Free Essay

Lab Report 6

In:

Submitted By jjccrizi
Words 1066
Pages 5
Digital Logic and Computer Lab EEL3701L Lab #8 1 Minute Clock UWF ECE Due: 09 July 2014

Abstract:

The purpose of the lab was to learn how to use data sheets and information given in them to design and create a one minute clock.

Introduction/Background/Theory:

When designing and creating things sometimes the materials needed are not always readily available to use, for example a function wave generator to generate the clock input needed for the flip flops. In this lab the 555 timer will be used to supply the clocking mechanism that is needed. Looking at the data sheets and reading them is very helpful in understanding what it is that is given, from there arrangements to the design can be made to make what is needed using the supplied materials. In the 555 timer:

Figure 1: 555 timer schematics info.

Reading the data sheet schematic for the 555 timer, equations are given to calculate the frequency. In this way one can calculate how fast the pulse is generated and supplied as a clock. From the equations the frequency can be set by changing the values of the resistors and capacitors. Another important part

of the lab is the counter chip. The 74LS163 is a 4-­‐bit binary counter which counts from 0-­‐15 or (0000 to 1111). Using two of these chips one can make a timer, one counter that counts up to 9 (the ones place) and one timer that counts up to 5 (the tens place).

Figure 2: Counter chip diagram

In the counter chip diagram, pins 3,4,5,6 are set to low, that is these pins are the input on which number to start.( i.e. starting at all pins set to low starts at 0 0 0 0 Which starts at 0, or all pins set at high, the count will start at 1 1 1 1, or 15.) pin 2 is the clock, which is supplied by the 555 timer in this case, or a function wave generator. Pin 1 is the clear, when clear = 0, the outputs will go to 0000 at the next clock input. Pin 9 is the load, when load=0 the output will be what the input to A, B, C, D is at the next clock input. Pins 7, 10 are the enable pins, these pins allow the 163 to count. In order for the counter to increment, load, clear, p and t have to be set to 1. If load and clear=1 and either p or t are set to 0, the clock will hold. Pins 11,12,13,14 are the outputs of the chip this outputs the next number in the sequence. Pin 15 is the ripple carry output if overflow occurs. Pin 8 is ground and pin 16 is power.

Procedure:

1. Using the 555 timer and the counter 74LS163, and 74LS47 BCD to 7 segment display decoders, design and build a one minute clock. 2. the timer will provide the clock inputs, the counter will count, and the BCD will provide the outputs to the 7 segment display. 3. a dipswitch is also going to be needed to be able to reset the timer to 0 0 whenever wanted.

Discussions:

1. Read thru the data sheets for the 555 timer. It is a very versatile chip. List at least 3 other functions that the chip can be configured to perform, and briefly describe what each of those functions do/are for. -­‐Monostable operator where a trigger is used and the timer works as a one-­‐shot function, can also act as a frequency divider that can be generated using a divide by 3 circuit. Lastly it can also act as a pulse position modulator where the pulse can be varies with the modulating signal. 2. What is the difference between a synchronous and an asynchronous input to your counters? -­‐synchronous transmissions are synchronized by a clock, as in asynchronous transmission are synchronized by other means not using a clock.

3. If you were to add a minute digit to your clock, how and when would you clock it? -­‐a minute clock would go up to 9 and then would need another display to display a tens minute place. It would clock after the reset of 5 and 9, as those reset the counter would clock and add a 1 to the one minute digit. 4. Discuss, in detail, how you configured the 555 timer to get the proper frequency. After using the equations on the data sheet, did you have to make any adjustments to get you frequency closer to the value you were looking for?

What happened to the resulting frequency after you plugged the 555 clock signal into your circuit (ie, after you loaded down the output of your 555 timer)? -­‐I used my resources and found a calculator online that would help calculate the values of the frequency depending on the capacitor and resistors that I used. As the output was loaded the frequency sped up some but not enough to be significant. 5. Create your own experiment: What does the effect of loading the output of your 555 timer have on the frequency it generates? Use different load values. Also test the results as you vary Ra, Rb, and C (i.e., what happens to the frequency if you raise and lower Ra, Rb, and C individually?). Since you are dealing with 3 values (Ra, Rb, and C) to set the frequencies, there are many different sets of values that will give you the same frequency. Experiment to find out whether or not it is best to use large values of resistors or smaller values. Don’t forget to include a load. Include a table showing the various resistor values that you used and the resulting frequency that they generated.

Conclusion: This lab was to create a one minute counter demonstrated the use of the 555 timer and the 163 chip. It also showed the importance of the data sheets in the information that is given in them. This helped create timer that helped supply the function wave needed instead of having a wave generator, made the designer be resourceful in designing a design with materials that didn’t exactly gave the designer what was needed.

