines whether it is a decreasing sequence. A decreasing sequence is one where each value is greater than or equal to the next element in the sequence. The program will first read the number of values to process followed by the......

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...Matlab Assignment 7 Make the Matalb assignment discussed in the last class (least square regression estimates). Make sure that you program a function with proper comments and at least one test for sound input. Test your function with some input vectors, for example: y=[1,2,4,23,4,6,3,2] and x=[5,4,3,2,6,5,4,3] You can take any other input vectors. m.file command: function [alpha_estimate, beta_estimate] = my_regression(y,x) n = length(x) a = sum(x); b = sum(y); c = sum(x)/n; d = sum(y)/n; e = sum(x.*y); f = sum(x.*x); alpha_estimate = d-(e-n*c*d)/(f-n*c^2)*c; beta_estimate = (e-n*c*d)/(f-n*c^2); disp('alpha =') disp(alpha_estimate) disp('beta =') disp(beta_estimate) % Purpose of the function: This function is used to calculate the % coefficients of the regression formula. % Input: value of y and x % Output: alpha_estimate and beta_estimate % How to run the function: % I use n to represent the length of vector x and y % a to represent the sum of vector x % b to represent the sum of vector y % c to represent the avergae of vector x % d to represent the average of vector y % e to represent the sum of vector x and y % f to represent the sum of square of vector x %then calculating: alpha_estimate = d-(e-n*c*d)/(f-n*c^2)*c; % beta_estimate = (e-n*c*d)/(f-n*c^2); % Author: Hengya Jin % Date of last change: 11/27/2013 end Check: >>......

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...MTH 1002: Calculus 2 Spring 2014 Instructor: Dr. C. Knoll Office: Bldg 406 (Academic Quad) Email: cknoll@fit.edu Dr. A. Gibbins Bldg 406 (Academic Quad) agibbins@fit.edu Dr. D. Zaffran Bldg 405 (Academic Quad) dzaffran@fit.edu Grading Policy: Online Homework ( 50 Practice Tests ( 50 Quizzes ( 200 Tests ( 300 Final Exam ( 200 TOTAL ( 800 Grading Scale: A: 90 – 100; B: 80 – 89; C: 70 – 79; D: 60 – 69; F: below 60 Late work will not be accepted without an excused absence. Only students with excused absences will be allowed to take make-up exams, quizzes, labs, etc. There will be absolutely no exceptions (consult your student handbook). An excused absence requires official documentation, e.g. a doctor’s note (in the case of illness). ATTENDANCE IS REQUIRED and will be taken at all lectures and labs. Required Text: Single Variable Calculus: Early Transcendentals, 7th ed., by Stewart. Online Homework URL: Available through the Angel link on the FloridaTech homepage or at www.webassign.net using the Course ID: fit 9672 0423 The LectureTopics will correspond to the following sections from the textbook: 5.1: Area Between Two Curves 5.2: Volumes by Slicing & Disks and Washers 5.3: Volumes by Cylindrical Shells 7.1: Integration by Parts 7.2: Trigonometric Integrals 7.3: Trigonometric Substitution 7.4: Partial Fraction Decomposition 7.5: Strategy for Integration 7.6: Integration...

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