Free Essay

Week 3 Homework

In: Computers and Technology

Submitted By Gobbish
Words 947
Pages 4
Week 3 homework
Exercise 7.1, problem 10a
The total number of pairs we can either include or not is 4^2-4=16. Any reflexive relation is a subset of this set of 12 elements; we know there are 2^12 such subsets.
Problem 10b
The number of decisions we can make for any symmetric relation is 4+ (16-4)/2=4+6=10.
The number of possible symmetric relations is 210.
Exercise 7.2, Problem 15a
a) Draw the digraph G1 (V1, E1) where V1 {a, b, c, d, e, f } and E1 {(a, b), (a, d), (b, c), (b, e), (d, b),
(d, e), (e, c), (e, f), (f, d)}.

Exercise 7.3, Problem 1
Draw the Hasse diagram for the poset ⊆, where{1, 2, 3, 4}.
(1,1)<(1,2)<(1,3)<(1,4)<(2,1)<(2,2)<...<(4,3)<(4,4 ). o------o------o------o------o------o--- ... ---o------o (1,1) (1,2) (1,3) (1,4) (2,1) (2,2) ... (4,3) (4,4)

3
1
2
4
3
1
2
4

Problem 6a . For A {a, b, c, d, e}, the Hasse diagram for the poset
(A, R) is shown in Fig. 7.23. (a) Determine the relation matrix for R. a b c d e a 1 1 1 0 0 b 1 1 0 1 0 c 1 0 1 1 0 d 0 1 1 1 0 e 1 0 0 0 1
Exercise 7.4, Problem 1a
Determine whether each of the following collections of sets is a partition for the given set A. If the collection is not a partition, explain why it fails to be.
a) A {1, 2, 3, 4, 5, 6, 7, 8}; A1 {4, 5, 6}, A2 {1, 8}, A3 {2, 3, 7}.
The Question A is a partition.
Problem 2a
There are only three ways, corresponding to the partition A_1 = {1,2,8}, A_2 = {3,4}, A_3 = {5,6,7}, the partition A_1 = {1,2}, A_2 = {3,4,8}, A_3 = {5,6,7}, and the partition A_1 = {1,2}, A_2 = {3,4}, A_3 = {5,6,7,8}. The point is that the given requirements almost completely determine the sets A_1 and A_2 and A_3; we just need to choose which set 8 goes into, and there are three different choices we can make in doing that.
Exercise 8.1, Problem 4
A = members that bring hot dog B= members that bring fried chicken C = members that bring salads D = members that bring desserts n(A) = 21 n(B) = 35 n(C) = 28 n(D) =32 n(A∩B) = 13 ; n(A∩C)=10; n(A∩D) = 9; n(B∩C) = 12 ; n(B∩D)=17 ; n(C∩D)=14; n(A∩B∩C)=4 ; n(A∩B∩D)=4; n (A∩C∩D)=5;n(B∩C∩D)=7 ;n(A∩B∩C∩D)= 2
a) 7
b) Zero
c) 17
Problem 12
C (n,r)= n!/r!(n-r)! =12! /9! (12-9)! = 220 220 entries = Troy has 220 ways to select nine marbles from a bag of twelve.
Exercise 8.2, Problem 4
a) We need to find the number of sequences with exactly 4 distinct numbers. There are (7 choose 4) ways of choosing four numbers, say a_1, a_2, a_3, a_4 from the numbers 1 through 7. Now we need to find the number of sequences that contain the selected numbers a_1, a_2, a_3, a_4 each at least once, but contain no other numbers.
There are 4^10 sequences that contain no other numbers besides a_1, a_2, a_3, a_4. Now we restrict our attention to these 4^10 sequences only.
Out of these 4^10 sequences, the number of sequences that are *missing* at least one of a_1, a_2, a_3, a_4, by the inclusion-exclusion principle, is sum of numbers of sequences missing a_i's taken one at a time - sum of numbers of sequences missing a_i's taken two at a time + sum of numbers of sequences missing a_i's taken three at a time - sum of numbers of sequences missing a_i's taken four at a time = (4 choose 1)*3^10 - (4 choose 2)*2^10 + (4 choose 3)*1^10 - (4 choose 4)*0^10. So the number of sequences that contain the selected numbers a_1, a_2, a_3, a_4 each at least once, but contain no other numbers, is 4^10 - (4 choose 1)*3^10 + (4 choose 2)*2^10 - (4 choose 3)*1^10 + (4 choose 4)*0^10. Therefore, the overall number of sequences with exactly 4 distinct numbers (i.e. the number of functions satisfying |f(A)| = 4) is (7 choose 4) * [4^10 - (4 choose 1)*3^10 + (4 choose 2)*2^10 - (4 choose 3)*1^10 + (4 choose 4)*0^10] = 35*(1048576 - 4(59049) + 6(1024) - 4(1) + 0) = 28648200. b) We need to find the number of sequences with at most 4 distinct numbers. The number of sequences with exactly 1 distinct number is clearly 7. Using similar reasoning as in part a), we find that the numbers of sequences with exactly 2, 3 distinct numbers, respectively, are (7 choose 2) * [2^10 - (2 choose 1)*1^10 + (2 choose 2)*0^10] = 21462, and (7 choose 3) * [3^10 - (3 choose 1)*2^10 + (3 choose 2)*1^10 - (3 choose 3)*0^10] = 1959300. From part a) the numbers of sequences with exactly 4 distinct numbers is 28648200. Therefore, the overall number of sequences with at most 4 distinct numbers (i.e. the number of functions satisfying |f(A)| <= 4) is 7 + 21462 + 1959300 + 28648200 = 30628969.