Pre-­‐lab:

Figure 3: logic works design for the one minute clock with reset dipswitch

Similar Documents

Free Essay

Lab Report Instructions

...London School of Engineering and Materials Science Laboratory report writing instructions DEN101 - Fluid Mechanics 1 Flow Rate Measurement Experiment A. Student Student Number: 1234567 Version 2.0, 27 November 2010 Template for Word 97-2003 Abstract This document explains what is expected in your Fluids 1 lab report. The sections that should be covered are outlined and a structure you could follow is proposed. Detailed advice on how to edit the report is given. The document concludes with the marking criteria for this lab report. Table of Contents Abstract 2 1. Introduction 3 1.1. Writing 3 1.2. Editing and formatting 3 1.3. Content of the introduction 4 2. Background and theory 4 3. Apparatus 4 4. Test 4 5. Experimental procedure 4 6. Results 5 7. Discussion 5 8. Conclusions 5 9. References 5 10. Appendix A: Marking criteria 6 Introduction Before starting to write a report, you should think about what is your audience. Am I writing for colleagues who want a lot of detail how it is done, or am I writing for my boss who just wants an executive summary as he has no time for details? In general, there is not a single type of audience and we have to make our writing suitable for the detailed read, as well as the fast perusal. To understand what is required from you in this report, please have a look at the marking criteria in the Appendix. 1 Writing To limit...

Words: 2017 - Pages: 9

Premium Essay

Nt1310 Unit 6 Lab Report

...For the first round of the stimulation was random mating. After the 20 students drew out two new cards from starting genotype, the new genetic pool had five pairs of dominant homozygous, ten pairs of heterozygous, and five pairs of recessive homozygous. The new generation had the same number of the starting gene pool of the known allele frequency. Random selection frequency of alleles does not change over time, due to which all individuals have an equal chance of being selected. The Hardy-Weinberg equilibrium equation, p2 + 2pq + q2 = 1, is used to define a population in which to understand both allele and genotype frequencies. The equation only occurs when mating is at random on a large population, and the relative genotype and allele frequencies persist in being constant. In all possible combination defined by the Punnett square, 60% or 0.6 of the gene pool is the A allele, and 40% or 0.4 of the a allele, totaling in for 100%. When adding the probability, the results are 0.36 for AA, 0.24 for aA, 0.24 for Aa, and 0.16 aa. In total, will equal 1. The AA homozygotes will have the frequency of p2, and similarly, aa homozygotes will have the frequency of q2 when the population is in equilibrium. Then lastly, the Aa heterozygotes will have the relative genotype frequency of 2pq. The calculation would remain the same throughout generations, but only with random mating. The Hardy-Weinberg equilibrium will not equal 1 when it is disturbed by nonrandom mating, mutations, migration, and...

Words: 754 - Pages: 4

Premium Essay

Nt1330 Unit 6 Lab Report

...1 2 3 4 5 6 7 8 9 10 11 angular.module("MyApp", []) .controller("MyCtrl",["$scope", "$timeout", function($scope, $timeout) { $scope.colors = ["white","purple","pink"]; $scope.$watchCollection("colors", function(newList, oldList) { console.log("new list: " + newList); console.log("old list: " + oldList); }); $timeout(function() { $scope.colors.push("gray"); }, 2000); }]); $watchGroup $watchGroup function is introduced in Angular1.3. It works same as $watch() function but it accept an array of expressions as the first parameter instead of single expression.. 1 $watchGroup(watchExpression, listener) The listener is passed as an array with the new and old values for the watched variables. The listener is called whenever any expression in the watchExpressions array changes. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 angular.module("MyApp", []) .controller("MyCtrl",["$scope", "$timeout", function($scope, $timeout) { $scope.message1 = "First Message!"; $scope.message2 = "Second...

Words: 465 - Pages: 2

Premium Essay

Nt1310 Unit 6 Lab Report

...only a small amount of power. Step 3. Traffic density metric • Select the path that is lightly loaded from the three selected paths Algorithm 1.1 Algorithm for broadcasting RReq 1.2. Algorithm for node failures reduction Step1: Source broadcasts Route Request packets which are heard by neighbor nodes within the coverage area. Step 2: all node those get the RReq will calculate their remaining battery power by using: Rp = Einitial - Eci Step 3: Also all nodes will calculate their transition power needed to transmit the RReq packet to next-hop by using the following formula: Step 4: Check that they have enough power for transmitting the packet to next-hop. Step 5: The neighboring nodes re-broadcast the route request. Step 6: The destination will select all available path that has enough power 1.3. Algorithm for reducing traffic density Step 1: once all the path those have enough power have been selected the destination nodes can count the number of hop for all the available paths and order them based on the shortest path first. Step 2: The destination node will select the path that is lightly loaded from the ordered list. Step 3: The destination will send the RRep to the source node through the selected path. Step 4: The destination sends Route Reply only to the first received Route Request. ...

