...breathing there are different filters are used to remove the Gaussian noise. Mainly three different filters are used to remove the Gaussian in lung images. The SNR (Signal to Noise Ratio).is gets calculated. The better filter chooses by SNR value. Table1 Noise Comparison Table Image Name Gaussian Filter Median Filter Wiener Filter 1 3.9DB 3.2DB 4.9DB 2 3.4DB 3.5DB 4.8DB 3 3.9DB 3.3DB 4.8DB 4 4.0DB 3.0DB 4.9DB 5 3.5DB 3.4DB 4.8DB 6 3.7DB 3.3DB 5.0DB 7 3.6DB 3.2DB 4.8DB 8 3.3DB 3.3DB 4.6DB 9 3.7DB 3.5DB 4.8DB 10 3.9DB 3.1DB 4.9DB The lung regions of the denoised CXRS images are separated from the rest of the anatomical structures by applying graph cut segmentation operations as shown in fig4 Fig4 segmented lungs EXPERIMENTAL ANALYSIS...
Words: 417 - Pages: 2
...2.3 The other 3 sources Aside from the five most basic issue ranges, we have secured above, three other incessant wellsprings of problematic specimen quality found in Hospital Serdand are those connected with blood gas analysis, blood culture and urine specimens. 2.3.1 Blood Gas Specimens Whilst the centralization of heparin in most blood gas syringes is higher than in emptied blood collection tubes, clotted specimens are a key issue and prompt expanded TAT and expanded blood gas analyzer downtime. Mixing of these specimens is troublesome because of the non-attendance of an air rising in the syringe (keeping up an anaerobic state with a non-appearance of air bubbles is obviously a necessity for a quality specimen). Mixing by reversal alone is essentially insufficient. When filled to the right level, the syringe must be "moved" between the palms of the hands for no less than 5 seconds to guarantee satisfactory mixing of the heparin anticoagulant. Mixing by reversal too is additionally suggested. The forced environment in different division likewise exhibits a huge danger of NSI in...
Words: 727 - Pages: 3
...definitely have more angular vibrations. Yet in the β-phase, there will be no thermal expansion because there is no such mechanisms. In this case, there is a model reflecting the transition from α to β. This model is the single order parameterthe tilt angle δ. This model is used as the PO4 tetrahedral as well as the FeO4 indiv average δ. This is defined as: δ2 = 2/3 δ0 2 [1 + (1 – ¾ (T – Tc/T0 – Tc))^1/2]. This δ0 represents the decline in the tilt angle at 980K (which is the transition temperature) and Tc signifies the temperature for the second-order transition. The average of the overall δ can also be used as the separate δ. FePO4 doesn’t have behavior the same as any other α-quartz materials and this can be seen from its quick drop of its tilt angle δ compared to the rest. PARAGRAPH 2 FePO4 will show α- FePO4 when temperature is below 980K because it has a transition temperature of 980K. In other words, a temperature above 980K would show β- FePO4. Both structures would 1 formula unit in its unit cell. However, an α- FePO4 has a trigonal unit cell while a β- FePO4 has a hexagonal unit cell. Table 2 shows the unit cell parameters and the volume of FePO4 and its correspondence with temperature. The table shows that there are changes to the structure of the cells as the temperature changes. The cell parameters increases significantly and instantly as the temperature increases, and cell volume increases along with the temperature as well. This means that the c/a ratio would also...
Words: 1073 - Pages: 5
...compound and have different crystal structures with its own unique degree of symmetry. At room temperature (about 298k), the compound will be at the phase 3 that consists of the features in a monoclinic structure and a space group of C2/m. As the temperature rises (to about 369k), the compound will then be at phase 2 and will produce a monoclinic-A2/a symmetry structure. When the temperature reaches 470k and above, the compound will be at phase 1. It will transit into a trigon structure and has a space group of R3-m. In the article mentioned, the M3H(XO4)2 contains different symmetrical forms when it has been exposed to different temperatures. Figure 2a is one example of the compound shown in phase 3. The positioning...
