Free Essay

Drosphilla Flies

In: Science

Submitted By chucky881117
Words 4038
Pages 17
Eyeless mutation gene located within the second intron of Drosophila melanogaster
Justin Lazarus
Genetic 300

The following experiment was conduct over a several week time span to determine and identify the mutation that is causing the eyeless mutation within the Drosophila melanogaster fruit flies. The experiment included genome sequencing and comparison between the Drosophila melanogaster wild type and the Drosophila melanogaster eyeless type. After combining the two different phenotypes. We determined that we were unable to visualize the mutation at a chromosomal level, as both wild-type and eyeless flies looked similar. The experiment involved electrophoresis and Polymerase Chain Reaction (PCR) through which we were able to isolate and amplify the needed DNA eyeless DNA. The difference between the wild-type Drosophila melanogaster and the eyeless Drosophila melanogaster is approximately only 500-nucleotide base pairs. As we see the eyeless phenotype is approximately 3000 base pairs in length while the wild-type phenotype is approximately 2500 nucleotides base pairs in length, a difference of about 500 base pairs. After completing nucleotide sequencing and comparing our data on the blast website, we determined that the eyeless mutation has being interest exons two and three, but more specifically the mutation itself was located within the second intron at base pairs 8264 to 9212.
In the early 20th century scientists had already been acquainted with chromosomes, yet the correlation between genes and heredity was still unknown. Many scientists believed that genes were located on chromosomes, but lack that scientific evidence to prove this theory. Thomas H. Morgan an American biologist along with his student at Colombia University discovered a particular eye color mutation in the Drosophila melanogaster. (1) Morgan was able provide definitive proof for the chromosomal theory of inheritance. Morgan was able to establish that the gene responsible for the white mutation in the Drosophila melanogaster was inherited together with the X-Chromosome.(1) Although Morgan’s data proved to be of great importance, it was Morgan’s student C.B. Bridges who ultimately unraveled the deviation to Mendel’s laws that had explained through chromosomal movement. Bridges was the first biologist to report on polytene chromosomes in detail. In certain organisms, some tissue may become polyploidy during the tissue development. The occurrence of this polyploidization may be the result for the need of multiple copies each chromosome along with the traits they accompany (1). The procedure that results in polyploid cells is known as endomitosis, this process incorporates the duplication of chromosomes, followed next by the detachment of the sister chromatids. This eventually leads to the build up of additional chromosomes in the nucleus.(1) Occasionally the polyploidization may not occur with the sister chromosomes being separated. This would results in a bundle of strands that are aligned in parallel. These chromosomes are known as polytene. Drosophila larvae have a great example of polytene chromosomes within their salivary glands. Each of these chromosomes has undergone nine separate rotations of replication, causing the overall production of 500 copies of every cell. (1). These copies will then bind closely creating a large bundle of chromatin fibers. According to Snustad and Simmons a mutation is defined as both a change in the genetic material, and the process by which this change occurred. A mutant is therefore defined as an organism that exhibits a novel phenotype resulting from a mutation (1). It had be discovered that mutation on a chromosomal level can occur due to many different reason such as deletion, in which a large amount of DNA sequencing has been removed. The type of mutation we see within the experiment would be the addition of nucleotides into the sequence, resulting in frame shift mutation. A novel phenotype could be a result of the transposons being added into a gene and therefor causing a mutation.
Drosophila melanogaster was among the first organisms used for genetics analysis, and today it is one of the most widely used and genetically best known of all eukaryotic organisms (2).
Drosophila eyeless mutation, this mutation leads to decrease production of the eye protein, resulting in a phenotype exhibiting a reduction or absence of the eye. This phenotype is viewed as a mutation yet the knowledge to why the mutation occurs is still limited. Eyeless gene is located on the fourth chromosome and when mutated, appears to produce variability in the size of the eye (3).
We believe that there are three possible hypotheses for the follow experiment. Firstly, we believe that there is a mutation within the splicing mechanism. Second, we believe that there is a mutation occurring within the scaffolding proteins. Finally we hypothesize that a mutation has occurred on the enhancer or silencer proteins.
Drosophila Polytene Chromosomal Squash Prep.
Polytene Chromosome Isolation/Staining
The purpose of this lab is to determine if the mutations studied in previous exercises are visible at the chromosomal level? We accomplished this through dissecting out the salivary glands from third instar larva in order to isolate the polytene chromosomes. These were then strains with Acetic-Orcein. This helped label the heterochromatic regions. After the chromosomes had been stained, we viewed the wild type and eyeless mutant under microscope to determine whether there was any visible difference between the two, or any signs of possible mutation.
Protocol had been modified from: Kennison JA, Preparations and Analysis of Polytene Chromosomes.
Genomic DNA isolation
In order to determine the cause of the eyeless mutation, we need to be able to determine the eyeless allele found in the mutant flies. In order to do this DNA from both the wild type and the eyeless adults had to be removed.
The following steps we use the Wizard SV Genomic DNA Purification System.
III.B. Preparation of Mouse Tail and Tissue Lysates (alteration) Mouse-tails were not used in this experiment; alternatively we ground up 25-30 flies to provide for the needed Drosophila melanogaster DNA. The tubes were not left over night overnight (16-18 hours), but rather incubated at 550 C for one hour.
PCR of the eyeless gene
The purpose of this section was to isolate the eyeless alleles from the previously isolated genomic DNA. Using primers designed to specific portions of the eyeless gene, we will attempt to “PCR out” the region of the genome potentially containing the eyeless mutation. (PCR kit from Promega).
A Typical PCR Reaction Alterations ddH2O 29.75ul (34.5ul) 10X PCR Buffer- 5.0ul (used 5x buffer instead of 10x) MgCl2 (25mM)
 3.0ul dNTPs (10mM each) 1.0ul Primer 1 (10uM) (F) 2.5ul Primer 2 (10 uM) (R)
DMSO (Optional) 5.0ul (DMSO is omitted) Taq 0.25 total 49ul (Add 1ul of DNA (1 ng final volume))