Similar Documents

Premium Essay

Intro to Psych Homework Week 3

...Homework Assignment Week 3 Critical and Creative Thinking Questions—Page 169 2. What are some examples of ways in which observational learning has benefited you in your life? Are there instances in which observational learning has worked to your disadvantage? Our book defines observational learning as learning new behavior or information by watching others. Some examples of ways in which observation learning has benefited me in my life are cooking, parenting, and work ethic. Watching my mother cook when I was little made me want to learn how and that’s how I now have the ability to cook meals for my own family without assistance. Parenting was another thing that I got from my mother; she was a single mother and was still able to provide for her two children without male figure in the picture. She was both a father and mother and I try to be that same parent with my children because of her. Work ethic is something else that I got from watching my sister and mother. They were always very dedicated, responsible, and punctual to their jobs and that’s how I am now. Observational learning can work to your disadvantage; it all just depends on the what, for example, driving. Growing up my mother and sister never used to wear their seatbelts therefore when it was time for me drive, I never wore my seatbelt. Very soon, I learned that I should my seatbelt if I didn’t want to get ticketed every time I was caught. Now, I don’t go anywhere without wearing my seatbelt and neither does...

Words: 755 - Pages: 4

Free Essay

Netw430 Week 3 Homework

...Week 6 homework 1. (TCO 5) Which component of an Intelligent Storage System provides the interface between the storage system and the host? a. The Front End b. The Cache Memory c. The Back End d. The Physical Disks 2. (TCO 5) Which component of an Intelligent Storage System is made of semiconductor memory where data is placed temporarily? a. The Front End b. The Cache Memory c. The Back End d. The Physical Disks 3. (TCO 5) What is the smallest unit of cache that can be allocated? a. book b. chapter c. section d. page 4. (TCO 5) What is used by cache memory to indicate whether data in cache has been written to disk or not? a. A dirty bit flag b. A grimy bit flag c. An uncommitted flag d. A committed flag 5. (TCO 5) What term is give used to describe an operation where the required data was found in cache? d. Read loss e. Read miss f. Read find d. Read hit 6. (TCO 5) Select two protocols that are used as the transport mechanism when implementing IP SAN storage systems. g. IPX/SPX b. iSCSI c. FCIP d. SNA 7. (TCO 5) Which protocol is a host-based encapsulation of SCSI I/O over IP using an Ethernet NIC card or an HBA? h. TCP/IP i. FC j. FCIP d. iSCSI 8. (TCO 5) Which protocol is extensively used in disaster-recovery implementations where data is duplicated on disk or tape to an alternate site? k. TCP/IP l. FC c. FCIP d. iSCSI ...