Words: 641 - Pages: 3
...Chapter 3 Digital storage oscilloscope 3.1 Introduction Digital Storage Oscilloscope DSO built by Philip Cupitt . A standard oscilloscope displays variations in a voltage over time. A simple oscilloscope is of limited use for non-repeating signals .A storage scope is more advantageous as it stores the data related to signal Which can be displayed at any time. Because the screen is not continuously refreshed with the current state of the signal the scope can be used to analyze non-repeating signals. Both analogue storage and digital storage scopes are available, but digital storage are of greater use. Standard oscilloscopes use an electron beam, which is swept across a phosphor screen, the vertical deflection of the beam being proportional...
Words: 848 - Pages: 4
...Figure 6. The plot of the voltage through the capacitor as time increases. After assembling the basic RC circuits, the next step is assembling a circuit in Monostable mode. Since the capacitors and the resistors were measured values the only calculations needed in assembling this circuit were to figure out the values of the resistor in series with the capacitor which was found by using 30 seconds as the time and 470µF as the resistor and plugging those values into Equation 1 to get that the resistor needed was a 55.5kΩ resistor. After assembling the circuit as shown in Figure 3 the accuracy of the time it took the light to cut off (as shown in Table 2) can be acquired by calculating a percent error (as seen in Equation 6). The average percent error was 11.5% which means that with the measured resistance the time should have been 28.69 seconds and the approximate time measured by the stop watch was 31.59 seconds which is also shown in Table 1. Figure 7 illustrates the plot of the measured “time on” values in comparison to the RC time constant values. This graph shows they are proportional and therefore one can conclude that the correct...
Words: 1192 - Pages: 5
...Exercise One Nt1310 Week 1 In: Computers and Technology Exercise One Nt1310 Week 1 NT1310:Week 1 Telecommunications By: Kenneth Martin You are an IT Network Specialist and are required to develop the design of the company’s telephone system for its new building which will begin construction in a few months. In order to get a background which will help when developing the new system, your supervisor asked you to research the current Plain Old Telephone Service (POTS) currently used by the company. You must research the system components and report back to your supervisor , the Telecommunications Manager, within a week. 1. Describe a local land line phone system based on the following Landline Telephone Components: a. Local Loop a local loop is the wired connection from a telephone company's central office in a locality to its customers' telephones at homes and businesses. This connection is usually on a pair of copper wires called twisted pair. The system was originally designed for voice transmission only using analog transmission technology on a single voice channel. Today, your computer's modem makes the conversion between analog signals and digital signals. With Integrated Services Digital Network (ISDN) or Digital Subscriber Line (DSL), the local loop can carry digital signals directly and at a much higher bandwidth than they do for voice only. b. Central Office In telephone communication in the United States, a central office (CO) is an office in a locality...
Words: 496 - Pages: 2
...ITT Technical Institute IS3340 Windows Security Onsite Course SYLLABUS Credit hours: 4.5 Contact/Instructional hours: 60 (30 Theory Hours, 30 Lab Hours) Prerequisite(s) and/or Corequisite(s): Prerequisite: NT2580 Introduction to Information Security or equivalent Course Description: This course examines security implementations for a variety of Windows platforms and applications. Areas of study include analysis of the security architecture of Windows systems. Students will identify and examine security risks and apply tools and methods to address security issues in the Windows environment. Windows Security Syllabus Where Does This Course Belong? This course is required for the Bachelor of Science in Information Systems Security program. This program covers the following core areas: Foundational Courses Technical Courses BSISS Project The following diagram demonstrates how this course fits in the program: IS4799 NT2799 IS4670 ISC Capstone Project Capstone ProjectCybercrime Forensics NSA NT2580 NT2670 Introduction to Information Security IS4680 IS4560 NT2580 NT2670 Email and Web Services Hacking and Introduction to Security Auditing for Compliance Countermeasures Information Security Email and Web Services NT1230 NT1330 Client-Server Client-Server Networking I Networking II IS3230 IS3350 NT1230 NT1330 Issues Client-Server Client-Server SecurityContext in Legal Access Security Networking I Networking II NT1110...
Words: 2305 - Pages: 10