Cycle: 1. Hot Start | 94C | 2 min | 2. Denaturation | 94C | 1 min | 3. Annealing | 35C – 62C | 1 min | 4. Elongation | 72C | 3 min | 5. Final Elongation | 7oC | 5 min Indefinitely | 6. Hold | 4C | | | | | Steps 2-4: Repeat 35 times | | |

PCR Clean Up
The purpose of this section was to obtain DNA from the previous laboratory session and purify it. To ensure there is no harmful by product from the PCR reaction that could potentially interfere with the experiment. The PCR clean up reaction was performed to ensure the proper DNA sequence is obtained.
Agarose Gel Electrophoresis:
1. Make a 1% agarose solution
a. Weigh out 0.4 g agarose and add it to 40 ml of 1x TAE in small flask
b. Bring the solution to a boil in the microwave (roughly 30 seconds on high). c. Be sure that the agarose goes in to solution (no white “chunks”.
d. Add 1.0 μl of 10mg/ml ethidium bromide.
e. Allow the solution to cool for 30 second or until it is approximately 500C.
2. Place cold dams in the apparatus and pour the agarose into gel apparatus.

3. Insert the comb with appropriate number of teeth into the gel solution. 4. Let the gel solidify at room temperature. 5. Remove the dams from the gel box, and cover the gel with 1x TAE Buffer.
6. Load the samples when ready
Cut out the DNA band of interest from the gel using a coverslip. Be sure that the chunk of agarose is as small as possible.
Follow the Procedure in the UltraClean 15 DNA Purification Kit (or Comparable DNA Extraction Kit) protocol alteration were made at this step. The UltraClean 15 DNA Purification Kit was replaced with Wizard SV and PCR Clean-Up System. Also we skipped section B and instead of using 50ul in step 8 we only used 25ul
Data collected 1.052mg/without DNA and 1.087 mg showing a 35 mg difference =35ul
End-A Cloning
This section of the experiment focused on the cloning of the PCR fragments in order increase to a suitable concentration for sequencing. Cloning will allow us to manipulate the PCR fragments, prior to cloning, we must use Taq polymerase to re add the “End-A’s” as they are lost over time.
Readdition of End A’s to the PCR Fragment
Steps 1-3 remained the same as below
1. Please set up a PCR reaction with the following ingredients for each of your samples in a PCR tube.
1.0 ul of PCR Buffer

0.2 ul of dNTP’s
0.2 ul of Taq

8.6 ul of sample DNA (prior PCR product)
2. Place the reactions into the thermocycler set at the following parameters.
940C: 2 Minutes 680C: 30 minutes 40C: infinite time.
3. Remove the samples from the thermocycler following the 30-minute run.
Alteration occurred at this point during the End-A Cloning Reaction/Transformation protocol. We used the pGEM®-T and pGEM®-T Easy Vector Systems

- Protocol for Ligations Using the pGEM ®-T and pGEM®-T Easy Vectors and the 2X Rapid Ligation Buffer
Section IV changes:The amount of PCR product add was 3ul to keep the total of 10ul
Section V changed to protocol: Step eight required: Add 950μl room temperature SOC medium to the tubes containing cells transformed with ligation reactions and 900μl to the tube containing cells transformed with uncut plasmid. we only added 100ul not 950ul rest of the protocol remained the same.

Miniprep of Plasmid DNA
This section of the experiment was to isolate the plasmid vector from the bacterial host so that we can prepare the DNA for sequencing, this process is also known as Mini prep. We used be the Promega Wizard Miniprep Kit
Two alteration occurred during this protocol was when using the Restriction Enzyme Digest protocol. Firstly, in step two 0.1ul of ddh2o was added instead of 1 ul Not 1. Secondly, instep four incubation was not for an hour and a half as indicated in the protocol but rather only incubated for one hour.
DNA Sequencing
The following section of the experiment involved the sequencing the isolated plasmids in order to determine the sequence of the eyeless fragment. We used the Sequenasetm sequencing kit and the LiCOR gel apparatus.

