...all samples of rhyolite and andesite? A) pyroxene C) biotite B) quartz D) potassium feldspar 3. Base your answer to the following question on the map and cross section below. The shaded areas on the map represent regions of the United States that have evaporite rock layers (layers of rock formed from the evaporation of seawater) under the surface bedrock. The cross section shows the generalized structure of the area in which the evaporite layers are found in New York State. These evaporite deposits could be composed of which minerals? A) garnet and pyroxene C) hornblende and olivine B) mica and feldspar D) halite and gypsum 4. What is the approximate density of a mineral with a mass of 262.2 grams that displaces 46 cubic centimeters of water? A) 1.8 g/cm3 C) 6.1 g/cm3 B) 5.7 g/cm3 D) 12.2 g/cm3 Page 1 3rd Qt. Redemption Test 5. Base your answer to the following question on the diagram below, which shows the results of three different physical tests, A, B, and C, that were performed on a mineral. The luster of this mineral could be determined by A) using an electronic balance B) using a graduated cylinder C) observing how light reflects from the surface of the mineral D) observing what happens when acid is placed on the mineral 6. The diagram below shows four mineral samples, each having approximately the same mass. If all four samples are placed together in a closed, dry container and shaken vigorously for 10 minutes, which...
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...How do the atmospheric conditions that produce sleet differ from those that produce hail? Sleet forms when there is a layer of above freezing temperatures below cloud base but the temperatures at the surface are below freezing. A snowflake falling out of the cloud will melt in the above freezing layer producing a rain drop. The below freezing surface layer must be thick and cold enough to refreeze the raindrop before reaching the ground. Hail is produced inside a cumulonimbus cloud by accretion of super-cooled liquid water onto a large frozen embryo caught in a strong updraft. Continuous cycles through areas of super-cooled liquid water will cause the hailstone to increase in size until it can overcome the upward vertical velocity and eventually fall to the earth’s surface. What is the difference between freezing rain and sleet? Freezing rain is liquid (super-cooled) that will freeze on contact with objects that are below freezing on the surface. The determining factor between sleet and freezing rain as a precipitation type, is the depth and coldness of the subfreezing layer near the surface. Sleet is usually a transparent or translucent ice ball around .2 inches or less in diameter. When it hits the ground it can bounce. The formation of sleet was discussed in the previous question. Describe how hail might form in a cumulonimbus cloud? Hail is formed when clouds, specifically cumulonimbus clouds, have both high altitudes and powerful updrafts within the condensation...
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...AP10005 Physics I Tutorial: Week 4 1. Three blocks are in contact with one another on a frictionless, horizontal surface as shown in the figure below. A horizontal force is applied to m1. Take m1 = 2.00 kg, m2 = 3.00 kg, m3 = 4.80 kg, and F = 16.5 N. a. Draw a separate free-body diagram for each block. b. Find the acceleration of the blocks. c. Find the resultant force on each block. d. Find the magnitudes of the contact forces between the blocks. 2. A crate of weight Fg is pushed by a force on a horizontal floor as shown in the figure below. The coefficient of static friction is μs, and is directed at angle θ below the horizontal. e. Show that the minimum value of P that will move the crate is given by P=μsFgsecθ1-μstanθ f. Find the condition on θ in terms of μs for which motion of the crate is impossible for any value of P. (Use the following variable as necessary: μs.) 3. What horizontal force must be applied to a large block of mass M shown in the figure below so that the tan blocks remain stationary relative to M? Assume all surfaces and the pulley are frictionless. Notice that the force exerted by the string accelerates m2. (Use the following as necessary: m1, m2, M, and g.) 4. A crate of eggs is located in the middle of the flat bed of a pickup truck as the truck negotiates a curve in the flat road. The curve may be regarded as an arc of a circle of radius 30.5 m. If the coefficient of static friction...
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...Gross Anatomy allen SUPERFICIAL FASCIA Under the skin, similarly found in the other parts of the body. In obese individuals, heavily laid with fats Thin above the umbilicus, continuous with the superficial fascia of the thorax Below the umbilicus, there are 2 distinct parts o Camper’s Fascia –fatty superficial layer of the superficial fascia, wherein superficial blood vessels and nerves are found o Scarpa’s Fascia –deeper membranous layer of the superficial fascia. Provided with greater amount of elastic tissue. After crossing the inguinal ligament anteriorly, will blend with the FASCIA LATA of the thigh. In the pubis, it is continued over the spermatic cord, penis and the scrotum, and blends with the COLLE’S FASCIA of the perineum ABDOMEN ABDOMINAL WALL SURFACE ANATOMY LINEA ALBA Median band of a tendinous raphe between the two rectus abdominis muscles, formed by the fusion of the aponeurosis of the external oblique, internal oblique, and transverse abdominal muscles. Represented by a depression that extends from the xiphoid process to the pubic symphysis in pregnancy, it becomes a dark brown or black pigmented vertical line (linea nigra), probably due to hormone stimulation to produce more melanin. Infraumbilical part is very narrow Supraumbilical part gradually widens towards the sternal end NAVEL/ UMBILICUS Not a good landmark, variations due to obesity and beer drinkers Depression along the linea alba and indicates the site of the...
