...Solutions to Chapter 5 1. Explain the difference between connectionless unacknowledged service and connectionless acknowledged service. How do the protocols that provide these services differ? Solution: In an acknowledged connectionless network, reliable delivery can be achieved through the use of ACK and NAK transmissions. Such protocols are suited for communication over networks in which higher layers are sensitive to loss and the underlying network is inherently unreliable with a significant probability of loss or error. Unacknowledged networks provide simpler and faster communication for networks that are inherently reliable or provide service to higher layers that can tolerate information loss. 2. Explain the difference between connection-oriented acknowledged service and connectionless acknowledged service. How do the protocols that provide these services differ? Solution: The use of acknowledgments can provide reliable transfer over networks that are prone to error and loss. In connection oriented networks, every packet in a data flow travels on the same path through the network and the proper ordering of packets is guaranteed. In such networks, if a packet arrives out of order, the receiver immediately knows that a packet has been lost. In a connectionless network, the service needs a mechanism for dealing with unordered delivery of information. This is especially important for real-time or delay-sensitive traffic, which may require immediate retransmission and may not...
Words: 13263 - Pages: 54
...Chapter 5 A firm has three investment alternatives. Payoffs are in thousands of dollars. a) Using the expected value approach, which decision is preferred? b) For the lottery having a payoff of $100,000 with probability p and $0 with probability (1 - p), two decision makers expressed the following indifference probabilities. Find the most preferred decision for each decision maker using the expected utility approach. c) Why don’t decision makers A and B select the same decision alternative? Difference in attitude toward risk. Decision maker A tends to avoid risk, while decision maker B tends to take a risk for the opportunity (Risk taker) of a large payoff. (Can be check by plotting the values). Q#2. Alexander Industries is considering purchasing an insurance policy for its new office building in St. Louis, Missouri. The policy has an annual cost of $10,000. If Alexander Industries doesn’t purchase the insurance and minor fire damage occurs, a cost of $100,000 is anticipated; the cost if major or total destruction occurs is $200,000. The costs, including the state-of-nature probabilities, are as follows: a) Using the expected value approach, what decision do you recommend? b) What lottery would you use to assess utilities? (Note: Because the data are costs, the best payoff is $0.) Lottery: p= probability of a $0 Cost and (0 is highest payoff and 200, 000 is the lowest value) 1 - p = probability of a $200,000 Cost c) Assume that...
Words: 629 - Pages: 3
...Appendix to Chapter 5 5A.1 a. The present value of any coupon bond is the present value of its coupon payments and face value. Match each cash flow with the appropriate spot rate. For the cash flow that occurs at the end of the first year, use the one-year spot rate. For the cash flow that occurs at the end of the second year, use the two-year spot rate. P = C1 / (1+r1) + (C2+F) / (1+r2)2 = $60 / (1.1) + ($60 + $1,000) / (1.11)2 = $54.55 + $860.32 = $914.87 The price of the bond is $914.87. b. The yield to the maturity is the discount rate, y, which sets the cash flows equal to the price of the bond. P = C1 / (1+y) + (C2+F) / (1+y)2 $914.87 = $60 / (1+y) + ($60 + $1,000) / (1+y)2 y = .1097 = 10.97% The yield to maturity is 10.97%. 5A.2 The present value of any coupon bond is the present value of its coupon payments and face value. Match each cash flow with the appropriate spot rate. P = C1 / (1+r1) + (C2+F) / (1+r2)2 = $50 / (1.10) + ($50 + $1,000) / (1.08)2 = $45.45 + $900.21 = $945.66 The price of the bond is $945.66. 5A.3 Apply the forward rate formula to calculate the one-year rate over the second year. (1+r1) ( (1+f2) = (1+r2)2 (1.09) ( (1+f2) = (1.10)2 f2 = .1101 The one-year forward rate over the second year is 11.01%. 5A.4 Calculate the forward...