DNA | 2.64ul | fwd Primer | 1.5ul | reverse Primer | 1.5ul | Reaction Buffer | 7.2ul | Polymerase | 1.0ul | water | 6.16ul | total | 20ul |
Given: 200fmol DNA:
Wild-type= 5500 base pairs
Eyeless= 6000 base pairs
* 660g/mol base pair
Equation to determine the amount of ul DNA need
660/mol bp x 109/1g x mol/ 1015fmol x 6000bp x 1ul/ 300ng x 200fmol
=2.64 ul DNA
Analysis of Sequencing Results
This section of the experiment will be analyzing the results of the sequencing reactions in order to determine the cause of the eyeless mutation.
We have the eyeless gene now located within the pGEM-T plasmid. We bind two separate primer to the to the sequence, moving in opposite direction. One primer would be located on the top strand while the second primer is located on the bottom strand both moving in the 5’ to 3’ direction.
We only expect to correctly sequences approximately 800 base pairs. We where given two eyeless sequences along with one wild-type sequence.
The Sp6 primer as well as the T7 primer would act each of these sequences on. What analyzing the pGEM-TEZ we found that T7 also has a promoter region known as T7, which it recognizes, and starts priming from 5’ to 3’. T7 works on the top strand. While Sp6 doesn’t have a promoter site is does prime 5’ to 3’ on the bottom strand. These are known as the forward and reverse primers.
Eyeless 1 Sp6.
Trim down the sequence to about 800 base pairs, we then highlighted the characters that followed the 800 characters. At no point did we delete any of the character. The highlight characters merely suggest that they are not included. We only want to keep these 800 characters as more than this would create chaos and may skew that data towards alternative things located within the plasmid.
When determining the front-end sequence when looking at the pGEM-T plasmid, there is about 60 base pairs sequenced prior to the insert these sequences will be seen as vector and not insert. This sequence must therefore be trimmed as well. When analyzing Sp6 you have to look at the sequence but in the opposite direction as Sp6 is associated with the bottom strand. We started off looking for GAATT then CACTA, next GTGATT all of these sites were located in the vector and needs to be trimmed out.
Now that we have determined the sequence we needed we wanted to know do we have eyeless insert. We do this by using blast (Basic local alignment search tool), as it contains recording of all known sequences. We can use this to compare and contrast our sequence to other known sequences. After completing this with the other two sequences we can determine the approximate base pairs they align to.
Polytene chromosomes

Figure 1. Drosophila Polytene Chromosomes that have been labeled with an unknown dye. Polytene chromosome differs greatly in size compare to that of the mitotic chromosomes. Top left corner illustrates the comparative size of normal mitotic chromosomes to the extreme size of the Polytene Chromosomes

Figure 1. Drosophila Polytene Chromosomes that have been labeled with an unknown dye. Polytene chromosome differs greatly in size compare to that of the mitotic chromosomes. Top left corner illustrates the comparative size of normal mitotic chromosomes to the extreme size of the Polytene Chromosomes

PCR gel of WT and eyeless

Figure 2: PCR gel of WT and eyeless.

This figure represents the difference in base pair sizes of the wild-type and the eyeless genes. Wild-type exhibits 2500 base pairs while eyeless mutation exhibits 3000 base pairs, this is the representation of nucleotide insertion occur. Wild-type is shown on the far right hand right of the figure while eyeless is represent to its immediate left. The 1kb DNA ladder in the far left lane
Figure 2: PCR gel of WT and eyeless.

This figure represents the difference in base pair sizes of the wild-type and the eyeless genes. Wild-type exhibits 2500 base pairs while eyeless mutation exhibits 3000 base pairs, this is the representation of nucleotide insertion occur. Wild-type is shown on the far right hand right of the figure while eyeless is represent to its immediate left. The 1kb DNA ladder in the far left lane

Introns and exon containing the eyeless mutation Exon 1 | | | Exon 2 | 8264 to 9212 | | Exon 3 | | Exon 4 | | Exon 5 | | Exon 6 | |
Figure 3. Exon and intron containing eyeless mutation within the wild type sequence.
The figure above explains that when searching for the eyeless Sp6 aligns to the location to which the eyeless mutation is located. this showed that the eyeless mutation occurs with intron 2.
Figure 3. Exon and intron containing eyeless mutation within the wild type sequence.
The figure above explains that when searching for the eyeless Sp6 aligns to the location to which the eyeless mutation is located. this showed that the eyeless mutation occurs with intron 2.



Sequence 1: Seye1-Sp6. Sequence one represents the eyeless 1-Sp6 sequence.

The sequence shows three separate colors. The sequence that has been highlighted yellow and red are parts of the vector sequence and have been trimmed.
Sequence 1: Seye1-Sp6. Sequence one represents the eyeless 1-Sp6 sequence.

The sequence shows three separate colors. The sequence that has been highlighted yellow and red are parts of the vector sequence and have been trimmed.