Words: 317 - Pages: 2

Premium Essay

Week 3 Homework

...A = Atr is equal to the number of matrices that i construct selecting the entries in the diagonal and above. 1+2+3+4+5+6 = 21 Answer: 21 Exercise 7.3:   a) Relation matrix is M=1 1 1 1 10 1 0 1 10 0 1 1 10 0 0 1 10 0 0 0 1 b) I will do it by hand c) Work: Using the Fig 7.23 For k = 1 e is the only vertex that has no edges starting at it Then we remove e Result: e For k = 2 d is the only vertex that has no edges starting at it Then we remove d Result: d < e For k = 3 b and c are the only vertices that has no edges starting at it we select c (it can be b too) Then we remove c Result: c<d<e For k = 4 b is the only vertex that has no edges starting at it Then we remove b Result: b<c<d<e For k = 5 (k =n) a is the only vertex that has no edges starting at it Then we remove a Result: a<b<c<d < e Answer: a < b < c < d < e Exercise 7.4: Work: a) Since A1UA2UA3 = A and AiAj = (i,j I={1,2,3}, ij} , yes {A1,A2,A3} it is a partition of A Answer: Yes b) Since A1A2 ={d} then {A1,A2,A3,A4} is a not a partition of A Answer: No Work a) We have to add 8 into one set (only one) to construct a partition of A Then we can do this in 3 ways Answer: 3 b) We must a place 7 and 8 in the 3 sets (7 on 1 set and 8 on another set) Since A1= 3 we must add one element here ( 7 or 8) If we add 7 to A1 then 8 must be placed into A2 or A3 (2 ways) If we......

Words: 2227 - Pages: 9

Free Essay

Mgmt 520 Week 3 Homework

...Andrea Grigsby MGMT 520 Week 3 Homework You will be able to upload both attachments in the same Dropbox. The Dropbox allows you to attach multiple documents in the same submission. Failure to submit your shepardized case will result in a loss of 10 points. You will not be able to submit it after your assignment has been graded. Your assignment is due by Sunday, end of Week 3, 11:59 p.m. (MT). (Note: You will not submit anything to the Homework CASE Dropbox. Questions 1-6: Week 3 Homework answers (there are 6 questions total). While viewing the Nadel v. Burger King & Emil case answer the following questions: 1. What court decided the case in the assignment? (2 points) Answer: Court of Appeals Ohio, First District, Hamilton County 2. What must a party establish to prevail on a motion for summary judgment? (3 points) Answer: In order to prevail on a motion for summary judgment, a movant has the burden to demonstrate that no genuine issue of material fact remains to be litigated; that is entitled to judgment as a matter of law, and that it appears from the evidence, when viewed most strongly in favor of the nonmoving party, that reasonable minds can come to but tone conclusion and that conclusion is adverse to the non-moving party. The movant in this case would be the Nadel family. Nadel v. Burger King Corp., 1997 WL 266762 (Ct. App, 1st Dist., Ohio) 3. Briefly – state the facts of this case, using the information found in the case in LexisNexis.......

Words: 1284 - Pages: 6

Premium Essay

Mgmt 597 Week 3 Homework

...MGT End of Chapter Questions – Week 3 Lauren Wilkes Mgmt 597 Chapter 22.10 In the case of Holly Hill Acres, Ltd. V Charter Bank of Gainsville, Holly Hill purchased land from Rogers and Blythe giving them a promissory note and purchase money mortgage. The note stated, “this note with interest is secured by a mortgage on real estate, of even date herewith, made by the maker hereof in favor of the said payee, and shall be constructed and enforced according to laws of the State of Florida” (HOLLY HILL ACRES, LTD., a Limited Partnership, Appellant, v. CHARTER BANK OF GAINESVILLE, a Banking Corporation, et al., Appellees., 1975). The promissory note was issued to Rogers and Blythe, Rogers and Blythe later took a loan from Charter Bank, in order to secure the loan, they transferred the promissory note they had created with Holly Hill. After Holly Hill defaulted, Charter Bank sued to recover on Holly Hill’s promissory note, the question being if the reference to the mortgage in the note makes it non-negotiable. First, it would have to be determined if Charter Bank was a holder in due course, they do fit the books description “a holder who takes a negotiable instrument for value, in good faith, and without notice that is defective or overdue” (Cheeseman, 2010). Which according the case the lower court did agree with. Although the court on appeal found the note was non-negotiable because it incorporated the terms of the purchase money mortgage. Now the bank was not a......

