In: Science

Submitted By scot4999

Words 1031

Pages 5

Words 1031

Pages 5

6l | 034 | |

6h | 667899 | |

7l | 00122244 | |

7h | | Stem=Tens |

8l | 001111122344 | Leaf=Ones |

8h | 5557899 | |

9l | 03 | |

9h | 58 | |

This display brings out the gap in the data: There are no scores in the high 70's.

13.

a.

| | | |

12 | 2 | Leaf = ones |

12 | 445 | Stem = tens | |

12 | 6667777 | | |

12 | 889999 | | |

13 | 00011111111 | | |

13 | 2222222222333333333333333 | | |

13 | 44444444444444444455555555555555555555 |

13 | 6666666666667777777777 | | |

13 | 888888888888999999 | | |

14 | 0000001111 | | |

14 | 2333333 | | |

14 | 444 | | |

14 | 77 | | |

The observations are highly concentrated at 134 – 135, where the display suggests the typical value falls.

b.

The histogram is symmetric and unimodal, with the point of symmetry at approximately 135.

15

Crunchy | | Creamy |

| 2 | 2 |

644 | 3 | 69 |

77220 | 4 | 145 |

6320 | 5 | 3666 |

222 | 6 | 258 |

55 | 7 | |

0 | 8 | |

Both sets of scores are reasonably spread out. There appear to be no outliers. The three highest scores are for the crunchy peanut butter, the three lowest for the creamy peanut butter.

17

a

Number

Nonconforming Frequency RelativeFrequency(Freq/60)

0 7 0.117

1 12 0.200

2 13 0.217

3 14 0.233

4 6 0.100

5 3 0.050

6 3 0.050

7 1 0.017

8 1 0.017

doesn't add exactly to 1 because relative frequencies have been rounded 1.001

b The number of batches with at most 5 nonconforming items is 7+12+13+14+6+3 = 55, which is a proportion of 55/60 = .917. The proportion of batches with (strictly) fewer than 5 nonconforming items is 52/60 = .867. Notice that these proportions could also have been computed by using the relative frequencies:…...

... | Guinea | Belgium | Burundi | Czech Republic | Bolivia | Hungary | Dominican Republic | Haiti | Belarus | Benin | Azerbaijan | Austria | Honduras | Israel | Bulgaria | Libya | Jordan | Laos | El Salvador | Er'trea | Nicaragua | Kyrgyzstan | Denmark | Finland | Central African Republic | Norway | Ireland | Bosnia and Herzegovina | Georgia | Costa Rica | Croatia | Moldova | New Zealand | Congo, Republic of the | Lebanon | Liberia | Lithuania | Mauritania | Mongolia | Albania | Armenia | Jamaica | Kuwait | Latvia | Namibia | Macedonia | Botswana | Lesotho | Kosovo | Gambia | Guinea-Bissau | Gabon | Mauritius | Estonia | Bahrain | Cyprus | Fiji | Comoros | Djibouti | Guyana | Bhutan | Equatorial Guinea | Montenegro | Cape Verde | Luxembourg | Malta | Brunei | Maldives | Belize | Bahamas, The | Iceland | Barbados | Grenada | Micronesia, Federated States of | Kiribati | Antigua and Barbuda | Andorra | Dominica | Marshall Islands | Liechtenstein | Monaco | Population Descriptive Statistics: Column1 | | | Mean | 39786098,5 | Standard Error | 14001122,25 | Median | 6508271 | Mode | #YOK | Standard Deviation | 159022180 | Sample Variance | 2,52881E+16 | Kurtosis | 55,5365861 | Skewness | 7,327371857 | Range | 1336687476 | Minimum | 30539 | Maximum | 1336718015 | Sum | 5132406706 | Count...