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...located below sea surface, wherein the condenser comprises: a condenser main body, respectively connected to the turbine and the working fluid pump; and a deep sea water pipe, connected to the condenser main body and having a first inlet end and a first outlet end, wherein the deep sea water pipe is connected to the condenser main body via the first outlet end; a working fluid, flowing between the working fluid pump, the evaporator, the turbine, and the condenser under the driven of the working fluid pump; an outflow working fluid pipe, connected between the evaporator and the condenser; and an inflow working fluid pipe, connected between the turbine and the condenser, wherein a section of the inflow working fluid pipe locates in the outflow working fluid pipe. 2. (Original) The OTEC system according to claim 1, wherein the working fluid pump, the evaporator, and the turbine are located on a sea surface or on land. 3. (Original) The OTEC system according to claim 1, wherein the condenser main body is located between 50 meters and 100 meters below sea surface. 4. (Original) The OTEC system according to claim 3, wherein the condenser main body is located on a continental shelf or in a vertical shaft. 5. (Cancelled) 6. (Original) The OTEC system according to claim 1, further comprising a surface sea water pipe connected to the evaporator and having a second inlet end and a second outlet end, wherein the surface sea water...
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...atmospheric CO2 4. To identify the impacts of different inputs to the carbon cycle on atmospheric CO2 concentrations Directions Go to http://www.learner.org/courses/envsci/interactives/carbon/ and complete the lessons below. If you are unsure of how to use the simulator or have questions about it at any time, click “Help” on the main page for the lab. Lesson 1. The Carbon Cycle 1. Read the Overview section, then click on The Carbon Cycle. a. Read through the information provided, then click Open Simulator. b. To familiarize yourself with this simulator and its components, click Help on the main page for the lab. Read through the information provided. c. Run the simulation to 2100 with the default settings, and, using the step 1 data table below, record the total carbon levels in each "sink" (terrestrial plants, soil, oil and gas, coal, surface ocean, and deep ocean) at 2050 and 2100. d. Answer the questions for Step 1 below. 2. Click on Step 2 under The Carbon Cycle. a. Read through the information provided. b. Run the simulation again, one decade at a time. Record the total amount of carbon in the atmosphere (the number in the sky) and other carbon sinks (terrestrial plants, soil, surface ocean, and deep ocean), as carbon moves through...
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...A Summary of the Hydrologic Cycle The hydrologic cycle begins with the evaporation of water from the surface of the ocean. As moist air is lifted, it cools and water vapor condenses to form clouds. Moisture is transported around the globe until it returns to the surface as precipitation. Once the water reaches the ground, one of two processes may occur; 1) some of the water may evaporate back into the atmosphere or 2) the water may penetrate the surface and become groundwater. Groundwater either seeps its way to into the oceans, rivers, and streams, or is released back into the atmosphere through transpiration. The balance of water that remains on the earth's surface is runoff, which empties into lakes, rivers and streams and is carried back to the oceans, where the cycle begins again. Lake effect snowfall is good example of the hydrologic cycle at work. Below is a vertical cross-section summarizing the processes of the hydrologic cycle that contribute to the production of lake effect snow. The cycle begins as cold winds (horizontal blue arrows) blow across a large lake, a phenomena that occurs frequently in the late fall and winter months around the Great Lakes. Evaporation of warm surface water increases the amount of moisture in the colder, drier air flowing immediately above the lake surface. With continued evaporation, water vapor in the cold air condenses to form ice-crystal clouds, which are transported toward shore. | By the time these clouds reach the shoreline,...
