...Unit 1 Assignment 1: Integrated Circuit Technology Processor | Transistor count | Date of introduction | Manufacturer | Process | Intel 4004 | 2,300 | 1971 | Intel | 10 µm | Intel 8008 | 3,500 | 1972 | Intel | 10 µm | Intel 8080 | 4,500 | 1974 | Intel | 6 μm | Intel 8085 | 6,500 | 1976 | Intel | 3 μm | Intel 8086 | 29,000 | 1978 | Intel | 3 μm | Intel 8088 | 29,000 | 1979 | Intel | 3 μm | Intel 80186 | 55,000 | 1982 | Intel | 3 μm | Intel 80286 | 134,000 | 1982 | Intel | 1.5 µm | Intel 80386 | 275,000 | 1985 | Intel | 1.5 µm | Intel i960 | 250,000 | 1988 | Intel | 0.6 µm | Intel 80486 | 1,180,235 | 1989 | Intel | 1 µm | Pentium | 3,100,000 | 1993 | Intel | 0.8 µm | Pentium Pro | 5,500,000 | 1995 | Intel | 0.5 µm | Pentium II Klamath | 7,500,000 | 1997 | Intel | 0.35 µm | Pentium II Deschutes | 7,500,000 | 1998 | Intel | 0.25 µm | Pentium III Katmai | 9,500,000 | 1999 | Intel | 0.25 µm | Pentium III Coppermine | 21,000,000 | 2000 | Intel | 180 nm | Pentium III Tualatin | 45,000,000 | 2001 | Intel | 130 nm | Pentium 4 Willamette | 42,000,000 | 2000 | Intel | 180 nm | Pentium 4 Northwood | 55,000,000 | 2002 | Intel | 130 nm | Pentium 4 Prescott | 112,000,000 | 2004 | Intel | 90 nm | Pentium 4 Prescott-2M | 169,000,000 | 2005 | Intel | 90 nm | Pentium 4 Cedar Mill | 184,000,000 | 2006 | Intel | 65 nm | Atom | 47,000,000 | 2008 | Intel | 45 nm | Itanium 2 McKinley | 220,000,000 | 2002 | Intel | 180 nm | Core 2 Duo Conroe | 291...
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...A port expander is a hardware device that will allow users to utilize multiple devices on a single port at the same time. It is the same principle as using a power strip for the power in a home or a splitter for the cable. For example, if you only have 1 Universal Serial Bus (USB) port, yet you have a USB mouse and keyboard, then you can use a USB port expander to allow one port slot to become multiple ports and plug in the mouse and keyboard. Allowing multiple devices to be able to connect to a single port is a major advantage to port expanders. However, one of the biggest drawbacks is that the speed of that port is now divided throughout all the expansion ports, an example being a 3Gbps port expanded to accommodate 4 ports will now have to split that 3Gbps between all 4 ports and not 3Gbps per expansion slot. There are two types of port expanders: internal and external. An internal port expander will usually connect to the motherboard and have an expansion plate with multiple ports along the box of the computer. An external port expander will plug into an existing port (such as a USB) and will then have multiple connections off of the port expander. Port expanders are also very generic and will allow expansion on just about any computer. There are many ports available that come with port expansion hardware. Some examples are, but are not limited to, USB Port Expander Hardware, Microphone Port Expander Hardware, FireWire Port Expander Hardware, Serial Port Expander...
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...Fredrick Donaldson Nov.5, 2014 NT1110 Unit 5 Assignment 1 Video Summary 3 CPUs In today’s market there are 2 main manufacturers of CPUs: Intel and AMD. There are also some smaller competitors that manufacture CPUs, but they tend to come and go. The way a CPU is organized varies, but here are the basics: The motherboard system bus carries information into and out of the CPU. When the system bus enters the CPU, it’s called a Front side bus. The Front side bus usually uses a 64-bit wide data path. On the side of the CPU you will find a controller. A controller manages the basic functions of the CPU, and controls communication between the motherboard and other components within the CPU. These other components includes one or more ALUs and internal cache. An ALU (Arithmetic Logic Unit), is responsible for solving complex calculations. Having multiple ALUs in a single processor is what gave the early Pentiums their multi-processing capabilities. Communication between the controllers and the ALU uses a 32-bit wide internal data bus. The bus system that supports communication between the cache, the ALU, and the controllers is referred to as the backside bus. The most important thing a person needs to know about a processor is the speed at which it processes information; (CPU speed). There are several ways to gauge CPU speeds. This may sound like an advantage, but oftentimes, these multiple ways are misleading. The speeds differ inside and outside the processor. Internally...
