Free Essay

# Gs1140 Mod 4.4

Submitted By JackMehoffGood
Words 414
Pages 2
Jason Williams
Problem Solving
Module 4.4 geometry

1.) You have to solve for C. A = 3 m and B = 4 m. To do this you would need the formula A^2 + B ^2 = C^2. So you have 3^2 +4^2 = C^2. So you have 9+16 = C^2. So you now have 25 = C^2. Then you square root each side to get rid of the squared part. C = 5 2.) To find this you must some up the sides and the widths times 2. Prect = 2l +2w. L is 2.5m and width is 10m. (5.0*2)= 10.0m (20*2) = 40m So Prect = 50.0m 3.) You use the area formula of a circle. Acir = ( pi)r^2. D = 4M to find radius you take the diameter and divide it by 2 so radius is 2. Pi is 3.141 or 22/7. Acir = (3.141)2^2 = Area. (3.141)4 = area. Area= 12.564. or 12.571 if you use 22/7 4.) We need to find the volume of a sphere radius is 5 m. your formula is Vsph =(4/3)(pi)r^3. So you take (4/3)(3.141)5^3 or (4/3)(22/7)5^3. V = 420.59 or V = 420.839 5.) We need to find the length of the rectangular prism. Volume is 144 m^3. Width is 2 m. Height is 6 m. your formula would be L = V/H*W So L = 144/2*6 L= 144/12 So L = 12 6.) Find area of triangle. A = 3M B = 4M. Your formula is Atri = (1/2)bh. So Atri = (1/2)4*3. Atri = 2*3. Area =6 7.) You need to find the length of the hypotenuse. Y = 6m and the area is 36m^2. Your formula is 8.) Find the volume of a cylinder your radius is 3m height is 10m. the formula is Vcyl = (pi)r^2h. So it’s (3.141)3^2*10 or (22/7)3^2*10. First one is 28.269*10 V = 282.69 or 28.28*10 = V = 282.85 9.) A sphere would have more 4 units and the radius is 3 the formula for volume in a cube is A^3=V so you take 4^3 = 80.342. a sphere is (4/3)(pi)r^3. So you have (4/3)(22/7)3^3 = 4.190etc *3^3 V= 252.50etc
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