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...increases with pressure n. Hot water contains more minerals than cold water o. Geyser water is full of high-pressure gases p. Geyser water is unusually pure 5. Geysers can be destroyed by: q. Minerals plugging the conduit of the geyser r. Unusually violent eruptions s. Both a and b. t. Neither a nor b 6. Artesian wells: u. Are always pure v. Cannot be polluted because they are sealed w. Always flow to the surface x. None of the above 7. Center-pivot irrigation: y. Has made it possible to farm soils that cannot be conventionally irrigate z. Is causing the depletion of many aquifers {. Is very distinctive seen from the air |. All the above 8. Infiltration capacity is the: }. rate at which a stream erodes ~. distance a stream flows from its source to the ocean . maximum rate at which surface materials can absorb water . vertical distance a stream can erode below sea level . variation in flow velocity across a stream channel 9. Which of the following is an example of deposition by groundwater? . karst...
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...* Forming Dew Radiational cooling of the surface- Outgoing longwave radiation emitted to space Surfaces (grass,trees,cars) cool to the “dew” “point” Air is cooled by “conduction” and reaches its dew point condensation of liquid droplets on surfaces Dew Formation More likely to form on nights with clear skies and calm winds Objects near the ground will emit infradred radiation (clear nights) coldest air is located near the ground (calm winds) Frost Formation Radiational cooling of the Surface surfaces (grass,trees,cars) cool below frost point (below freezing). Air temp reaches frost point (air becomes saturated) (temp and dew point are equal) deposition of ice onto surfaces also known as hoarfrost or white frost exhibits “tree-like branching pattern.” FROST IS NOT FROZEN DEW! Frost forms on objects that are below freezing (vapor) Frozen dew is dew (liquid) that freezes as temperatures drop Haze…What Is It? Dust or salt particles suspended in the air Morning – Distant objects on the horizon are harder to see RH is much higher, therefore, water vapor condenses more readily and fills the air Afternoon – Distant objects on the horizon are easier to see RH is much lower, therefore, water vapor doesn’t condense as it would in the morning Hygoscopic – “Water-Seeking.” Ocean salt Hydrophobic – “water-repelling.” Oils, wax, and gas Wet haze – tiny liquid drops scatter light and appears dull grey or white Dry haze – non-water particles appear orange or yellowish ...
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... describe the functions of the structure and the flight controls. Apply aerodynamic principles to explain how flight controls control pitch, roll, and yaw’. It will also outline the basic control surfaces of an aircraft and the primary and secondary effects of each of them. In addition, it will also explore Bernoulli’s Principle and the forces acting on an aircraft in flight. Table of Contents Introduction5 Main Components of An Airplane 6 * Fuselage * Wings * Empennage The Wing and the Aerofoil7 Aerodynamics of Flight (Bernoulli’s Principle) 8 The Forces in Flight 9 * Lift * Thrust * Drag * Weight The 3 Axes of Rotations 10 * Longitudinal Axis * Lateral Axis * Vertical Axis Main Control Surfaces11 * Ailerons * Elevators * Rudders Secondary Effects of Control Surfaces12 Conclusion14 List of Figures Figure 1: The Magic of Flight 3 Figure 2: Main Components of an Airplane 4 Figure 3: The Wing And Aerofoil 5 Figure 4: Aerofoil Nomenclature 6 Figure 5: Bernoulli’s Principle 7 Figure 6: Forces on An Airplane in Flight 8 Figure 7: The 3 Axes of Rotation 9 Figure 8: 6 Degrees of Freedom 10 Figure 9: Control Surface: Ailerons 11 Figure 10: Control Surface: Elevators 11 Figure 11: Control Surface: Rudders 11 Introduction Figure 1: The Magic of Flight Man has come a long way since the advent of the first heavier-than-air flight by the Wright brothers back in 1903. In the span of merely...
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...navigation, and building. Geometry, as we know it is actually known as Euclidean geometry which was written well over 2000 years ago in Ancient Greece by Euclid, Pythagoras, Thales, Plato and Aristotle just to mention a few. The most fascinating and accurate geometry text was written by Euclid, and was called Elements. Euclid's text has been used for over 2000 years! Geometry is the study of angles and triangles, perimeter, area and volume. It differs from algebra in that one develops a logical structure where mathematical relationships are proved and applied. In part 1, you will learn about the basic terms associated with Geometry. Terms (Undefined) 1. Point Points show position. A point is shown by one capital letter. In the example below, A, B, and C are all points. Notice that points are on the line. 2. Line A line is infinite and straight. If you look at the picture above, is a line, is also a line and is a line. A line is identified when you name two points on the line and draw a line over the letters. A line is a set of continuous points that extend indefintely in either of its direction. Lines are also named with lowercase letters or a single loswer case letter. For instance, I could name one of the lines above simply by indicating an e. Terms (Defined) 1. Line Segment A line segment is a straight line segment which is part of the straight line between two points. To identify a line segment, one can write AB or . The points on each side of the line segment...
