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Moving Average Method

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Moving Average Method

Example-1: ABC Company has the following manpower data for their health care division for the past six years:
|Year |Manpower level/Data |
| |(in nos.) |
|2003 |500 |
|2004 |600 |
|2005 |800 |
|2006 |1,000 |
|2007 |1,100 |
|2008 |1,300 |

You have been asked to forecast their manpower requirement in 2009 using a 6-period moving average.
Answer:

F 2009 = (500+600+800+1000+1100+1300) /6 = 5300/ 6 = 883 (Ans:)

Weighted Moving Average Method

Example-2:

|Year |Manpower level/Data |
| |(in nos.) |
|2003 |500 |
|2004 |600 |
|2005 |800 |
|2006 |1,000 |
|2007 |1,100 |
|2008 |1,300 |

For example, manpower levels of 2003, 2004, 2005 may be less relevant, hence, for these years weights may be assigned as 1 each. For 2006, weight may be 2, for 2007 weight may be 3, while for 2008, weight may be 4. Determine the forecasted manpower for the year 2009.

Answer:

F 2009 = (1(500)+1(600)+1(800)+2(1000)+3(1100)+4(1300) /∑W = (500+600+800+2000+3300+5200) /12 = 1033 (Ans:)

N:B: When not mention the year then divided by 1

Example-4: Assume that the forecasted manpower requirement for an organization was 500, while their actual requirement was 480. Considering an alpha value of 0.4, compute the manpower requirement for the current period.

Answer:

|Ft = a (A) + (1-a) (F) |a = Alpha Value |
|= .4 (480) + (1-.4) (500) = 492 |A = Actual |
| |F= Previous/First |

Ft = a (A) + (1-a) (F)

= .4 (480) + (1-.4) (500) = 492 (Ans:)

Determination of Quarterly Forecast:

The following quarterly data represent a demand time series for manpower needs of a company:

| | Q |U A |R T | E R |
|YEAR |1 |2 |3 |4 |
|Last year |1,200 |700 |900 |1,100 |
|This year |1,400 |1,000 |F3 =? | |

Forecast the demand for the third quarter of this year. Assume that α = 0.2 and the previous forecast is constructed from the average for the four quarters of last year.

Answer:

Fo = (1200+700+900+1100)/4 = 3900/4 = 975

F1 = .2 (1100) + .8 (975) = 220+780 =1000

F2 = .2 (1400) + .8 (1000) = 280+800 =1080

F3 = .2 (1000) + .8 (1080) = 200+864 =1064 (Ans:)

Example-8.4: As HR planning manager for Bexter Company Ltd., you have an important task to fulfill. To continue the company's history of successful growth, you need to forecast the number of marketing personnel required for Tk 8 million and Tk 10 million of sales activity. You have the following historical information available to guide your regression analysis and HR demand forecast:

|X |Y |
|Sales Level |Number of |
|(Tk million) |Marketing Personnel |
|2.0 |20 |
|3.5 |32 |
|4.5 |42 |
|6.0 |55 |
|7.0 |66 |

Answer:

|Sales X |No of people Y |XY |X² |
|2.0 |20 |40 |4.0 |
|3.5 |32 |112 |12.25 |
|4.5 |42 |189 |20.25 |
|6.0 |55 |330 |36.00 |
|7.0 |66 |462 |49.00 |
| ∑X=23.0 | ∑Y=215 | ∑XY=1133 | ∑ X²=121.50 |

[pic]= 23/5 = 4.6
Ỳ = 215/5 = 43

| ∑XY – N([pic])(Ỳ) | 1133-5×4.6×43 | 1133-989 | 144 | |
|B = --------------------- |= --------------------- |= -------------------- |= ---------------- |= 9.17 (Ans:) |
|∑(X2) – N([pic])2 |121.50-5-(4.6)² |121.50-5×21.16 |121.50-105.8 | |

A = Ỳ - B[pic] = 43-9.17×4.6 = 0.82

Y = A + BX = 0.82+9.17 X

➢ For 8 million of sales (X=8)

Y = 0.82+9.17 x 8 =74 People will be needed.

➢ For 10 million of sales (X=10)

Y = 0.82+9.17 x 10 =93 People will be needed.

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