Words: 571 - Pages: 3

Premium Essay

Nt1310 Unit 6 Lab Report

...Adedamola Iyiola M.E. LAB: Lab View Section 06   Lab View Adedamola Iyiola Department of Mechanical and Aerospace Engineering Rutgers University, Piscataway, New Jersey 08854 A Data acquisition board, thermocouple and a BNC terminal block were used simultaneously with Lab view to obtain measurements of different waveforms with varying frequencies of 500, 100, and 3000 Hz. Additionally, we varied sampling rates, at an input of 1000 Hz, at 500 Hz and 2500 Hz (0.5x and 2.5x the input wave frequency). Furthermore for the second set of measurements, we obtained data from running a thermocouple data acquisition program. We acquired temperature measurements of a room for a period of 60 seconds and an individual’s finger for 50 seconds....

Words: 1259 - Pages: 6

Premium Essay

Nt1310 Unit 6 Lab Report

...Probability of getting no more than 0 heads: 0.0625 Probability of getting no more than 1 head: 0.3125 Probability of getting no more than 2 heads: 0.6875 Probability of getting no more than 3 heads: 0.9375 Probability of getting no more than 4 heads: 1.000 4. True 5. > pbinom(1, size=3, prob=.5) [1] 0.5 6. > round(pbinom(3, size=5, prob=.5), 2) [1] 0.81 7. > lmb expectation expectation [1] 0.25 or 15 seconds 8. The answer is .06 for minutes or 225 for seconds. 9. > round(pexp(15.5/60, rate=4), 2) # using minutes [1] 0.64 10. > pexp(40.2/60, rate=4) - pexp(10.7/60, rate=4) [1] 0.421445 11. > round(qexp(.95, rate=4), 2) # minutes [1] 0.75 > round(qexp(.95, rate=4/60), 2) # seconds [1] 44.94 12. The R command pexp(1.2, rate=3) shows the estimated probability of randomly selecting a value less than or equal to 1.2 from an exponential distribution that has a rate of 3. 13. > round(1 - pnorm(9, mean=7, sd=3),...

Words: 358 - Pages: 2

Premium Essay

Pt1420 Unit 6 Lab Report

...Row 1 1 1x22 1(odd) Row 2 1+2 2x32 3 (odd) Row 3 1+2+3 3x42 6 (even) Row 4 1+2+3+4 4x52 10 (even) Row 5 1+2+3+4+5 10x112 15 (odd) Row n 1+2…+n n(n+1)2 n/a A pattern I noticed when filling in the table was how the answer to the 2nd column increase in order. (The difference between each answer is - 1,2,3,4,5). I can predict last column is always going to be equal to the 2nd column. Another prediction I could explore how the last column has 2 even and 2 odd numbers. Row 6: 1+2+3+4+5+6 = 6x7 ÷ 2 = 21 (odd) Row 7: 1+2+3+4+5+6+7 = 7x8 ÷ 2 = 28 (even) Row 8: 1+2+3+4+5+6+7+8 = 8x9 ÷ 2 = 36 (even) This shows how the 2 odd & 2 even method continues throughout the sequence, this would be correct as the numbers from the last column (1,3,6,10,15,21,28,36…)...

Words: 406 - Pages: 2

Premium Essay

Nt1310 Unit 6 Lab Report

...CHAPTER-6 EXPERIMENTAL SETUP AND RESULTS This chapter provides an overview of network simulation and different VANET simulators that can be used to simulate different VANET algorithms to analyze the performance of the network without the need of real systems. This not only saves cost but also provides opportunity to test new protocols and algorithms in a controlled environment which otherwise would have not been possible. 6.I INTRODUCTION A network simulator is a software program that models the working of a computer network and its communications. It can be a software or hardware that helps to predict the behavior of a network, without need of any actual network. It imitates the working of a network such that the performance of the network can be analyzed without...

