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Ecet310

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Homework 1_1
ECET310

1. Add: (a) 60 dB + 25 dB = 85 dB (b) 20 dBW + 5 dBW = 25 dBW (c) 22 dB - 4 dB = 18 dB

2. Convert:

(d) 65 W into dB

10log(65) = 18.1291 dB

(e) 10 dB into watts

log^-1(10/10) = 10 W

(f) – 5 dB into watts

log^-1(-5/10) = 0.3162 W = 316.2 mW

(g) –30 dBm into dBrn

-30 + 90 = 60 dBrn

(h) 15 dBrn into dBm

AP3 = 30
AP3 = 30
AP2 = 25
AP2 = 25
AP1 = 10
AP1 = 10

2. A three-stage amplifier is shown with power gains. Calculate total power gain in decibels, and as a number.

A_p(tot)_(dB) = (10)(25)(30) = 7500

A_p(tot)_ = 10log(10) + 10log(25) + 10log(30) = 38.75 dB

AP3 = 20
AP3 = 20
AP2 = 10
AP2 = 10
AP1 = 10
AP1 = 10

3. (a) Determine the overall power gain.

Ap(t) = (10)(10)(20) = 2000 (b) Find the output power if Pin = 15 mW

P_o_ = (15mW)(2000) = 30 W

AP3 = -6 dB
AP3 = -6 dB
AP2 = 16 dB
AP2 = 16 dB
AP1 = 13 dB
AP1 = 13 dB

4. If Pin = -20 dBm, determine the output power in dBm and watts.

A_p(t)_ = 13 + 16 – 6 = 23 dB

A_p(t)_ = log^-1(23/10) = 199.526

-20 dB = (1mW)(log^-1(-20/10)) = 10µW

P_o_ = (10 µW)(199.526) = 1.995mW

P_o_ = 10log(1.995mW/1mW) = 2.9 dBm

PS = 0.1W
PS = 0.1W

AP1
AP1
AP2
AP2

AP1 = 400 AP1 = 400 L = 2000 L = 2000 AP2 = 500 AP2 = 500
RL
RL 0
1
0
1

5. Determine:

(a) Net gain (b) Net gain in dBs (c) Power output

(a) A_P(t)_ = (400)(1/2000)(500) = 100 (b) A_P(t)_ = 10log(100) = 20 dB (c) P_o_ = (0.1W)(100) = 10W

PS = -8 dBm
PS = -8 dBm

AP1
AP1
AP2
AP2

AP2 = 28 dB AP2 = 28 dB AP1 = 32 dB AP1 = 32 dB L = 24 dB L = 24 dB
RL
RL 0
1
0
1

6. Determine:

(a) Net gain (b) Net gain in dBs (c) Power output

(a) A_P(t)_ = 32 dB

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