Words: 369 - Pages: 2
...What is the function of a redirector? To determine whether a request is meant for the client CPU or the server What are the three tiers in a 3-tier architecture? Client, middleware, server If Alex’s user account belongs to the Teachers group on a Windows Server 2008 network, and the Teachers group has read and execute permissions for the Lessons folder, what can Alex do with documents in the Lessons folder? Open an existing document. Suppose you own a computer that contains a 1 GHz processor, 512 MB of RAM, and an 8 GB hard drive. If you wanted to install Windows Server 2008 on this computer, what is the minimum hardware upgrade you must perform, if any? Increase the hard drive space to 10 GB. You have created a printer object for a new HP LaserJet in your Windows Server 2008 Active Directory. Before users can print to this printer, what else must you create in Active Directory? a. A printer share What is the purpose of a container in an LDAP-compatible NOS directory? To organize similar objects for easier management What is the relationship between threads and multiprocessing? Processes are made of threads; threads within a process can be handled by different processors to improve server performance. When a server’s RAM is fully utilized, where can the NOS store unused information blocks? In a page file on its hard drive What primary advantage does Windows Server 2008 gain by assigning each operation its own 32- or 64-bit memory area? a. Multiple applications...
Words: 636 - Pages: 3
...Chapter 5, Problem 1. The equivalent model of a certain op amp is shown in Fig. 5.43. Determine: (a) the input resistance. (b) the output resistance. (c) the voltage gain in dB. 8x104vd Figure 5.43 for Prob. 5.1 Chapter 5, Solution 1. (a) (b) (c) Rin = 1.5 MΩ Rout = 60 Ω A = 8x104 Therefore AdB = 20 log 8x104 = 98.0 dB Chapter 5, Problem 2 The open-loop gain of an op amp is 100,000. Calculate the output voltage when there are inputs of +10 µV on the inverting terminal and + 20 µV on the noninverting terminal. Chapter 5, Solution 2. v0 = Avd = A(v2 - v1) = 105 (20-10) x 10-6 = 1V PROPRIETARY MATERIAL. © 2007 The McGraw-Hill Companies, Inc. All rights reserved. No part of this Manual may be displayed, reproduced or distributed in any form or by any means, without the prior written permission of the publisher, or used beyond the limited distribution to teachers and educators permitted by McGraw-Hill for their individual course preparation. If you are a student using this Manual, you are using it without permission. Chapter 5, Problem 3 Determine the output voltage when .20 µV is applied to the inverting terminal of an op amp and +30 µV to its noninverting terminal. Assume that the op amp has an open-loop gain of 200,000. Chapter 5, Solution 3. v0 = Avd = A(v2 - v1) = 2 x 105 (30 + 20) x 10-6 = 10V Chapter 5, Problem 4 The output voltage of an op amp is .4 V when the noninverting input is 1 mV. If the open-loop gain of the op amp is 2 × 106, what is the inverting...
Words: 6920 - Pages: 28
...Business Decision Making Session – IV Chapter 11: Linear Programming Chapter 12: Transportation, Transshipment, and Assignment Problems Chapter 13: Decision Analysis Faculty Pankaj Dutta Chapter – 11 Linear Programming LPP solution through Excel Solver: The Steps in Implementing an LP Model in a Spreadsheet: 1. 2. 3. 4. Organize the data for the model on the spreadsheet. Reserve separate cells in the spreadsheet for each decision variable in the model. Create a formula in a cell in the spreadsheet that corresponds to the objective function. For each constraint, create a formula in a separate cell in the spreadsheet that corresponds to the left-hand side (LHS) of the constraint. PANKAJ DUTTA IMTCDL Chapter – 11 Linear Programming LPP solution through Excel Solver: Max Z = 350X1 + 300X2 Subject To 1X1 + 1X2 ≤ 200 9X1 + 6X2 ≤ 1566 12X1+16X2 ≤ 2880 X1 , X 2 ≥ 0 1. Organize the data for the model on the spreadsheet. PANKAJ DUTTA IMTCDL Chapter – 11 Linear Programming LPP solution through Excel Solver: Max Z = 350X1 + 300X2 Subject To 1X1 + 1X2 ≤ 200 9X1 + 6X2 ≤ 1566 12X1+16X2 ≤ 2880 X1 , X 2 ≥ 0 1. Organize the data for the model on the spreadsheet. Changing cells Target cell PANKAJ DUTTA IMTCDL Constraint cells Chapter – 11 Linear Programming Max Z = 350X1 + 300X2 Subject To 1X1 + 1X2 ≤ 200 9X1 + 6X2 ≤ 1566 12X1+16X2 ≤ 2880 X1 , X 2 ≥ 0 LPP solution through Excel Solver: 1. Organize the...