Words: 938 - Pages: 4

Premium Essay

Week 3 Homework

...WEEK 3 Homework * * * What is the relationship between a firm’s life cycle stage and its ability to accurately forecast sales? Why is this the case, and how do capital suppliers respond?  Why is so much emphasis placed on forecasting sales and cash balances in building proformas and projections? * * * Professor, class,  * * There is a tight relationship between a firm's life cycle stage and its ability to accurately forecast sales. The earlier a venture is at its life cycle stage the more difficult it will have to accurately forecast its sales. It is usually easier to forecast a firm being at the later stages  of life cycle such as maturity compared to early stage firms that have not operated yet. Firms at the early life cycle stage do not have any historical sales and records that are the crucial element to guide the future performances. Capital suppliers emphasize a lot on forecasting sales that is an efficient way to see future performances and results  of the ventures they are about to finance  * * * * * * * * * Chapter 6: Discussion Question: #4 p. 223 Why is it usually easier to forecast sales for seasoned firms in contrast with early-stage ventures? We usually forecast sales efficiently based on an horizontal analysis in other words, based on sales from previous years. The difficulty in forecasting sales for early stage ventures rely on the fact the ventures do not have any past......

Words: 1583 - Pages: 7

Premium Essay

Homework Week 3

...Homework Week 3 September 22, 2013 DeVry University Online Operant conditioning sometimes referred to as instrumental conditioning is a method of learning that occurs through rewards and punishments for behavior. Through operant conditioning, an association is made between a behavior and a consequence for that behavior. A good example of Operant conditioning is: employees finishing projects to receive praise or promotions (Cherry, 2013). Observational learning occurs when one observes another’s behaviors, which enables one to reenact those behaviors. In the workplace observational learning is used in a few ways. For example: whenever a manager started to train an employee they used instructional videos, so that the new employees could observe the job functions they were to undertake. Next, normally the manager would take the new employees into the actual work area that they would occupy and allow them to observe someone performing the job task. After that, the manager would pair a new employee with an employee that performed their job title well enough to train another employee. This allowed the new employee to observe the other employee, which enabled the new employee to learn though observing the other employees behaviors (Whitaker, 2012). The social learning theory, a system of learning most commonly associated with behaviorist Albert Bandura, is most commonly applied in educational settings. You can also apply this theory, which argues that people learn from each......

Words: 965 - Pages: 4

Premium Essay

Fasb Codification Week 3 Homework

...AC540 Week 3 Assignment Please complete the below problems and submit your answers in the Week 3 Dropbox. See "Syllabus/Due Dates for Assignments & Exams" for due date information. 1. In the Course Home tab of your course shell, click on “FASB Codification Access.” Scroll to the bottom of the page and click on “For tutorials please click on the link here.” Watch and listen to the four tutorial modules and answer the following questions with information you learned in the tutorial, your book and through Internet research: a. Why was codification needed? Ultimately the Codification was needed to simplify access, improves accuracy of research and mitigates risk of non-compliance. The research process is now streamlines, there are real-time updates, and it assists with the IFRS convergence efforts. b. What is the goal of codification? FASB had three primary goals when creating the codification: 1. Simplify user access by codifying all authoritative US GAAP in one spot. 2. Ensure that the codified content accurately represented authoritative US GAAP as of July 1, 2009. 3. Create a codification research system that is up to date for the released results of standard-setting activity. c. What authoritative literature does the codification supersede? The codification in Statement No. 168 supersedes Statement No. 162 - The Hierarchy of Generally Accepted Accounting Principles. d. How is the codification structured? Include as......

Words: 1128 - Pages: 5

Premium Essay

Nt1110 Week 3 Homework

...Doctor: A doctor would use a desktop like the gamer, but they wouldn’t need the computing power because they are not running any intense software similar to the author. They would need extra space to keep patient data if need be so they would need a large HDD. Most likely going with the HP Pavilion. Teacher: A teacher would more than likely have both of these types of computers but I would see a laptop being much more convenient. Being able to bring all of their grades around from classroom to classroom without bringing an entire desktop with them would be a life saver. Unit 2 Assignment 1: Transfer Time Table 1: Calculating transfer time File Size | Transfer Rate | Transfer Time | 100 MB | 56 Kbps | 4 Hrs | 100 MB | 4 Mbps | 3 mins | 2 GB | 56 Kbps | 79 Hrs | 2 GB | 4 Mbps | 1 Hour | Table 2: Calculating file size Transfer Rate | Transfer Time | File Size | 56 Kbps | 31 Mins | 13 KB | 4 Mbps | 10 Mins | | 56 Kbps | 4 Hrs | | 4 Mbps | 2 Hrs | | A much higher transfer rate equals less transfer time to download a file. So if you’re trying to download a very big file, I would suggest finding the best download speed around you and use that if you have a very weak download speed....