Blast graphically representation of similarities to another known sequence the closer the sequence is to red to closer the similarity between the two sequences are.
Sequences producing significant alignments:

Chart 1: Seye1-Sp6 graphical depiction. The chart above shows the representation of the similarity of Seye1-Sp6 and other known sequences. The more red depicted show greater evidence that there is strong correlation to another known sequence
Chart 1: Seye1-Sp6 graphical depiction. The chart above shows the representation of the similarity of Seye1-Sp6 and other known sequences. The more red depicted show greater evidence that there is strong correlation to another known sequence

Table 1: This table represents sequences with similar or containing similar sequences as the Seye1-Sp6. Our main focus is that of the E value as this shows the level of identity, the closer the E value is to zero the closer the two sequences are to being same. As E value moves away from zero it begin to loose similarity.

It is important to acknowledge the fact that of the initial six sequences pulled up five of them spoke about the Drosophila melanogaster chromosome 4. This is vital information because we are sequencing the Eyeless –Sp6 we would expect to see chromosome 4 sequences evident, as the eyeless gene is located on chromosome 4.
Another important bullet would be the Drosophila melanogaster eyeless (ey), transcript variant D, mRNA this transcript showed 58/58(100%) identities. The Expect may not be close to zero but this is due to it being a transcript variant.
This is due to we added genomic DNA into the plasmid which contained everything as nothing has yet to be processed out yet. The only thing to be process out at this point would be the intron of the genomic DNA.

Sequence 2: Seye2-Sp6. Sequence one represents the eyeless 2-Sp6 sequence. The sequence shows three separate colors. The sequence that has been highlighted yellow and red are parts of the vector sequence and have been trimmed.

Chart 2. Seye2-Sp6 graphical depiction. The chart above shows the representation of the similarity of Seye1-Sp6 and other known sequences. The more red depicted show greater evidence that there is strong correlation to another known sequence. The large amount red depicted here is due to the large occurrence of vector which exhibit similar multiple binding sites

Chart 2. Seye2-Sp6 graphical depiction. The chart above shows the representation of the similarity of Seye1-Sp6 and other known sequences. The more red depicted show greater evidence that there is strong correlation to another known sequence. The large amount red depicted here is due to the large occurrence of vector which exhibit similar multiple binding sites

When comparing the Wild-type and Eyeless 2 to eyeless we see there is a large amount of vector present, evidence didn’t show signs of pGEM-ETZ as there was such a large amount of vector present. The identity for all the vector would be zero or close to zero therefore line up, vectors also all have multiple cloning sites. Vectors do differ slightly from one to the next, but all vectors have multiple cloning site region that are pretty close to being the same.
When development of colonies occurred, we notice both white and blue colonies. The white colonies gave evidence that we had only obtained vector and not insert. This could have occurred when the vector and the eyeless were place together through the ligation process. If it only shows the vector is present then ligation didn’t occur and we weren’t able to get any one the eyeless. The gene didn’t stay linear to itself. The vector we have is B-galactosidase, it multiple cloning sites are located in the middle of B-galactosidase, so if B-galactosidase is present it cleaves the x-gal and the gel would turn blue.
White colonies don’t have a functional B-galactosidase, this is possible when you experience nuclease degradation and eliminate enough B-galactosidase so that it become non-function.
Most of the time blue-white colonies will show whether or not you have insert present.
At the start of this experiment we had three possible hypotheses for the follow experiment. Firstly, we believe that there is a mutation within the splicing mechanism. Second, we believe that there is a mutation occurring within the scaffolding proteins. Finally we hypothesize that a mutation has occurred on the enhancer or silencer proteins. As we have discover the hypothesis for mutation of the splicing could not be possible. If we were to encounter a mutation of the splicing mechanism it would alter everything we are seeing. Throughout the experiment there was no signs that mutation of splicing mechanism had occurred, as intron would be spliced out during the formation of the proteins.
When it came to the hypothesis that the scaffolding attachment regions SAR were mutated. If this were to occur it would have to occur on a large scale. If only one or a couple SAR’s were to be mutated, there would still be a metaphase chromosome. Apposing this is the possibility that the SAR’s underwent large mutation, this theory isn’t possible because if large amounts of SAR’s were mutated the phenotype would experience death. Therefore, this hypothesis doesn’t fit our phenotype we seeing.
Lastly, our hypothesis that a mutation that effected the silencer or enhancer. This hypothesis is not completely correct. When analyzing silencer, if we where to have 500 base pairs and have disrupted a silencer their would be an affect on gene translation but not in the way we would expect to see eyeless flies. If the silencer is effected then its ability to silence would be hindered, and transcription would increase. Therefore, the mutation of a silencer doesn’t fit our phenotype as it exhibits smaller eye.
The best possible fit for a hypothesis is the mutation of an enhancer. If there were an enhancer located in the intron, a 500 base pair insertion would disrupt its activity. This would cause the lowering of expression of the eye protein causing less eye protein to be present resulting in the phenotype of eyeless. This hypothesis does fit our expectations and results
We would test thing by performing a western blot test and a northern blot test. If we were to run the western blot test we would expect to see a decrease in expression of the protein of the eyeless compared to that of the wild type. If we were to run a northern blot test we would see an effect on the mRNA, the eyeless genes would experience a decrease in the mRNA. The use of RT-PCR (reverse transcriptase PCR) to isolate mRNA to reverse transcribe into DNA to have an idea how much mRNA is present. This would tell that there is less eyeless protein.
We would correlate this with the phenotype by variable expression as this could compare the eyeless flies that have variable expression and see if the levels of eyeless proteins or mRNA correlate with the phenotype.
Lastly, we could knock out the enhancer proteins and study the effect on the phenotype. We would take wild-type flies and mutate the region to which the enhancer encodes and see how they may differ, if we mutate the element being the enhancers we would expect to produce eyeless genes.