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...Corey Young Monday The first part of this video was talking about the history of the operating systems. The Microsoft OS were DOS that had a GUI interface, after that you had NT, 9x, 2000, XP, Vista which in my opinion was terrible, server 2003 and 2008. There are also other OS that have been out Unix and Linux is what Macintosh are built from and then you also have Mac OS X. Video 3.02 was talking about installing new hard ware, creating partitions and formatting partitions, and installing OS systems. Before you install an OS system after installing a new hard drive you need to create and format a partition which will be an c partitions. There are two types of partitions which are primary and extended. You can only create one of each with the FAT file system. The NTFS you can create four primary partitions or three primaries and one extended. In creating partitions you need to know the order they are created and deleted. The orders to create partitions are first primary then extended and logical. To delete a partition you will simple reverse the order. Video 3.03 is about comparing active, system and boot partitions. After creating partitions you need to mark one active which usually contains the boot file so you can start up the OS. The system and the boot partitions are part of this system. The system partitions contain boot files which contains the operating system which boots up the OS. The boot partition contains system files which contain the OS files. So the...
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...NT1110 Computer Structure and Logic STUDENT COPY STUDENT COPY The following sections contain student copies of the assignments that must be distributed to students at least two weeks prior to the due dates for those assignments. Online students will have access to those documents in PDF format available for downloading at any time during the course. © ITT Educational Services, Inc. All Rights Reserved. -87- Change Date: 08/25/2011 NT1110 Computer Structure and Logic STUDENT COPY: Graded Assignments Graded Assignment Requirements Assignment Requirements documents provided below must be printed and distributed to students as the guidance for completing the assignments and submitting them for grading. Instructors must remind students to retain all handouts and assignment documents issued in every U U unit, as well as student-prepared documentation and graded deliverables. Some or all these documents will be used repeatedly across different units. Unit 1 Assignment 1: Integrated Circuit Technology Learning Objectives and Outcomes This assignment addresses the course objective “Describe the components of a personal computer.” The expected learning outcomes that will result from completing the assignment are: You will be able to perform specific Internet searches for information. You will be able to illustrate the growth of the number of transistors available in integrated circuits used in computers. You...
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...Mr. Yang | NT1110 Computer Structure and Logic | Unit 3 Assignment 1: I/O Devices | | Jesus Gutierrez I/O Devices I/O devices enable us to control the computer and Information in a variety of ways. * What critical I/O devices are necessary to use a personal computer? Which ones are not necessary for normal day-to- day use and why? Necessary devices used on a personal computer keyboard, for typing or telling the computer what to do. Monitor, for seeing all the information you type in, watching videos ect… Speakers for listening music and watching videos. Now a days we often use USB ports for just about everything, storing information from one device to a desk top up to a laptop. Also charging our electric devices, as well as storing information into USB cards. Not necessary I/O for a personal computer can be printer, scanner, web cam. * Why a modem is considered an I/O device? The reason Is it sends and retrieves data usually at the same time. * Though a printer is an essential I/O device, can you think of why it may be also classified as an input device? If It is a combination of printer/fax/scanner it could be both. When it is printing it’s an output device. When scanning it is an input device. [Type the abstract of the document here. The abstract is typically a short summary of the contents...