Words: 673 - Pages: 3

Premium Essay

Nt1310 Unit 6 Lab Report

...CHAPTER-6 EXPERIMENT RESULT 6.1 System Model For experimental purposes we assume that total 5000 jobs will be scheduled on the grid consists of 7 clusters. In general, each resource/cluster contains 80 computing nodes (Machines), and each computing node contains 1 Processing Elements (PE). The processors of computing nodes in different resources have same processing power (i.e. 1GHz). Every computing node consist RAM of 53GB approx. Network speeds among the computing node are also assumed same for different resources. The characteristics of 7resources used in our experiment, shown in Table 6.1. Parameter Name Value Total Number of Jobs 5000 Number of Cluster 07 Number of CPU per Cluster 80 RAM 53 GB Baud Rate 10000 CPU Speed 1GHz...

Words: 852 - Pages: 4

Premium Essay

Nt1310 Unit 6 Lab Report

...Katie Carroll Mr. Miller APP1 November 15, 2015 1. Background a. Equations: i. Σ F = T-mhg = mha ii. fk=ukN 2. Materials a. Before assembling the materials, prepare a clean, dry workspace (away from food) with all necessary materials. i. Wooden board that can be adjusted to various angles ii. Spring scale iii. Wooden block (with tape on one side) iv. Pulley v. Paperclips (weights) vi. Safety goggles 3. Procedure a. (Part 1)-determine kinetic friction between the wooden block and the wooden board b. Read through the entire procedure and prepare to carefully collect your data before you begin. c. Before assembling the materials, prepare a clean, dry workspace (away from food) with all necessary materials. d. Weigh and record the mass of the wooden block. e. Make sure the surfaced of the wooden plank and the block are clean of dirt so that nothing will disrupt the experimental friction coefficient. f. Put the wooden block (with tape side down) on the end of the wooden board and attach the string to the block. Then attach the spring scale to the other end of the pulley so that it hangs over the far end of the wooden board. g. Put mass on the spring scale and start the block with a small push. i. If the wooden block speeds up, take some of the mass off. ii. If the wooden block slows down, add more mass. iii. Once the block moves across the whole wooden board with a constant speed, record the total hanging mass and its weight. h. (Part 2)- Determine the difference surface area...

Words: 472 - Pages: 2

Premium Essay

Pt1420 Unit 6 Lab Report

...all of the alleles are dominant. Also, punnett squares 3 and 4 have a 100% probability because they both have at least two dominant alleles in the proper allele cross to result in a dominant allele in every box. All of these boxes have a dominant gene, and even though there are recessive genes present, they do not show because of the dominant allele. In punnett square 2, there is 75% chance for the dominant traits. This is because on box in the square is homozygous recessive, meaning there is no dominant gene present to show, and is the only form that the recessive gene will show in the phenotype. Lastly, punnett square 5, has a 50% probability of receiving the dominant trait. On the other hand, for the recessive phenotype, punnett square 6 has a 100% chance. This is because all alleles present are recessive, and to show a dominant trait, there needs to be a dominant allele present. Furthermore, square 7 has a 50% chance of showing the recessive allele. That is because a dominant ia also present, which is the more authoritative allele. Lastly, punnett square 8 shows a 25% probability for the recessive trait. This is because there are 2 dominant alleles which overpower the recessive alleles. These punnett squares support the original hypothesis because when 1 or more dominant alleles are present, the probability of the recessive trait as the phenotype is...

Words: 1077 - Pages: 5

Premium Essay

Nt1310 Unit 6 Lab Report

...The attractive force between the positive charge in the nucleus and the valence electrons decreases because these electrons are farther from the nucleus. 4. a) The elements that are found at the main peaks of my graph are Lithium, Sodium, Potassium, and Rubidium. These elements are all found in the same group. They are all Alkali Metals. b) The elements that are found at the main valleys of my graph are Neon, Argon, Krypton, and Helium. These elements are all found in the same group. They are all part of the Noble Gases. 5. I predict Rubidium would be the largest atom in the atomic table because it has an atomic radius of 248pm. I predict the smallest atom in the atomic table would be Hydrogen because it has an atomic radius of 32pm. 6. There is a significant jump in the size of the nucleus (protons + neutrons) each time you move from period to period down a group. Additionally, new energy levels of elections are added to the atom as you move from period to period down a group, making the each atom significantly more massive, both is mass and volume. This makes the atomic radii bigger. Part 2 – Ionization Energy 7. The ionization energy is the exact quantity of energy that it takes to remove the outermost electron from the atom. 9. a) The elements that are found at the main peaks of my graph are Helium, Neon, Argon, and Krypton. These elements are all found in the same group. They are all part of the Noble Gases. b) The elements that are found at the main valleys of my...