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... the AOV in Table 10-5, SSR =(0.75) $ (2.02) = 1.52 Ssr = (0.25) $ (2.02) = 0.51 In more complicated regression models, it is often desirable to adjust for the degrees of freedom of regression by R Radj 2 ( 2 Ra2dj ! 1" MSr /MSY For the liver-body weight examples (Table 10-4) Radj 2 ! 1" 0.13 / (2.02 / 5) ! 0.68 Note that the considerable reduction in R2 (from 0.75 to 0.68) is a result of the large adjustment due to the small number of regression points. In the case of corn data in Table 10-7, R2 = 24459.36/26302.81 = 0.93 and Radj = 1 - [141.8/(26302.81/14)] = 0.925 2 This is a relatively small change due to the greater number of degrees of freedom. 10.5 Confidence limits for the regression coefficient (') The mean square for residuals from regression (Msr) can be used as an estimate of the population variance if there is no significant lack of fit. Its square root is used to compute standard errors for various statistics associated with regression. The standard error of the regression coefficient b is Sb Sb ! [MSr / #(X " X)2 ]1/2 To construct a confidence interval for the true regression coefficient, we need a t-statistic which is defined as t = (b - '/Sb with df = k-2 where ' is the true regression coefficient. This formula provides a t-test for significance for a nonzero ' equivalent to the F-test of the AOV for regression. The confidence limits of ' for a given ) are, b + t,),k-2 •Sb The 95% C. L. for for the regression of liver weight on...

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...If A and B are mutually exclusive events with P(A) = 0.70, then P(B) can be any value between 0 and 1. can be any value between 0 and 0.70. cannot be larger than 0.30. None of the above statements are true. If A and B are independent events with P(A) = 0.20 and P(B) = 0.60, then P(A|B) is 0.2000 In the notation below, X is the random variable, c is a constant, and V refers to the variance. Which of the following laws of variance is not correct? V(c) = 0 V(X + c) = V(X) V(X + c) = V(X) + c V(cX) = c2 V(X) Which of the following statements is always correct? P(A and B) = P(A) * P(B) P(A or B) = P(A) + P(B) P(A or B) = P(A) + P(B) + P(A and B) P[pic]= 1- P(A) An experiment consists of tossing an unbiased coin three times. Drawing a probability tree for this experiment will show that the number of simple events in this experiment is 8 Use the following information to answer questions 6 and 7: The weights of newborn children in the United States vary according to a normal distribution with mean 7.5 pounds and standard deviation 1.25 pounds. The government classifies a newborn as having low birth weight if the weight is less than 5.5 pounds. What proportion of babies weigh less than 5.5 pounds at birth? 0.0548 If the government wanted to change the value 5.5 pounds to a weight where only 2% of newborns weigh less than the new value, what weight should they use? 4.9375 pounds If you are given a table of joint probabilities of two events...

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...CHAPTER 9 [pic] Current Liabilities, Contingencies, and the Time Value of Money OVERVIEW OF EXERCISES, PROBLEMS, AND CASES Estimated Time in Learning Objective Exercises Minutes Level 1. Identify the components of the current liability category of 1 10 Easy the balance sheet. 2 10 Easy 3 10 Easy 2. Examine how accruals affect the current liability category. 4 20 Mod 5 15 Mod 6 10 Mod 7 15 Mod 8 15 Mod 3. Demonstrate an understanding of how changes in current liabilities 9 5 Easy affect the statement of cash flows. 10 5 Mod 11 5 Mod 4. Determine when contingent liabilities should be presented on the 12 15 Mod balance sheet or disclosed in notes and how to calculate their amounts. 5. Explain the difference between simple and compound interest. 13 20 Mod 6. Calculate amounts using the future value and present value concepts. 14 5 Easy 15 5 Mod 16 10 Mod 17 10 Mod 24* 10 Diff 25* 10 Diff 7. Apply the compound interest concepts to some common 18 5 Mod accounting situations. 19 10 Mod 20 10 Diff 24* 10 Diff 25* 10 Diff 8. Demonstrate an understanding of the deductions 21 15 Mod and expenses for payroll accounting. (Appendix 9A) 22 20 Mod 9. Determine when compensated absences must be 23 10 Diff accrued as a liability. (Appendix 9A) *Exercise, problem, or case covers two or more learning objectives Level = Difficulty...

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.... $62.583, found by $751/12. b. Between $60.54 and $64.63, found by [pic] c. $60 is not reasonable, because it is outside of the confidence interval. 53. a. 89.4667, found by 1342/15. b. Between 84.99 and 93.94, found by [pic] c. Yes, because even the lower limit of the confidence interval is above 80. 55. Between .647 and .753, found by [pic] Yes, because even the lower limit of the confidence interval is above .500. 57. $52.56 and $55.44, found by [pic] 59. 369, found by n ( 0.60(1 ( 0.60)[1.96/0.05]2. 61. 97, found by [(1.96 ( 500)/100]2. 63. a. 708.13, rounded up to 709, found by 0.21(1 ( 0.21)[1.96/0.03]2. b. 1068, found by 0.50(0.50)(1.96/0.03)2. 65. Between .573 and .653, found by [pic]. Yes, because even the lower limit of the confidence interval is above .500. 67. Between 12.69 and 14.11, found by [pic] 69. Answers are from MegaStat a. |Descriptive statistics | | | | | | |List Price | |Count |96 | |Mean |447,403.14 | |sample variance |20,560,909,990.86 | |sample standard deviation |143,390.76 | |Confidence interval - mean...