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...Nt1110 Integrated Circuit Technology Jerick San Gabriel NT1110 Unit 1 Assignment 1: Integrated Circuit Technology 2.) Processor Model | Year | Transistor Count | Intel 4004 | 1971 | 2,300 | Intel 8008 | 1972 | 3,500 | Intel 8080 | 1974 | 4,500 | Intel 8085 | 1976 | 6,500 | Intel 8086 | 1978 | 29,000 | Intel 8088 | 1979 | 29,000 | Intel 80186 | 1982 | 55,000 | Intel 80286 | 1982 | 134,000 | Intel 80386 | 1985 | 275,000 | Intel 80486 | 1989 | 1,180,235 | Pentium | 1993 | 3,100,000 | Pentium Pro | 1995 | 5,500,000 | Pentium II | 1997 | 7,500,000 | Pentium III | 1999 | 9,500,000 | Pentium 4 | 2000 | 42,000,000 | Atom | 2008 | 47,000,000 | Itanium 2 McKinley | 2002 | 220,000,000 | Core 2 Duo | 2006 | 291,000,000 | Itanium 2 Madison 6M | 2003 | 410,000,000 | Itanium 2 with 9MB cache | 2004 | 592,000,000 | Core i7 (Quad) | 2008 | 731,000,000 | Quad-Core + GPU Core i7 | 2011 | 1,160,000,000 | Six-Core Core i7 (Gulf town) | 2010 | 1,170,000,000 | Quad-Core + GPU Core i7 | 2012 | 1,400,000,000 | Dual-Core Itanium 2 | 2006 | 1,700,000,000 | Six-Core Xeon 7400 | 2008 | 1,900,000,000 | Quad-Core Itanium Tukwila | 2010 | 2,000,000,000 | Six-Core Core i7/8- Core Xeon E5 | 2011 | 2,270,000,000 | 8-Core Xeon Nehalem-EX | 2010 | 2,300,000,000 | 10-Core Xeon West mere-EX | 2011 | 2,600,000,000 | 8-Core Itanium Poulson | 2012 | 3,100,000,000 | 62-Core Xeon Phi | 2012 | 5,000,000,000 | 3.) Quad-Core Itanium Tukwila, 2010, 2,000,000,000 4.) Anonymous....
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...examine processes and procedures involving the installation, configuration, maintanence, troublshooting and routine adminstrative tasks of popular desktop operating system(s) for standalone and network client computers, and related aspects of typical network server functions. Client-Server Networking I Syllabus Where Does This Course Belong? 1st QTR GS1140 NT1110 GS1145 Problem Solving Theory Computer Structure and Logic Strategies for the Technical Professional 2nd QTR NT1210 Introduction to Networking NT1230 Client-Server Networking I MA1210 College Mathematics I 3rd QTR NT1310 NT1330 MA1310 4th QTR PT1420 NT1430 EN1320 5th QTR PT2520 NT2580 EN1420 6th QTR NT2640 NT2670 CO2520 7th QTR NT2799 SP2750 Physical Networking Client-Server Networking II College Mathematics II Introduction to Programming Linux Networking Composition I Database Concepts Introduction to Information Security Composition II IP Networking Email and Web Services Communications Network Systems Administration Capstone Project Group Theory The follow diagram indicates how this course relates to other courses in the NSA program: 1 Date: 8/31/2012 Client-Server Networking I Syllabus NT2799 NSA Capstone Project NT2580 Introduction to Information Security NT2670 Email and Web Services NT2640 IP Networking PT2520 Database Concepts NT1330 Client-Server Networking II NT1230 Client-Server Networking I NT1430 Linux Networking PT1420...
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...Contact/Instructional hours: 56 (34 Theory Hours, 22 Lab Hours) Prerequisite(s) and/or Corequisite(s): Prerequisites: NT1110 Computer Structure and Logic or equivalent Course Description: This course serves as a foundation for the study of computer networking technologies. Concepts in data communications, such as signaling, coding and decoding, multiplexing, circuit switching and packet switching, OSI and TCP/IP models, LAN/WAN protocols, network devices and their functions, topologies and capabilities are discussed. Industry standards and the development of networking technologies are surveyed in conjunction with a basic awareness of software and hardware components used in typical networking and internetworking environments Introduction to Networking Syllabus Where Does This Course Belong? This course is required for the associate program in Network System Administration and the associate program in Electrical Engineering Technology. The following diagrams demonstrate how this course fits in each program. Associate Program in Network Systems Administration NT2799 NSA Capstone Project NT2580 Introduction to Information Security NT2670 Email and Web Services NT2640 IP Networking PT2520 Database Concepts NT1330 Client-Server Networking II NT1230 Client-Server Networking I NT1430 Linux Networking PT1420 Introduction to Programming NT1110 Computer Structure and Logic NT1210 Introduction to Networking NT1310 Physical Networking CO2520 Communications ...