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...CHAPTER 8—THE SUN-OUR STAR Multiple Choice Identify the letter of the choice that best completes the statement or answers the question. ____ 1. Granulation is caused by |a. |sunspots. | |b. |rising gas below the photosphere. | |c. |shock waves in the corona. | |d. |the solar wind flowing away from the corona. | |e. |the heating in the chromosphere. | ____ 2. In some regions of the corona, the magnetic field does not loop back to the sun, and the gas escapes unimpeded. These regions are called _______________ and are believed to be the source of the solar wind. |a. |prominences | |b. |flares | |c. |granules | |d. |auroras ...
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...1. What is the dry adiabatic lapse rate (give a number with units)? The cooling and warming of unsaturated air of 10C every 1000 meters or about 5.5F for every 1000 feet. The rate of change of any meteorological factor with altitude, esp atmospheric temperature, which usually decreases at a rate of 0.6°C per 100 metres (environmental lapse rate). Unsaturated air loses about 1°C per 100 m (dry adiabatic lapse rate), whereas saturated air loses an average 0.5°C per 100 m (saturated adiabatic lapse rate) 2. Is the moist adiabatic rate greater than or less than the dry adiabatic lapse rate? Less .During saturated ascent, the release of latent heat via condensation partly offsets the conversion of thermal energy into work as parcels expand, reducing the cooling rate of the parcel to less than the dry adiabatic lapse rate (that observed for unsaturated parcels.) The saturated adiabatic lapse rate is 6 degrees per 1,000 meters. The dry adiabatic rate is 10 degrees per 1,000 meters. When a mass of saturated air rises in the atmosphere adiabatically,its temperature falls with height at a rate which is considerably less than the dry adiabatic lapse rate on account of continuous addition of the latent heat of condensation that accompanies the adiabatic cooling of saturated air and the consequent separating out of excess water vapour in the form of drops of liquid water. 3. A parcel of air becomes cooler than its environment if lifted. Is this a stable or unstable condition?...
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...DUE Wednesday, Jan. 16th at the BEGINNING of class. SUNBURN: A CASE STUDY IN THE INTEGUMENTARY SYSTEM DIRECTIONS: Answer the questions below in as thorough a manner as possible. Since you have more than a week to do it, your answers should be complete and polished. You may hand draw the diagram of skin, but the rest MUST BE TYPED or otherwise word processed and double-spaced. This assignment is due at the BEGINNING of the period, and any part of it not completed at that time will not be accepted for credit. Number your answers to correspond to the questions below. (NOTE: This material WILL be included on the next lecture exam; and you WILL NOT have this assignment graded and handed back to you before then. Be sure you have one copy to hand in, and one to study from.) One day in mid-July, a Walla Walla Community College student lies out in the sun for six hours. Later that night he notices that the skin on his trunk, legs and arms becomes red, swollen and extremely painful throughout the burned areas. By morning all of the afflicted areas have developed numerous blisters. These areas cover 35% of the trunk (front and back) and 25% of the arms and legs (front and back). 1. Draw a simple two-dimensional diagram of the skin, showing the three major layers (epidermis, dermis, and hypodermis) and the following accessory structures: a hair follicle, a sebaceous gland, eccrine and apocrine sweat (sudoriferous) glands, and an arrector pili muscle. Draw this diagram freehand. Do not trace...
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...Maths Studies Project: What is the most efficient method to decrease the surface area of an octagonal prism, whilst keeping the volume constant? Maths Coursework Title What is the most efficient method to decrease the surface area of anElizabeth Shaw chocolate box, whilst keeping the volume constant? Introduction- Aim I want to find out the smallest possible surface area of the octagonal Elizabeth Shaw chocolate box. A standard box has a volume of Xcm³, and has a surface area of Xcm². The volume of the box will have to remain the same throughout the entirety of the experiment. This is an example of the Elizabeth Shaw chocolate box, as you can see; it is a regular polygon with sides of 6.5cm length and a height of 3cm with a radius of 7.85cm. Minimising the surface area of the box would have a number of advantages; it would save costs of producing the packaging as well as producing fewer pollutants that would derive from producing the packaging, reducing our carbon footprint. My aim is to use the 3 mathematical techniques- 1. Trial and improvement (using excel) This will entail finding the minimum surface area by increasing the number of decimal places each time, for x value 2. Autograph (for PC) I will insert the optimisation equation into the program which will construct a graph, where the lowest point (where the gradient is 0) will identify the minimum surface area obtainable. 3. Algebraic Differentiation This is where I will These will be...
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