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... 2. When testing for differences between the means of 2 related populations, we can use either a one-tailed or two-tailed test. True 3. The test for the equality of 2 population variances assumes that each of the 2 populations is normally distributed. True 4. When the sample sizes are equal , the pooled variance of the 2 groups is the average of the 2 sample variances. True 5. A researcher is curious about the effect of s leep on students’ test performances. He chooses 60 students and gives each 2 tests: one given after 2 hours’ sleep and one after 8 hours’ sleep. The test the researcher should use would be a related samples test. True 6. A statistics professor wanted to test whether the grades on a statistics test were the same for upper and lower classmen. The professor took a random sample of size 10 from each, conducted a test and found out that the variances were equal. For this situation, the professor should use a t test with related samples. False 7. In testing the difference between two proportions using the normal distribution, we may use a two-tailed Z test. True SECTION III: FREE RESPONSE QUESTIONS TABLE (A) A researcher randomly sampled 30 graduates of an MBA program and recorded data concerning their starting salaries. Of primary interest to the researcher was the effect of gender on starting salaries. Analysis of the mean salaries of the females and males in the sample is......

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...1. A US National Public Transportation survey taken few years ago in USA indicated that less than 5% of US citizens use public transportation. Collect secondary data from several websites of U.S. Departments of Transportation, US Census Bureau etc. to test this hypothesis from the survey. Write a short essay to explain the data. * Solution: Table of public transportation for workers 16 years old and over (2011) States | | Population | Used public trans | New York | 9,369,306 | 814,751 | Massachusetts | 4,855,839 | 275,025 | California | 15,793,961 | 654,698 | Texas | 9,609,319 | 188,186 | Illinois | 6,993,703 | 412,433 | Total | = 46,622,128 | = 2,345,093 | (Statistic from U.S. Departments of Transportation) We choose 5 states of the USA: New York , Massachusetts, California, Texas, Illinois for making a survey. - According to the U.S. Departments of Transportation, the population of 5 states is n= 46,622,128. They estimates the number of workers who commuted by public transportation in the 5 largest states is 2,345,093 - Let p denote the probability of people using public transportation. Thus, the null and alternative hypotheses are Ho: p < 5% H1: p ≥ 5% - So, sample porpotion: total number of workers use public transportationn = 0,0503 - We have: =0,0503-0,05√0,05X0,9546,622,128= 9,40 - Z test is 9,4 so p-value = 2,7736x10-21 . Because p-value < 5%, so we reject Ho . Therefore we do not accept that in 2011, less...

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...Statistic 145 Instructor’s at University Heights College approval ratings are as follows: Ms. Green 90%, Mr. White 50% and Mr. Brown 95%. Each instructor teaches three classes each semester. There have been twenty different instructors in the last nine years. In University Heights College on an average 40% Female, 20% African American and 30% of University Heights College population are believed to have poor math skills. I believe Ms. Green had a higher approval rating cause she purchased a set of text books to remain in here classroom. Therefore giving all students in her classroom an equal chance. My (Ha), would be students feel female teacher are more approachable then male teachers. Giving Ms. Green a high approval rating. (α) level would be at .05 to reach statistical significance. In this study the statistical analysis method of choice would be the Correlation method. The Correlation method is the best measure for linear relationships. In this study I’ve chosen to sample the students using a block design due to the fact the students are already broken up into groups. In this study the variables are as follows: Instructors, textbooks the lab fee. In this study its pretty simple there could be some type of bias from the students against female and male instructors. Also, there could be some type of bias against using the text book and taking the animation lab. The lurking variable would be the instructor gender. Students tend to give the female instructor a higher...