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...Network Systems Administration and associate degree in Mobile Communications Technology. The following diagrams indicate how this course relates to other courses in respective programs: Network Systems Administration NT2799 NSA Capstone Project NT2580 Introduction to Information Security NT2670 Email and Web Services NT2640 IP Networking PT2520 Database Concepts NT1330 Client-Server Networking II NT1230 Client-Server Networking I NT1430 Linux Networking PT1420 Introduction to Programming NT1110 Computer Structure and Logic NT1201 Introduction to Networking NT1310 Physical Networking CO2520 Communications SP2750 Group Theories EN1420 Composition II EN1320 Composition I GS1140 Problem Solving Theory GS1145 Strategies for the Technical Professional MA1210 College Mathematics I MA1310 College Mathematics II Networking Technology Courses Programming Technology Courses General Education/ General Studies 1 Date: 7/18/2011 IP Networking Syllabus Mobile Communications Technology MC2799 MCT Capstone Project NT2640 IP Networking MC2560 Mobile Wireless Communication I MC2660 Mobile Wireless Communication II MC2665 Mobile...
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...Unit 1: Assignment 1: Intel Processor Transistor Count Kellie L NT1110 Intel Processor Transistor Count After researching through several websites and reading Chapter 1 about the “Intel Processor Transistor Count”, I was able to get a much better understanding of how “Moore’s Law” actually works. The graph table I found and made my on paper drawing of (gatotkacatulanglunak.wordpress.com) presents the processor model, the year that each model was created from 1971-2011, and the transistor count from 2,300-2,600,000,000. During late 2008- early 2009 the 65-nanometer Tukwila Itanium Processor was released. This processor could run at up to 2GHz, with “dual-integrated” memory controllers and use Intel’s “quick path” interconnect instead of a “front-side bus”. This processor had 2 billion transistors on one chip (Rob Shiveley, spokesman for Intel). Based on what I have learned from my reading assignment and the graph table I have found online showing “Moore’s Law” the growth of processor transistor counts from 1971- 2011 doubling every two years, sometime around the years 2019-2020 there will be a processor with 100 billion transistors on one chip. I also predict that not until the year 2026 will we have processors with up to 1 trillion transistors on one chip. Throughout the years graphed, the growth from 1971- now seems pretty reasonable, mainly because the growth is steadily growing. However, with the advanced technology we have today...
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...Unit 5 Assignment 1 Homework David Thompson NT1110 Oct/21/2013 1 Three reasons why overheating would occur in the CPU would be the result of having a lot of dust inside your computer, dirt buildup. Having a faulty fan. Another reason would be not enough air flow coming and coming into your computer. 2 Overclocking is to run a microprocessor faster than the speed for which it has been tested and approved. 3 Throttling process is a process responsible for regulating the rate at which application process scene is conducted either static we are dynamically 4 Thermal compound increases the thermal connectivity of a thermal interface five billion microscopic air gaps in imperfect flat smooth surfaces 5 Since the core or processor is a unit that reads and executes programs instructions, such as copy or move data. multiple cores can do multiple instructions at the same time increasing overall speed of the programs itself 6 Hyper threading is used to improve parallelization of computations or doing multiple tasks at once performed on the PCs microprocessor. It addresses two virtual or logic corps and shares the workload between them when possible the main function of hyper threading is to decrease the number of depending instructions to one core. 7 A cache is used to reduce the average time to access memory cache is a smaller faster memory which stores copies of the data from frequently used memory locations. There is instruction cache to...
