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Program That Will Calculate the Number of Square Feet (Living Space) in a 4-Room House.

In: Computers and Technology

Submitted By pickle
Words 294
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Program that will calculate the number of square feet (living space) in a 4-room house.
Problem Analysis

In this Program , the aim is to calculate the square feet of a 4 –room house
So we need to know each rooms length and breadth , then calculate each rom’s area and the find the sum of those
Area of Room1=length1*breadth1
Area of Room2=length2*breadth2
Area of Room3=length3*breadth3
Area of Room4=length4*breadth4
Total Number of Square Foots = Area of Room1+ Area of Room2+ Area of Room3+ Area of Room4

Program Design
Pseudocode
Start
Declare the variables i,j as interger length[4], breadth[4],area[4] as double array sum as double
Display “Enter the Rooms length and Breadth”
For i= 1 to 4 do Accept length[i], breadth[i]
Next i
Display “Finding Area and total number of square foots”
Set sum=0
For i= 1 to 4 do Area[i]= length[i]* breadth[i] Sum=sum+Area[i]
Next i
Display “Total number of square foots”, sum
Stop

Program Comments and Test Data
C++ code

#include<iostream>
#include<string>
using namespace std;

int main()
{
int i,j; double length[4], breadth[4] ,area[4], sum;

cout<<"\nEnter the length and breadth of each room"; for (i=0;i<4;i++)
{
cout<<"\nRoom "<<i+1<<" Length :"; cin >>length[i]; cout<<"\nRoom "<<i+1<<" Breadth :"; cin >>breadth[i];
}
sum=0; for (i=0;i<4;i++)
{
area[i]=length[i]* breadth[i]; sum=sum+area[i];
}
cout<<"\nTotal number of square foots :"<<sum<<endl;

return 0;
}

Test data and Output

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