Reference page 1- Snustad, D. Peter., and Michael J. Simmons. Principles of Genetics. Hoboken, NJ: Wiley, 2012. Print. 2- Bruce , A., Bray, D., Hopkin, K., Johnson , A.D., Lewis, J., Raff , M., Roberts, K., & Walter, P. (2009). Essential Cell Biology (3rd edition ed.). 3- Arnini, C. 2012. Using Drosophila to Teach Genetics. Yale-New Haven Teachers Institute. Unit 96.05.01.

Similar Documents

Free Essay


...Entomotoxicology The process of decomposition begins immediately after death and the process can be divided into five stages: fresh, bloated, decay, post-decay and skeletal. Therefore, the availability of tissues and blood samples for toxicological analysis is dependent on the state of decomposition. There are cases where blood and tissue samples are not available or suitable for analysis, the fly larvae found on the cadaver can be used as an alternative toxicological specimen. Successful detection of substances has been accomplished by several extraction methods from maggots, pupae and adults of Diptera and even from the feces of beetles (Miller et al. 1994). Bourel et al. (2001) conducted a study which showed that morphine was detected on third larval instar maggots of Calliphora vicina Linnaeus (Diptera: Calliphoridae) fed with an artificial diet mixed with the drug. This shows that morphine was stored inside the cuticle of the maggots during their development. However, the detection of diethylpropion (Inebex) showed negative result in larvae of Chrysomya megacephala and Chrysomya putoria suggesting the rapid excretion of drugs (Alves et al.2008). Insect succession Insect succession is the wave or pattern of insects’ colonization on dead remains and is also affected by the surrounding environment. Invasion of a body by insects and other arthropods occurs soon after death (Anderson and Goff, 2000). They are capable to arrive and colonized within minutes of the death......

Words: 2156 - Pages: 9

Free Essay

The Dream

... Elise Ashley Leyva I have chosen the article “A Normative Theory of Forgetting: Lessons from the Fruit Fly” I chose this article because the name was very interested to me, and I thought it would be very interesting. I also chose this article because it consisted of theories and experimental conditionings of why we forget thing. This caught my attention because for many, many years I have always wondered why I would forget things. This raised a concern and the urgency to learn this within this lesson because it would occur very frequently to me. As I was growing up, and even throughout my adult hood people close to me also noticed this, and I never know why, until reading more about this issue and how it affect other people as well and why it happens. This article conducted of a conditioning experience that featured a Drosophila melanogaster also known as a fruit flies. Conducting this experience it revealed that the cause underlying forgetting is an active process which is modulate by the learning task and not by internal constraints of memory system. This fly has been the favorite organism for biological research, initially in the field of genetics and now for the fundamental problems in biology freedom the fields of ecology and neurobiology. This was done by taking a group of fruit flies and placing them into a tube for conditioning, of course. This group was exposed to a specific odor and the exposer was paired with an......

Words: 763 - Pages: 4

Free Essay

Time Is a Healer

...Time is a Healer In Katherine Mansfield’s short story “The Fly”, she tells of a man and his struggle with the loss of his son. The setting starts out in the boss’s office, where he is talking to a man we know as Mr. Woodifield. Mr. Woodifield is an older gentleman whom since he had a stroke his family keeps him boxed up in his home every day of the week, expect for Tuesdays. Mr. Woodifield and the boss talk about the new decorations of the boss’s office, there is something though that Mr. Woodifield struggles to remember that he wanted to tell the boss. He remembers that is was his daughters had ran across the boss’s son grave while looking at Reggie’s, his son whom he had lost in World War One, grave. He goes on to tell the boss of how well the place is kept, and how his son and Reggie were quite close to one another. After Mr. Woodifield leaves the boss tells his office messenger that “I’ll see nobody for half an hour.” He begins to attempt to grieve over the loss of his son the way he used to be able to. He finds himself unable to weep and he finds himself easily distracted by a simple fly. The fly falls into the ink pot and the boss watches him struggle over and over until he is finally unable to overcome and dies. The moral of this story seems to be that time can heal all grief. Mr. Woodifield is a gentleman whom was a former employee of the boss. He has retired after the stroke he had and comes to visit the boss on Tuesdays, when his wife and girls let him...