Words: 798 - Pages: 4
... FOR MORE CLASSES VISIT www.fin534tutor.com FIN 534 Week 1 Chapter 1 Solution FIN 534 Week 1 Chapter 2 Solution FIN 534 Week 2 Chapter 3 Solution FIN 534 Week 3 Chapter 4 Solution FIN 534 Week 3 Chapter 5 Solution FIN 534 Week 4 Chapter 6 Solution FIN 534 Week 4 Chapter 7 Solution FIN 534 Week 5 Chapter 8 Solution FIN 534 Week 5 Chapter 9 Solution FIN 534 Week 6 Chapter 10 Solution FIN 534 Week 6 Chapter 11 Solution FIN 534 Week 7 Chapter 12 Solution FIN 534 Week 7 Chapter 13 Solution FIN 534 Week 8 Chapter 14 Solution FIN 534 Week 8 Chapter 15 Solution FIN 534 Week 9 Chapter 16 Solution FIN 534 Week 10 Chapter 17 Solution Fin 534 Week 1 Quiz 1 FIN 534 Week 3 Quiz 2 FIN 534 Week 4 Quiz 3 FIN 534 Week 5 Quiz 4 FIN 536 Week 6 Quiz 5 FIN 534 Week 7 Quiz 6 FIN 534 Week 8 Quiz 7 FIN 534 Week 9 Quiz 8 FIN 534 Week 10 Quiz 9 FIN 534 Week 11 Quiz 10 FIN 534 Week 1 DQ 1 FIN 534 Week 1 DQ 2 FIN 534 Week 2 DQ 1 FIN 534 Week 2 DQ 2 FIN 534 Week 3 DQ 1 FIN 534 Week 3 DQ 2 FIN 534 Week 4 DQ 1 FIN 534 Week 4 DQ 2 FIN 534 Week 5 DQ 1 FIN 534 Week 6 DQ 1 FIN 534 Week 7 DQ 1 FIN 534 Week 7 DQ 2 FIN 534 Week 8 DQ 1 FIN 534 Week 8 DQ 2 FIN 534 Week 9 DQ 1 FIN 534 Week 9 DQ 2 FIN 534 Week 10 DQ 1 FIN 534 Week 10 DQ 2 FIN 534 Week 11 DQ 1 FIN 534 Week 11 DQ 2 ------------------------------------------------------------------------------------ FIN 534 Week 1 Chapter 1 Solution (Str Course) FOR MORE CLASSES VISIT www.fin534tutor.com 1. Which...
