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Statistics MAT/300

As Manager of the Harley Bottle Company, I have been receiving complaints from customers on the quantity of product received when purchasing our sixteen ounces soda bottles. These complaints have caused my boss to worry and would like me to investigate the issue at hand. I will begin my investigation by instructing the employees to pull at random 30 bottles from all the shifts at the bottling plant. By pulling random containers from all shifts, I can eliminate the possibility of if being a human error. To start my investigation I begin by weighing the sample size of 30 bottles. The weight ranges between 14 oz. and 16.1oz., which lets be know there is a problem with our bottling consistence. For more detailed information to complete my investigation I must calculate the Mean, Median, and Standard Deviation of the sample size. * The Mean is the sum of the sample size in ounces divided by sample size. Based on the sample size of 30 bottles, there is a total of 446.1 ounces divided by the sample size of 30, gives is the mean of 14.87. = 14.87 * The Median is the data set middle number when the set is sorted in numerical order. Median of the 30 bottles is 14.8. * Standard deviation is the measure of how spread out the numbers is. To find the (Standard Deviation), you must find the square root of the variance. The is 0.5503.

The Harley Bottling Company is very optimistic of is bottling process. I will now construct the Confidence Interval of the ounces in the bottles at a 95%. The Confidence Interval describes the amount of the uncertainty associated with the sample estimate of the population parameter. By using the already discovered the information above I computed the Confidence Interval. 14.673 ≤ μ ≤ 15.067

My next course of action was to complete a hypothesis testing of the data…...

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...Bottling Company Case Study Imagine you are a manager at a major bottling company. Customers have begun to complain that the bottles of the brand of soda produced in your company contain less than the advertised sixteen (16) ounces of product. Your boss wants to solve the problem at hand and has asked you to investigate. You have your employees pull thirty (30) bottles off the line at random from all the shifts at the bottling plant. You ask your employees to measure the amount of soda there is in each bottle. Note: Use the data set provided by your instructor to complete this assignment. Bottle Number Ounces Bottle Number Ounces Bottle Number Ounces 1 14 11 14.6 21 15 2 14 12 14.7 22 15 3 14.1 13 14.7 23 15.1 4 14.2 14 14.8 24 15.2 5 14.4 15 14.8 25 15.3 6 14.5 16 14.8 26 15.5 7 14.5 17 14.8 27 15.8 8 14.5 18 14.9 28 15.8 9 14.6 19 14.9 29 16 10 14.6 20 14.9 30 16.1 Calculate the mean, median, and standard deviation for ounces in the bottles. According to Larson and Farber, 2009, the mean of a data set is the sum of the data entries divided by the number entries. To find the mean of the sample data set the formula must be used: Sample mean x̄ = (∑x)/N = 446.1/30= 14.87 According to Larson and Farber, 2009, the median of a data set is the value that lie in the middle of the data when the data set is ordered. The given numbers in the table are in order, there are thirty entries (an even number). The median is the mean of the two middle entries. Median...

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...Bottling Company Case Study Vincent Bacon Dr. Pamela Self MAT 300 Statistics December 14, 2013 Bottling Company Case Study Calculate the mean, median, and standard deviation for ounces in the bottles. To determine the mean, which is the statistical average of all numbers involved, we will add the number of ounces together and divide by the number of bottles, in this case 30. For the mean we get 446.1 / 30, for a mean of 14.9. The median, however, is the ‘middle’ number of the bottles ounces. Since we have an even number, it will be the average of the two middle numbers, which will give us a better perspective of the average than just the mean will. In this case it will be 14.8 + 14.8 / 2, which equals 14.8. The standard deviation is calculated to show how far apart the data can be. In the bottling case, after using the mean to get the variance, we divided by 30-1 to get a standard deviation of 0.55 (rounded down to two decimal places). Construct a 95% Confidence Interval for the ounces in the bottles. In order to construct a confidence interval, we need several statistics. The first is the sample mean, which is 14.9. Since we have selected a confidence interval of 95%, we need to find the margin of error to calculate our findings. Using the t-score model ( compute alpha, find the critical probability [.975], the degrees of freedom [999]) (StatTrek, 2013), we find that the critical value is 1.96. When we multiply this by the confidence......

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...Bottling Company Case Study Imagine you are a manager at a major bottling company. Customers have begun to complain that the bottles of the brand of soda produced in your company contain less than the advertised sixteen (16) ounces of product. Your boss wants to solve the problem at hand and has asked you to investigate. You have your employees pull thirty (30) bottles off the line at random from all the shifts at the bottling plant. You ask your employees to measure the amount of soda there is in each bottle. Note: Use the data set provided by your instructor to complete this assignment. Bottle Number Ounces Bottle Number Ounces Bottle Number Ounces 1 14 11 14.6 21 15 2 14 12 14.7 22 15 3 14.1 13 14.7 23 15.1 4 14.2 14 14.8 24 15.2 5 14.4 15 14.8 25 15.3 6 14.5 16 14.8 26 15.5 7 14.5 17 14.8 27 15.8 8 14.5 18 14.9 28 15.8 9 14.6 19 14.9 29 16 10 14.6 20 14.9 30 16.1 Calculate the mean, median, and standard deviation for ounces in the bottles. According to Larson and Farber, 2009, the mean of a data set is the sum of the data entries divided by the number entries. To find the mean of the sample data set the formula must be used: Sample mean x̄ = (∑x)/N = 446.1/30= 14.87 According to Larson and Farber, 2009, the median of a data set is the value that lie in the middle of the data when the data set is ordered. The given numbers in the table are in order, there are thirty entries (an even number). The median is the mean of the two middle entries. Median...

Words: 975 - Pages: 4

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...The purpose of this paper is to do a case study of a bottling company. The scenario is: Imagine you are a manager at a major bottling company. Customers have begun to complain that the bottles of the brand of soda produced in your company contain less than the advertised sixteen (16) ounces of product. Your boss wants to solve the problem at hand and has asked you to investigate. You have your employees pull thirty (30) bottles of the line at random from all the shifts at the bottling plant. You ask your employees to measure the amount of soda there is in each bottle. Use the data set below. Bottle Number Ounces Bottle Number Ounces Bottle Number Ounces 1 14.5 11 15 21 14.1 2 14.6 12 15.1 22 14.2 3 14.7 13 15 23 14 4 14.8 14 14.4 24 14.9 5 14.9 15 15.8 25 14.7 6 15.3 16 14 26 14.5 7 14.9 17 16 27 14.6 8 15.5 18 16.1 28 14.8 9 14.8 19 15.8 29 14.8 10 15.2 20 14.5 30 14.6 Calculate the mean, median, and standard deviation for ounces in the bottles. The mean is found by getting a total of all the ounces in the bottles. The ounces total, 446.10 and divided by the number of bottles of 30 is 14.87. The median is the midpoint of the data array which is when the data is sorted by size, the median is 14.8. The standard deviation is found by taking each value in the chart and subtracting the mean and squaring the value; get a total sum of the value of the squares and divide by the number of values minus one. The standard deviation is .55. Construct a......

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