Words: 975 - Pages: 4

Free Essay


...single black fly sat on the label of his greasy jacket. A short time later, there were already two. They ran up to him and crawled into his face, but he did not seem to notice. More flies were added, crawled over his nose, his cheeks, his lips, but he showed no reaction. It was not long, and they crept into his nostrils, in his eye and in his ears. They crawled out purely and again and showed it in no hurry. They inspected it really thoroughly, and he let it happen impassively. After some time had gathered two dozen flies on him, they now crawled into his sleeves and into the gaps between the neck and shirt collar. Walker came along the road and went between us through. They took no notice of him. As it dawned, the number of flies had grown to several hundred. I stood up and went home. When I again the next day I approached my place on the bench, hit me in the smell of vinegar from afar contrary. The man in the hat was already sitting opposite on the bench. The flies had almost completely taken possession of him. They ran all over him around, sometimes flew in small groups and then sat down again. He just sat there and looked like the day before indifferent through me. The fly took the occasion to be a little bolder. Increasingly, they were crawling now in his ears and in his nose. His face betrayed not even a twitch, as tentatively crawled the first maggots on his forehead. Dense clouds of flies buzzed around him now. His clothes were completely covered with flies.......

Words: 669 - Pages: 3

Free Essay

Wk 4 Hw Problems

...WEEK FOUR HW PROBLEMS There are four problems, each of which is worth one point. 1. Five Proteen Bars and 7 Superdrinks total 1915 calories. Four Proteen Bars and 3 Superdrinks total 1155 calories. How many calories does one Proteen Bar have? One Superdrink? One Proteen Bar has 180 calories and one Superdrink has 145 calories. 2. A plane goes from A to B against the wind in 4 hrs and 30 minutes. It goes back again (WITH the wind) in 3 hrs and 40 minutes. It is 400 miles from A to B. How fast does the plane fly in still air, and how fast is the wind? (Round to nearest hundredth.) The plane flies at 99.09 mph in still air and the wind is 10.2 mph. 3. You want 40 liters of 60% solution. How much 80% solution and how much 28% solution must you mix to produce that result? (Round to nearest hundredth.) In order to produce 40 liters of 60% solution I will need 24.62 liters of 80% solution and 15.38 liters of 28% solution. 4. Seven curly fries and four plain fries cost $16.83. Five curlies and 12 plains cost $23.45. How much does one order of curlies cost? One order of plains? One order of curlies costs $1.69 and one order of plains costs $1.25. 5. Solve the following system of equations: 2X + 3Y = 29 X + 1.5Y = 8 The system of equations is inconsistent and has no...

Words: 254 - Pages: 2

Premium Essay

Forensic Entomologists

...such as specimen cups, pharmacy bottles, labels, nets, and dissecting forceps. Included in their array of gear is a “killing jar,” which is a glass jar containing ethyl acetate-soaked cotton balls. There are a number of procedures forensic entomologists must follow when it comes to collecting specimen. They must first collect any live flies using nets, then the largest maggots and egg mounds found on the remains. The bug experts preserve a few of the collected maggots by plunging them into boiling water then storing them in alcohol. This stops any chance of discoloration or decomposition of the maggots. Not only do forensic entomologist need to collect any insects seen with the naked eye, they also check ear canals, nasal openings, other orifices, and any open wounds for the presence of insects....

Words: 700 - Pages: 3

Premium Essay

Lord of the Fies Essay

...Elisabeth Dolgetta Per.1 English Lord of the Flies Essay II. A leader is a person followed by others. Leaders who aren’t strong cannot stick to the rules and control a group. Leaders who are overly controlling become dictators and everything turns into chaos. A good leader is ambitious, intelligent, has good ideas and takes responsibility. In the novel, “Lord of the Flies” by William Golding, leadership is destroyed and anarchy is created. In the novel, young boys are on a plane that crashes and they arrive on a deserted island alone. There are no adults on the island. The boys were initially on the plane to be evacuated from the war. Their first thoughts are to be rescued. A boy named Ralph introduces himself to a boy whose real name is unknown but they call him Piggy, although that isn’t his wish. Ralph becomes leader because he is voted in by other children in the beginning. A leader is needed to help everyone work together and to get food, water, shelter and to be rescued from the island. Ralph had everything he wanted to stay organized, and to keep every rule he made. Ralph and Piggy discover a conch shell on the island and use it to call the boys together. "We can use this to call the others. Have a meeting. They’ll come when they hear us—." Piggy says this. At this point the conch is used to make rules for everyone to follow and it symbolizes civilization and order. Any boy, who holds the conch, has the right to speak. Every time Ralph wants......