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...Contact/Instructional hours: 56 (34 Theory Hours, 22 Lab Hours) Prerequisite(s) and/or Corequisite(s): Prerequisites: NT1110 Computer Structure and Logic or equivalent Course Description: This course serves as a foundation for the study of computer networking technologies. Concepts in data communications, such as signaling, coding and decoding, multiplexing, circuit switching and packet switching, OSI and TCP/IP models, LAN/WAN protocols, network devices and their functions, topologies and capabilities are discussed. Industry standards and the development of networking technologies are surveyed in conjunction with a basic awareness of software and hardware components used in typical networking and internetworking environments Introduction to Networking Syllabus Where Does This Course Belong? This course is required for the associate program in Network System Administration and the associate program in Electrical Engineering Technology. The following diagrams demonstrate how this course fits in each program. Associate Program in Network Systems Administration NT2799 NSA Capstone Project NT2580 Introduction to Information Security NT2670 Email and Web Services NT2640 IP Networking PT2520 Database Concepts NT1330 Client-Server Networking II NT1230 Client-Server Networking I NT1430 Linux Networking PT1420 Introduction to Programming NT1110 Computer Structure and Logic NT1210 Introduction to Networking NT1310 Physical Networking CO2520 Communications ...
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...Rymon Abdulmalek NT1110 07/03/2014 Mr. Mohamed Khan Unit 1 Assignment 1. Processor Model | Year | Transistor Count | Intel 4004 | 1971 | 2,300 Transistors | Intel 80286 | 1982 | 134,000 Transistors | Pentium III | 1999 | 9,500,000 Transistors | Core 2 Duo | 2006 | 291,000,000 Transistors | 8-Core Itanium Poulson | 2012 | 3,100,000,000 Transistors | In February 2008, Intel has announced the first microchip that contains more than two billion transistors. They called it Tukwila chip. The chip is designed for high-end servers rather than personal computers. Many of the chip´s two billion transistors are used for on-board memory, helping the system process data faster. The growth of the transistors used in the circuits has nearly doubled every two years. This growth is reasonable because it falls in line with Moore’s law (Founder of Intel). Moore stated that the amount of transistors on a chop would be doubled every 18 months to two years which is surprisingly fast. According to Moore’s law which says that the amount of the transistors will be doubled every 18 months to 2 years, I would say that the chip that will contain more than 100 Billion transistors will be in 2022. Which they might invent a chip that contains 192,000,000,000 billion transistors. References: -The processor model and year when two billion transistors were placed on a single processor chip information was retrieved from http://www.computerworld.com/s/article/9060900/Intel_squeezes_2_billion_transistors_onto_new_Itanium_chip...
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...NT1110 Unit 2 Assignment 1: Transfer Time – Step by step processRef: http://www.t1shopper.com/tools/calculate/downloadcalculator.phphttp://luckylarry.co.uk/programming-tutorials/how-to-calculate-data-transfer-speeds/Formula: Transfer Time = File Size / Transfer Rate 1.For file size - > Convert all KBytes to bytes (x 1024) and then to bits (x 8) 1.e.g. 2GB = 2 * 1024 * 1024 * 1024 * 8 bits = 17,179,869,184 bits2.For transfer rate -> convert to bits ( x 1000) 1.E.g. 56 Kbps = 56 * 1000 bps = 56,000 bpsProblem: Calculate Transfer timeFile SizeTransfer RateTransfer Time2 GB56 Kbps?Solution:Formula: Transfer Time = File Size / Transfer Rate Step 1: Convert file size to bytes. (Multiply by 1024 to get to GB -> MB -> KB -> bytes). 2 GB x 1024 = 2048 MB= 2048 * 1024 = 2097152 KB= 2097152 * 1024 = 2147483648 bytesStep 2: Covert file size from bytes to bits. (Multiply by 8).2147483648 * 8 = 17,179,869,184 bitsYou can combine Steps 1 and 2 by doing it in one step: 2 * 1024 * 1024 * 1024 * 8 (will give file size in bits)Step 3: Covert transfer rate to bits per sec. (Multiply by 1000).56 Kbps * 1000 = 56,000 bpsStep 4: Divide Step 2 result by Step 3 result to get transfer time in seconds.17,179,869,184 / 56,000 = 306,783.3783 secondsStep 5: Convert Step 4 answer in seconds to minutes, hours, days etc.306,783.3783 seconds / 60 = 5113 minutes (Divide by 60 to convert secs to mins)= 5113 minutes / 60 = 85.22 hours (Divide by 60 to convert mins to hours)= 85.22 hours / 24...
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