Words: 1501 - Pages: 7
...300 Quizzes Week 1-11 Solution All possible questions with answers BUS 300 Week 2 Quiz 1: Chapters 1 and 2 BUS 300 Week 3 Quiz 2: Chapters 3 and 4 BUS 300 Week 4 Quiz 3: Chapters 5 and 6 BUS 300 Week 5 Quiz 4: Chapters 7 and 8 BUS 300 Week 6 Quiz 5: Chapters 9 and 10 BUS 300 Week 7 Quiz 6: Chapters 11 and 12 BUS 300 Week 8 Quiz 7: Chapters 13 and 14 BUS 300 Week 9 Quiz 8: Chapters 15 and 16 BUS 300 Week 10 Quiz 9: Chapters 17 and 18 BUS 300 Week 11 Quiz 10: Chapter 19 BUS 300 Quizzes Week 1-11 Solution All possible questions with answers BUS 300 Week 2 Quiz 1: Chapters 1 and 2 BUS 300 Week 3 Quiz 2: Chapters 3 and 4 BUS 300 Week 4 Quiz 3: Chapters 5 and 6 BUS 300 Week 5 Quiz 4: Chapters 7 and 8 BUS 300 Week 6 Quiz 5: Chapters 9 and 10 BUS 300 Week 7 Quiz 6: Chapters 11 and 12 BUS 300 Week 8 Quiz 7: Chapters 13 and 14 BUS 300 Week 9 Quiz 8: Chapters 15 and 16 BUS 300 Week 10 Quiz 9: Chapters 17 and 18 BUS 300 Week 11 Quiz 10: Chapter 19 BUS 300 Quizzes Week 1-11 Solution All possible questions with answers BUS 300 Week 2 Quiz 1: Chapters 1 and 2 BUS 300 Week 3 Quiz 2: Chapters 3 and 4 BUS 300 Week 4 Quiz 3: Chapters 5 and 6 BUS 300 Week 5 Quiz 4: Chapters 7 and 8 BUS 300 Week 6 Quiz 5: Chapters 9 and 10 BUS 300 Week 7 Quiz 6: Chapters 11 and 12 BUS 300 Week 8 Quiz 7: Chapters 13 and 14 BUS 300 Week 9 Quiz 8: Chapters 15 and 16 BUS 300 Week 10 Quiz 9: Chapters 17 and 18 BUS 300...
Words: 459 - Pages: 2
...Adventures in Debentures c Copyright ⃝ 2004 by Michael R. Gibbons Adventures in Debentures we can solve for y to obtain Solutions to The Grammar of Fixed Income Securities 1. Part Part Part Part Part Part a. b. c. d. e. f. $100/(1.20)3 = $57.87. $100/(2)3 = $12.50. $100/(1)3 = $100. $100/(1.10)6 = $56.45. $100/(1.05)12 = $55.68. $100/e.20×3 = $54.88. y= So yB = and yA = 2nLN nSN 1 + c/2 −1 . P/100 2 · 184 1 + .09125/2 − 1 = 2.991185% 105 103.6776495/100 2 · 184 1 + .09125/2 − 1 = 2.778233% . 105 103.7401495/100 2. Remember we are trying to find r such that the growth in our initial investment is the ˙ same as the growth from an alternative investment providing a rate of r(m). That is, find r ˙ Part a. Part b. Part c. Part d. ˙ ˙ such that er = (1 + r(m)/m)m so r = m ln(1 + r(m)/m). m = 1: ln(1.04) = 3.922%. m = 1: ln(1.20) = 18.232%. m = 4: 4 ln(1.05) = 19.516%. m = 1: ln(2) = 69.315%. In addition, we have Part b. Ignoring for the moment any restrictions on lot size, we note that a cash flow of $100 to be received on 12/31/92 and purchased on 9/17/92 is available either in the form of $100 par amount of the 12/31/92 bill or in the form of $100/(1+.09125/2) par amount of the 9 1/8’s of 12/31/92. (Indeed, since $100 par of the 9 1/8’s will pay off $(100 + 9.125/2) on 12/31/92, $100/(1 + .09125/2) par amount of the 9 1/8’s will pay off $100.) Can we buy this cash flow low through one instrument and sell it high through the other? We must see if the asked price of one of the...