Words: 579 - Pages: 3

Free Essay

Fly Ash Brick

...Mayank Patel, Ahmedabad Partner & Director Mobile : 91 9662910224 Write us: Manish Kharti, Deesa Partner & Director Mobile : 91 9737689393 Write us: Mayank Patel Call : 91 9662910224 Manish Kharti Call : 91 9737689393 Fly Ash Brick Project Details Key features of the Fly Ash Brick project  Cost of Project     Cost is INR 70 Lakhs Land cost not included in this Value. It includes Installation cost and equipment cost. Equipment cost approximately INR 25 Lakhs.  Land Required  1-2 Acre Per Plant  Type of Raw material  Basic row material for fly ash bricks plant such as        Fly Ash Lime Gypsum Cement Sand Stone Dust Down Metal  Consumption of Row Material  Rated - 59 Ton per shift Mayank Patel Call : 91 9662910224 Manish Kharti Call : 91 9737689393  Generation  Generation per 8 hour = 18400 Units  If Plant works for 24 Hours a day  Generation per day = 3 * 18400 = 55200 Units  Generation Per Year  For 1st Year = 16560000 Units  From IInd Year onwards = 17280000 Units  Unit Drawing :  Cost of Generation  Cost of Fly Ash Brick produced is INR 1.7 to INR 2.7 /- per unit including all. Its depends as on type’s of production been used.  INR 1.7 to INR 2.7 /- per unit Cost has been calculated taking into account Production as well as operation and maintenance, Interest, depreciation, cost of raw material and transportation cost.  Buy back tariff  Form Buyer INR 3.7 – INR 4...

Words: 438 - Pages: 2

Free Essay

Coal Ash

...Two years ago, a massive coal-ash spill in Tennessee awakened Americans to the fact that the billion tons of coal we use each year doesn’t vanish into thin air when it’s burned. In 2008 alone, U.S. power plants produced nearly 100 million tons of coal ash; combined with other coalburning residues, such as gypsum, the total was 133 million tons. Much of that waste is mixed with water and kept in clay-lined ponds, often remarkably close to rivers, underground wells, and residential areas. On Dec. 22, 2008, at the Tennessee Valley Authority’s Kingston Fossil Plant, a dike broke and released 1.1 billion gallons of ash slurry. The ash spilled into the Emory River and inundated 300 acres of surrounding land. It was the largest fly-ash release in U.S. history, causing an estimated $3 billion in damages. And it could happen again, at another plant – reports have identified high-risk ash ponds across the country. Plus even when it doesn’t spill, coal ash disposal can be hazardous to your health: In many communities, concerns about groundwater contamination have been raised. Lisa P. Jackson, head of the U.S. Environmental Protection Agency, vowed to ensure no disaster like the TVA spill ever occurs again. Coal ash disposal, she argued, should be regulated to protect the public – and since early 2009, EPA has been working toward that goal. But it’s not an easy process. Since 1980, coal ash has been excluded from regulation as a hazardous waste under the so-called Bevill......

Words: 398 - Pages: 2

Free Essay

Lord of the Flies

...Lord of the Flies Comprehensive Test True/False- Mark “A” for True and “B” for False. 1. When Ralph is elected chief, Jack is so frustrated that he refuses to hunt. 2. Ralph starts the signal fire by rubbing two sticks together. 3. The signal fire goes out because Jack and the hunters neglect it. 4. A wild boar eats the littlun who has a mulberry-colored birthmark on his face. 5. Piggy’s parents will come find them. 6. The conch provides a symbol for authority that the boys recognize as civilized. 7. The main source of food on the island is food scavenged from the wreckage of the airplane. 8. The boys murder Simon because they think that he is “batty.” 9. Piggy is not afraid of Jack because he knows that SamnEric will protect him. 10. Ralph and Jack initially had a mutual respect for each other that diminished by the end of the book. Match the following descriptions with the choices given (A-E) a. Ralph b. Piggy c. Jack d. Simon e. Roger 11. dies when a rock falls on him 12. the elected leader of the group 13. the most evil character; kills Piggy 14. puts his own lust for hunting ahead of everyone else’s needs 15. sees people for what they really are 16. represents the power-hungry dictator in society 17. represents the mystic philosophers in society 18. represents the good-hearted rule-following leaders in society 19. represents the evil sadist figures in society 20. represents the......

Words: 1447 - Pages: 6

Free Essay

Corruption vs. Civilization in Lord of the Flies

...Every now and then, one finds themselves taking a deeper look inside of their soul, often times resulting in the discovery of an inner being. This inner being is perfectly depicted through the lord of the flies. Contrary to the boys’ beliefs, the lord of the flies, or in the novel the symbol of the "beast", is not "something you could hunt and kill" (164), but rather a spirit that dwells inside of a soul, and slowly seduces one into complete and utter savagery. In the novel, Lord of the Flies, William Golding gives the reader a glimpse into a society composed of a group of young British boys, all raised in a civilized and orderly manner, that find themselves stranded on a deserted island. Fighting for survival, many of the boys surrender to the Beast that engulfs them. Others, like Ralph, find themselves in a much more complex and compromising battle- one that takes place inside the mind. In his novel, Lord of the Flies, William Golding uses the motifs of the pig dance, the conch, and the masks to convey the theme that man becomes a corrupt and savage being without a strict system of order and civilization. By dancing and singing to celebrate the brutal murdering of a pig, the boys enter into a society, or even a cult, surrounded by sadistic and brutal thoughts. The first time the boys perform this ritual, Golding describes their actions as “relieved and excited…making pig-dying noises and shouting” (81). Clearly, the boys feel a rush of exhilaration and excitement when they...