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...Question 1: Hypothesis Test for US Public Transportation Year | Percent of Public Transportation | 1997 | 4.6 | 1999 | 4.9 | 2001 | 4.7 | 2003 | 4.4 | 2005 | 4.7 | 2006 | 4.8 | 2007 | 4.9 | 2008 | 5.0 | 2009 | 5.0 | 1/ Less than 5% of US citizens use public transportation according to several websites of U.S. Departments of Transportation Survey. = 4.778 SD = 0.199 n = 9 The test statistic: t= = = 71.276 We have enough evidence to reject H0 Thus, we have sufficient evidence to prove that less than 5% of US citizens use public transportation. Base on the data, in 2008 and 2009, the percentage of people who used public transportation was the highest (5%). Because of the development of the world in general and the U.S in particular, people in U.S prefer using bus, streetcar, subway, railroad, and elevated trains. In 1999 and 2007, there had high rate of proportion of residence using public transportation (4.9%) perhaps because of the population explosion. There were also 4.6% in 1997, 4.7% in 2001 and in 2005, and 4.8% in 2006 respectively. Resource: U.S. Department of Transportation Research and Innovative Technology Administration Bureau of Transportation Statistics National Transportation Statistics http://www.bts.gov/publications/national_transportation_statistics/2010/html/table_01_38.html Question 2: Multiple Regressions We take the data from OSEVEN Company (www.oseven.vn) The result of the Regression for the...

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...Bottling Company Case Study Introduction to Statistics: MAT 300 6/7/2014 Recently customers have begun to complain that the bottles of the brand of soda produced in this company contains less than the advertised 16 ounces of product. I have pulled 30 bottles of soda and am calculating the mean, median, standard deviation, constructing a 95% confidence interval and conducting a hypothesis test to verify the claim that a bottle contains less than 16 ounces is supported. The first set of tests will consist of calculating the mean, median and standard deviation for ounces in the bottles. Below is the data set from the 30 bottles collected: Bottle Number | Ounces | Bottle Number | Ounces | Bottle Number | Ounces | 1 | 14.5 | 11 | 15 | 21 | 14.1 | 2 | 14.6 | 12 | 15.1 | 22 | 14.2 | 3 | 14.7 | 13 | 15 | 23 | 14 | 4 | 14.8 | 14 | 14.4 | 24 | 14.9 | 5 | 14.9 | 15 | 15.8 | 25 | 14.7 | 6 | 15.3 | 16 | 14 | 26 | 14.5 | 7 | 14.9 | 17 | 16 | 27 | 14.6 | 8 | 15.5 | 18 | 16.1 | 28 | 14.8 | 9 | 14.8 | 19 | 15.8 | 29 | 14.8 | 10 | 15.2 | 20 | 14.5 | 30 | 14.6 | The mean for the samples above is 14.87 ounces. The median for the samples above is 14.8 ounces. The standard deviation for the above sample is 0.550 ounces. The second test is constructing a 95% confidence interval. The values needed to construct the 95% confidence interval include; samples size of 30, confidence coefficient of...

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...Applied Statistical Methods Larry Winner Department of Statistics University of Florida February 23, 2009 2 Contents 1 Introduction 1.1 Populations and Samples . . . . . . . . . . . 1.2 Types of Variables . . . . . . . . . . . . . . . 1.2.1 Quantitative vs Qualitative Variables 1.2.2 Dependent vs Independent Variables . 1.3 Parameters and Statistics . . . . . . . . . . . 1.4 Graphical Techniques . . . . . . . . . . . . . 1.5 Basic Probability . . . . . . . . . . . . . . . . 1.5.1 Diagnostic Tests . . . . . . . . . . . . 1.6 Exercises . . . . . . . . . . . . . . . . . . . . 7 7 8 8 9 10 12 16 20 21 25 25 29 29 29 32 32 32 32 32 35 35 37 38 38 39 40 42 42 44 48 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 2 Random Variables and Probability Distributions 2.1 The Normal Distribution . . . . . . . . . . . . . . . . . . 2.1.1 Statistical Models . . . . . . . . . . . . . . . . . 2.2 Sampling Distributions and the Central Limit Theorem 2.2.1 Distribution of Y . . . . . . . . . . . . . . . . . . 2.3 Other Commonly Used Sampling Distributions . . . . . 2.3.1...