Words: 25468 - Pages: 102
...Solutions to Case Problems Manual to Accompany An Introduction To Management Science Quantitative Approaches To Decision Making Twelfth Edition David R. Anderson University of Cincinnati Dennis J. Sweeney University of Cincinnati Thomas A. Williams Rochester Institute of Technology R. Kipp Martin University of Chicago South-Western Cincinnati, Ohio Contents Preface Chapter 1: Introduction ♦ Scheduling a Golf League Chapter 2: An Introduction to Linear Programming ♦ Workload Balancing ♦ Production Strategy ♦ Hart Venture Capital Chapter 3: Linear Programming: Sensitivity Analysis and Interpretation of Solution ♦ Product Mix ♦ Investment Strategy ♦ Truck Leasing Strategy Chapter 4: Linear Programming Applications in Marketing, Finance and Operations Management ♦ Planning an Advertising Campaign ♦ Phoenix Computer ♦ Textile Mill Scheduling ♦ Workforce Scheduling ♦ Duke Energy Coal Allocation Chapter 6: Distribution and Network Models ♦ Solution Plus ♦ Distribution Systems Design Chapter 7: Integer Linear Programming ♦ Textbook Publishing ♦ Yeager National Bank ♦ Production Scheduling with Changeover Costs Chapter 8: Nonlinear Optimization Models ♦ Portfolio Optimization with Transaction Costs Chapter 9: Project Scheduling: PERT/CPM ♦ R.C. Coleman Chapter 10: Inventory Models ♦ Wagner Fabricating Company ♦ River City Fire Department Chapter 11: Waiting Line Models ♦ Regional Airlines ♦ Office Equipment, Inc. Chapter 12: Simulation ♦ Tri-State Corporation...
Words: 5633 - Pages: 23
...[pic] |Quantitative Methods – MAT 540 | |Student Course Guide | |Prerequisite: MAT 300 | |INSTRUCTIONAL MATERIAL – Required | |( including all mandatory software) | |Taylor, B. M. (2010). Introduction to management science (10th ed.). Upper Saddle River, NJ: Pearson/Prentice Hall. | |Treeplan add-on for Excel. This software is available in the Open Lab at Strayer campuses, and can also be downloaded from the textbook's | |companion Website. http://wps.prenhall.com/bp_taylor_introms_10/112/28870/7390752.cw/-/7390754/index.html | | | |COURSE DESCRIPTION | |Applies quantitative methods to systems management...
Words: 2976 - Pages: 12
...and the interplay of kinetic, potential, heat and work energy. To describe and apply the Second Law of Thermodynamics from several points of view: randomness, chaos, probability, distribution of matter and energy, energy efficiency. 4. To know that we measure energy only through change, such as with a calorimeter. 5. To use potential energy diagrams to represent changes that take place in reactions 6. To use the terms endothermic and exothermic to describe the entry or exit of heat from chemical systems (and that the opposite change must take place in the surroundings). 7. To know that energy changes in reactions come from changes in chemical bonds, and how they can be estimated from differences in bond energies of bonds broken vs. formed. 8. To express and interpret these changes in potential energy diagrams and apply these skills to the combustion of fuels. 9. To view and describe recent trends in energy source utilization. 10. To give specific details on the composition of coal and its impacts on environmental quality. Assignments: Read §4.1 – 4.5. Recommended exercises: From the above sections, all in-chapter “Your Turn” exercises, and chapter-end problems selected from #1 – 18, 24 - 29 4/30 Outcomes: 1. To describe petroleum as a mixture of hydrocarbons, and how they are separated industrially. 2. To distinguish alkanes from other types of hydrocarbons. 3. To draw examples of straight-chain and branched alkanes and give...
