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Rectifier

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Submitted By Fawwaz
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Chapter 2 AC to DC CONVERSION (RECTIFIER)
• Single-phase, half wave rectifier – Uncontrolled: R load, R-L load, R-C load – Controlled – Free wheeling diode • Single-phase, full wave rectifier – Uncontrolled: R load, R-L load, – Controlled – Continuous and discontinuous current mode • Three-phase rectifier – uncontrolled – controlled

Power Electronics and Drives (Version 3-2003), Dr. Zainal Salam, 2003

1

Rectifiers
• DEFINITION: Converting AC (from mains or other AC source) to DC power by using power diodes or by controlling the firing angles of thyristors/controllable switches. • Basic block diagram

AC input

DC output

• Input can be single or multi-phase (e.g. 3phase). • Output can be made fixed or variable • Applications: DC welder, DC motor drive, Battery charger,DC power supply, HVDC
Power Electronics and Drives (Version 3-2003), Dr. Zainal Salam, 2003 2

Single-phase, half-wave, R-load
+ vs _ vs + vo _

π vo io 2π

ωt

Output voltage (DC or average), V Vo = Vavg = 1 Vm sin(ωt )dωt = m = 0.318Vm 2π 0 π Output voltage (rms), Vm 1 (Vm sin(ωt )dωt ) = = 0.5Vm Vo , RMS = 2π 0 2
Power Electronics and Drives (Version 3-2003), Dr. Zainal Salam, 2003 3

π

π

2

Half-wave with R-L load i + vR _ + vL _ + vo _

+ vs _

Vm sin(ωt ) = i (ωt ) R + L i (ωt ) = i f (ωt ) + in (ωt )

di (ωt ) dωt First order differential eqn. Solution :

KVL : vs = v R + v L

i f : forced response; in natural response, From diagram, forced response is : i f (ωt ) = where : Z = R 2 + (ωL) 2 Vm ⋅ sin(ωt − θ ) Z

θ = tan −1

ωL
R
Power Electronics and Drives (Version 3-2003), Dr. Zainal Salam, 2003 4

R-L load
Natural response is when source = 0, di (ωt ) i (ωt ) R + L =0 dωt which results in : in (ωt ) = Ae −ωt ωτ ; τ = L R Hence Vm i (ωt ) = i f (ωt ) + in (ωt ) = ⋅ sin(ωt − θ ) + Ae −ωt ωτ Z A can be solved by realising inductor

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