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...QBUS 215 HW #1 Due 07/15/15 @7:55 am Name: ──────────────── Based on the content of the Online Detailed Examples presentations along with other online resources and your textbook, plus the posted set of solved problems, complete and fill in the blanks below. All questions are based upon the Required Textbook: Statistics for Business and Economics by Anderson, Sweeney and Williams, 11th Ed., 2012, Thomson/South-Western. Ch-3 ( Learning Objectives) 1. Understand the purpose of measures of location. 2. Be able to compute the mean, median, mode, quartiles, and various percentiles. 3. Understand the purpose of measures of variability. 4. Be able to compute the range, interquartile range, variance, standard deviation, and coefficient of variation. 5. Understand skewness as a measure of the shape of a data distribution. Learn how to recognize when a data distribution is negatively skewed, roughly symmetric, and positively skewed. 6. Be able to compute and interpret covariance and correlation as measures of association between two variables. Ch-5 (Learning Objectives) 1. Understand the concepts of a random variable and a probability distribution. 2. Be able to distinguish between discrete and continuous random variables. 3. Be able to compute and interpret the expected value, variance, and standard deviation for a discrete random variable. Ch-8: ( Learning Objectives: Only Section 2) 1. Know how to construct and interpret an interval estimate of a population mean and / or a...

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... CLEVELAND WARRIORS No. 3 Diones, Shanelle Louise Padongao, Reneila Ramirez, Nikki Soledad, Christian 2015 Statistic Records of Golden State Warriors and Cleveland Cavaliers The data presented is a list of the scores of two well-known NBA teams in our time. Between the Golden State Warriors and the Cleveland Cavaliers, these two teams are what people are feasting their eyes on to watch their favorite players namely Stephen Curry in Golden State Warriors and Lebron James in Cleveland Cavaliers. Having been able to win the championship game last year, the Golden State Warriors are again on the run towards becoming this year’s champion. Trailing behind them is the team famously led by Lebron James which is the Cleveland Cavaliers. The data further shows the statistics and points made by each team and their corresponding average points. Table I. Statistic records of Golden State Warriors and Cleveland Cavaliers Date | Score ( Golden State Warriors) | SCORE( Cleveland Cavaliers) | October 28 | 111 | 95 | October 29 | | 106 | October 31 | 112 | 102 | November 1 | 134 | | November 3 | 119 | 107 | November 5 | 112 | 96 | November 7 | 119 | 108 | November 8 | 103 | | November 9 | | 111 | November10 | 109 | | November 11 | | 118 | November 12 | 100 | | November 13 | 129 | | November 14 | | 90 | November 15 | 117 | 105 | November 18 | 115 | 99 | November 20 | 124 | 115 | November 21 | 106 | | November 22 | | 109 | November 23 | 118 | | November...

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...Statistics in Business Statistics is defined by Merriam-Webster as a branch of math dealing with the collection, analysis, interpretation and presentation of masses of numerical data; or a collection of quantitative data (Statistics, n.d.). Statistics is all around us. Everything from our actions, to our purchases, to even sports involve the collection, analysis, interpretation and presentation of data. There are two types of statistics. One type is called, descriptive statistics, which uses numbers and graphs to identify patterns and trends in data sets and is used to present revealed information in an easy to understand form. The other type of statistic is known as inferential statistic. Inferential statistics is using sample data collected from a smaller sample, and using those results to make predictions, estimates, decisions and other generalizations about a larger set of data (McClave, Benson, & Sincich, 2011). Statistics plays a number of roles in business decisions. One of the more obvious roles it plays is in marketing. Research studies allow businesses to be proactive by predicting customer behavior and creating specific marketing plans. For instance a business that sells sandals would use statistics to identify when sales have increased and when they are likely to increase again. For instance the spring and summer months show statistics of higher sales, which tells the business to increase inventory at those times. Another one of the many roles...

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... men and women. While creating such percentage of population, this is better to judge and verify with various categories, using categories based on gender and earnings. Earnings | Men | Women | under 20,000$ | 47% | 52% | 20,000–50,000$ | 45% | 47% | over 50,000$ | 8% | 1% | Valid cases: 200 Missing cases: 0 | | | The types of data analysis suit to some specific pairs of variables. They vary according to the level of measurement of the variables of interest. Bivariate Statistical Tests refer to a simple of two variables that are completely alternative of multivariate analysis. Bivariate Statistical Tests look at the relation between two variables or questions. Online homework help can prove that such methods can tabulate in two different ways of format. They are known as in SPSS as a crosstab. If you want to go for such tests, it is better to involve two steps. Bivariate Statistical Tests provide some kind of top qualities descriptive statistic. They can be utilized in both terms that include statistics and descriptive statistics also. It is a fact that this type of intension can be used in statistical testing. The main factor tends to good level of statistics. At the same time, it is difficult to say that sampling distribution is different in kind. This is important to look how a dependent variable differs in terms relation among independent variable. For an example, age and sex are some independent variables. The values may vary while depending on the......

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