Words: 1442 - Pages: 6
...To download more slides, ebooks, solution manual and test bank, visit http://downloadslide.blogspot.com Solutions Manual COST ACCOUNTING © 2012 Pearson Education, Inc. Publishing as Prentice Hall. SM Cost Accounting 14/e by Horngren © 2012 Pearson Education, Inc. Publishing as Prentice Hall. SM Cost Accounting 14/e by Horngren To download more slides, ebooks, solution manual and test bank, visit http://downloadslide.blogspot.com Solutions Manual COST ACCOUNTING Fourteenth Edition Charles T. Horngren Srikant M. Datar Madhav Rajan Upper Saddle River, NJ 07458 © 2012 Pearson Education, Inc. Publishing as Prentice Hall © 2012 Pearson Education, Inc. Publishing as Prentice Hall. SM Cost Accounting 14/e by Horngren This work is protected by United States copyright laws and is provided solely for the use of instructors in teaching their courses and assessing student learning. Dissemination or sale of any part of this work (including on the World Wide Web) will destroy the integrity of the work and is not permitted. The work and materials from it should never be made available to students except by instructors using the accompanying text in their classes. All recipients of this work are expected to abide by these restrictions and to honor the intended pedagogical purposes and the needs of other instructors who rely on these materials. Acquisition Editor: Stephanie Wall Editorial Project Manager: Christina Rumbaugh Editorial Assistant: Brian Reilly Project Manager, Production:...
Words: 10664 - Pages: 43
...Chapter 3, Problem 1. Determine Ix in the circuit shown in Fig. 3.50 using nodal analysis. 1 kΩ Ix 9V + _ 2 kΩ + _ 6V 4 kΩ Figure 3.50 For Prob. 3.1. Chapter 3, Solution 1 Let Vx be the voltage at the node between 1-kΩ and 4-kΩ resistors. 9 − Vx 6 − Vx Vk + = 1k 4k 2k Vx Ix = = 3 mA 2k ⎯⎯ Vx = 6 → PROPRIETARY MATERIAL. © 2007 The McGraw-Hill Companies, Inc. All rights reserved. No part of this Manual may be displayed, reproduced or distributed in any form or by any means, without the prior written permission of the publisher, or used beyond the limited distribution to teachers and educators permitted by McGraw-Hill for their individual course preparation. If you are a student using this Manual, you are using it without permission. Chapter 3, Problem 2. For the circuit in Fig. 3.51, obtain v1 and v2. Figure 3.51 Chapter 3, Solution 2 At node 1, − v1 v1 v − v2 − = 6+ 1 10 5 2 At node 2, 60 = - 8v1 + 5v2 (1) v2 v − v2 = 3+ 6+ 1 4 2 Solving (1) and (2), v1 = 0 V, v2 = 12 V 36 = - 2v1 + 3v2 (2) PROPRIETARY MATERIAL. © 2007 The McGraw-Hill Companies, Inc. All rights reserved. No part of this Manual may be displayed, reproduced or distributed in any form or by any means, without the prior written permission of the publisher, or used beyond the limited distribution to teachers and educators permitted by McGraw-Hill for their individual course preparation. If you are a student using this Manual, you are using it without permission. Chapter...
Words: 19454 - Pages: 78
...Investment Analysis, 7th Edition Solutions to Text Problems: Chapter 1 Chapter 1: Problem 1 A. Opportunity Set With one dollar, you can buy 500 red hots and no rock candies (point A), or 100 rock candies and no red hots (point B), or any combination of red hots and rock candies (any point along the opportunity set line AB). then: Algebraically, if X = quantity of red hots and Y = quantity of rock candies, 0.2 X + 1Y = 100 That is, the money spent on candies, where red hots sell for 0.2 cents a piece and rock candy sells for 1 cent a piece, cannot exceed 100 cents ($1.00). Solving the above equation for X gives: X = 500 − 5Y which is the equation of a straight line, with an intercept of 500 and a slope of −5. Elton, Gruber, Brown, and Goetzmann Modern Portfolio Theory and Investment Analysis, 7th Edition Solutions to Text Problems: Chapter 1 1-1 B. Indifference Map Below is one indifference map. The indifference curves up and to the right indicate greater happiness, since these curves indicate more consumption from both candies. Each curve is negatively sloped, indicating a preference of more to less, and each curve is convex, indicating that the rate of exchange of red hots for rock candies decreases as more and more rock candies are consumed. Note that the exact slopes of the indifference curves in the indifference map will depend an the individual’s utility function and may differ among students. Chapter 1: Problem 2 A. Opportunity Set ...
Words: 2581 - Pages: 11