Words: 1431 - Pages: 6

Premium Essay

Nt1310 Unit 6 Lab Report

...This results in a value of (1.4 ± 0.4)s. This period can then be used to find the undamped oscillation frequency through the formula for frequency. rad/s. Uncertainty for this can be found by the following steps plugging in the appropriate values in this equation: rad/s. = (4.4880 ± 1.2823) rad/s The value of damping time was (2.5698 ± 0.1404)s. This was calculated by taking the natural log of the each ratio, the dividing the period by this value and multiplying by -1, then averaging all the values found. Uncertainty was calculated with standard deviation, in which the difference between each data point and the average was found. Then the differences were all squared, added together and then divided by the number of data points (which was 6 in this case). The recorded measurement for the driven resonant frequency we found through adjusting Lissajous plots was (4.430 ± 0.031)Hz. This was found by finding the frequency, 0.705 ±0.031 Hz, in which the Lissajous plotted by the output voltage and angle was most symmetric and did not lean to either side. This value was multiplied by 2 pi and yielded 4.430 Hz. The uncertainty of the frequency was found by seeing how much of the frequency had to change before seeing a difference in the Lissajous plots, which was 0.005Hz. The uncertainty for the driven resonant frequency was found through this formula . This value of the driven resonant frequency and the damping time can be then used to calculate a measured value of Q by the following...

Words: 1446 - Pages: 6

Premium Essay

Pm3110 Unit 6 Lab Report

... Figure 4.21 shows the magnetic hysteresis loop of CoFe2-xZnxO4 powders at room temperature, with a maximum applied field of up to 8 kOe. The saturated magnetization, remanence and coercivity are summarized in Table 4.10. Also, Figure 4.22 presented variations of saturated magnetization and coercivities for CoFe2-xZnxO4 powders as a function of compositions calcined at 900 ºC for 48 h. The magnetization value of doped samples increased sharply with the external magnetic field strength at the low field region. The highest saturated magnetization can be obtained in x = 0.1 Zn doped cobalt ferrites. Increasing in saturated magnetization can be attributed to influence of the cationic stoichiometry and its occupancy in specific sites. The magnetic order in the cubic system of ferromagnetic spinels was due to occurrence of the super-exchange interaction mechanism between metal ions in the tetrahedral A-site and octahedral B-site [20]. When the nonmagnetic zinc ion was substituted by the cobalt ferrite lattice, due to the zinc ferrite being a normal spinel, it had a stronger preference for the tetrahedral site and thus reduced the amount of Fe3+ in the A site. The net result, due to antiferromagnetic coupling, was an increase in magnetic moment on the B lattice and an increase in saturated magnetization. However, at high levels of zinc substitution in x > 0.1, the A-site magnetic ion becomes so diluted that coupling between the two lattices was lost, and the saturated magnetization drops...

Words: 344 - Pages: 2

Free Essay

Netw 202 Week 6 Lab Report Latest

...NETW 202 WEEK 6 LAB REPORT LATEST To Purchase this tutorial visit following link http://wiseamerican.us/product/netw-202-week-6-lab-report-latest/ Contact us at: SUPPORT@WISEAMERICAN.US NETW 202 WEEK 6 LAB REPORT LATEST SECTION I: Computing Usable Subnets and Hosts SECTION II: Calculating Subnet Masks Lab NETW 202 WEEK 6 LAB REPORT LATEST SECTION I: Computing Usable Subnets and Hosts SECTION II: Calculating Subnet Masks Lab NETW 202 WEEK 6 LAB REPORT LATEST SECTION I: Computing Usable Subnets and Hosts SECTION II: Calculating Subnet Masks Lab NETW 202 WEEK 6 LAB REPORT LATEST SECTION I: Computing Usable Subnets and Hosts SECTION II: Calculating Subnet Masks Lab NETW 202 WEEK 6 LAB REPORT LATEST SECTION I: Computing Usable Subnets and Hosts SECTION II: Calculating Subnet Masks Lab NETW 202 WEEK 6 LAB REPORT LATEST SECTION I: Computing Usable Subnets and Hosts SECTION II: Calculating Subnet Masks Lab NETW 202 WEEK 6 LAB REPORT LATEST SECTION I: Computing Usable Subnets and Hosts SECTION II: Calculating Subnet Masks Lab NETW 202 WEEK 6 LAB REPORT LATEST SECTION I: Computing Usable Subnets and Hosts SECTION II: Calculating Subnet Masks Lab NETW 202 WEEK 6 LAB REPORT LATEST SECTION I: Computing Usable Subnets and Hosts SECTION II: Calculating Subnet Masks Lab NETW 202 WEEK 6 LAB REPORT LATEST SECTION I: Computing Usable Subnets and Hosts SECTION II: Calculating Subnet Masks Lab NETW 202 WEEK 6 LAB REPORT LATEST SECTION I: Computing Usable Subnets...

Words: 491 - Pages: 2