Words: 1254 - Pages: 6

Free Essay

Parents and Entitlement in Huck Finn

...'LORD OF THE FLIES' by William Golding “Revision notes can never replace knowing the books thoroughly” J.W.Evans These notes should be used as pointers to the directions that your thoughts might take. They are not meant to replace your reading of the novel, you must still do that yourself.. CHARACTERISATION Never forget that we are talking about a group of boys whose maximum age is twelve. RALPH Does he represent all that is good in people? Tall, fair-skinned, blond hair, very athletic, natural leader although not that good a leader as many of his decisions are questionable, which ones?. He is middle-class, father a naval officer. Elected leader but not forceful enough to maintain position. Eventually he loses support and is reduced to the status of an outcast who must flee for his life. Ralph is an idealist and a dreamer. He needs Piggy to think for him. He finds the Conch but Piggy tells him how to use it. At the end of the book, he is a disillusioned realist who now sees his world and its inhabitants for what they are. JACK MERRIDEW Does he represent the worst in people? He is thin, tall, with red hair, light blue eyes and freckles. Leader of the choir, he becomes the leader of the hunters. Increasingly in conflict with Ralph and more particularly, Piggy, he breaks away, forms his own tribe and splits the group. He manages to get the support to do this by offering the boys the attraction of the hunting life and then by terrorising them. In the...

Words: 3535 - Pages: 15

Free Essay

Ash Utilization in Private Power Plants

...Private power plants Ash utilization MoEF Notification (3rd Nov 2009) on Fly Ash Utilisation has instructed Operating Coal/Lignite based Power Plants to Achieve the Target for 100% Coal Ash Utilisation S. No. Percentage Utilisation of Coal Ash Generation Target Date from the Date of issue of this Notification 1. At least 50% One Year 2. At least 60% Two Years 3. At least 75% Three Years 4. At least 90% Four Years 5. 100% Five Years A. TATA POWER Trombay, Jojobera and Maithon thermal power plants achieved 100% fly ash utilization whereas CGPL achieved 25% in its first year of full operation, which is in line with regulatory requirements. Innovations 1. Ultra-Thin White Topping technology: CTTL, a wholly owned subsidiary of Tata Power, in association with BASF, has developed a concrete mix which can help replacing 40% of cement with Fly Ash. The polyheed admixture developed for Trombay Thermal Station Fly Ash has been used in a demonstration project. A demonstration road stretch of 3.5 m x 100 m has been laid. This road has lower absorption of solar energy (higher reflectivity) and is expected to have a longer service life. 2. Bottom ash based brick making: Bottom ash based bricks were manufactured successfully. A patent on the same has been filed. Technologies Being Reviewed / Adopted Fly ash based plaster sand: Additives are added into fly ash and mixture is processed to manufacture ceramic sand through an already patented process. This sand is......

Words: 1615 - Pages: 7

Premium Essay

Jack Lord Of The Flies Character Analysis

...Throughout the book Lord of the Flies, Jack goes through several transformations. He starts out as the leader of his choir; someone who is seen as an orderly leader seeking precision in everything he does. This is shown when Jack yells, “Choir! Stand still!” (Golding 19). Although he is shown as orderly in the beginning, he soon gives us hints about his more aggressive and harsh side. He starts by pointing out Piggy, saying, “Shut up, Fatty.” (Golding 21). Towards the end of the book, he has turned into someone wild and untameable; he has lost control of himself and has succumb to the beast within. Jack was the leader of the hunters, or ‘savages’, on the island. He went out with his boys and hunted pigs for them to eat. Not to mention, when...

Words: 727 - Pages: 3

Premium Essay

Comparing Opening Skinner's Box And Lord Of The Flies

...William Golding’s Lord of the Flies and Lauren Slater’s Opening Skinner’s Box both take a look at human perpetuation towards evil. Slater argues that humans may commit evil deeds when obeying authority, by observing Stanley Milgram’s experiment in her second chapter, “Obscura”. In chapters one through six of Lord of the Flies, Golding examines society through the perspective of young boys, and their finding of inner evil. I think both Slater and Golding would argue that it is easy to find evil, when one loses their self. I believe that the quintessential part of “Obscura” is when Lauren Slater examines Milgram’s obedience experiment’s effect on people. In other words, Slater contends that the experiment has “managed to stamp itself so solidly into these men’s undeniably real lives” (58). Those personal interviews and stories share...

Words: 538 - Pages: 3