Words: 385 - Pages: 2

Free Essay

Cj 312 Week 3 Homework

...livor and rigor mortis, time since death can only be accurately measured for the first two or three days after death. In contrast, by calculating the age of immature insect stages feeding on a corpse and analyzing the necrophagous species present, postmortem intervals from the first day to several weeks can be estimated. I selected cased 1, 2, and 3 for the this weeks assignment. It appears that in each case, the time elapsed between the discovery of the bodies was all different. In case 1, the remains of a female child were recovered from shallow grave on a narrow ledge in Oahu, Hawaii (Case Studies). In this case it is estimated that the child had been deceased for approximately 52 days. In case 2, the body of a female was found along a highway. The victims brother had reported her missing just four days before her body was discovered. In case 3, the body of Lori Ann Auker was discovered on a dirt road. It is estimated that her body had been decaying for close to 25 days. In all three cases, the victims were female and the bodies were discovered outside. They had all been exposed to different elements. They were also all found in different stages of decomposition. In cases 2 and 3, weather data was used to determine the environmental conditions to which the bodies and insects were exposed. In case 1, the beetles that were found on the child appeared to have been in their adult stage. The skins of the beetles were in fairly good condition which suggested that they had......

Words: 765 - Pages: 4

Premium Essay

Unit 3 : Week 3 - Homework 6

...Unit 3 : Week 3 - Homework 6 ------------------------------------------------- Top of Form |     | Question 1.1. real property - In English Common Law, real property is any subset of land that has been legally defined and the improvements to it made by human efforts: any buildings, machinery, wells, dams, ponds, mines, canals, roads, various property rights, and so forth.              | Question 2.2. personal property - Personal property is generally considered property that is movable, as opposed to real property or real estate. In common law systems, personal property may also be called chattels or belongings.              | Question 3.3. eminent domain - The power the government has to obtain the property of an individual even without the person's full consent. In most countries, including the U.S., the land owner will be compensated for the land at fair market value. This power allows the government to seize land to be used in public enterprises such as roads, schools, or utilities              | Question 4.4. condemnation - the seizure, as of property, for public use.              | Question 5.5. inverse condemnation - is a term used in the law to describe a situation in which the government takes private property but fails to pay the compensation required by the 5th Amendment of Constitution. In some states the term also includes damaging of property as well as taking it. In order to be compensated, the owner must then sue the government. In such...

Words: 1514 - Pages: 7

Premium Essay

Week 3 Homework Fin 6000

...Week 3 Assignment 1 ------------------------------------------------- 1. Calculating the Number of Periods At 8 percent interest, how long does it take to double your money? To quadruple it? FV = PV (FVF) 8%, t = ? $2 = $1 (FVF) 8%, t = ? $2/ 1 = 2.0; so for FVF at 8 %, “t” is approximately 9 years. 2. Perpetuities An investor purchasing a British consul is entitled to receive annual payments from the British government forever. What is the price of a consul that pays $160 annually if the next payment occurs one year from today? The market interest rate is 4.5 percent. PV = C / r PV = $160 / 0.045 PV = $3,555.56 3. Present Value and Multiple Cash Flows Investment X offers to pay you $6,000 per year for nine years, whereas Investment Y offers to pay you $8,500 per year for five years. Which of these cash flow streams has the higher present value if the discount rate is 9 percent? If the discount rate is 21 percent? PVA = C ({1 – [1/(1 + r)]^t} / r X @ 9%: PVA $6,000 {[1 – (1 / 1.09)^9] / .09} = $35,974.48 Y @ 9%: PVA $8,500 {[1 – (1/1.09)^5] / .09} = $33,062.04 X @ 21%: PVA $6,000 {[1 – (1 / 1.21)^9] / .21} = $23,432.61 Y @ 21%: PVA $8,500 {[1 – (1/1.21)^5] / .21} = $24,870.87 4. Calculating EAR First National Bank charges 15.1 percent compounded monthly on its business loans. First United Bank charges 15.5 percent compounded semiannually. As a potential borrower, which bank would you go to for a new loan? EAR = [1 + (APR / m)]^m – 1 ...

Words: 674 - Pages: 3

Free Essay

Week 3 Homework

...occupation both the organization and the representative would bear the obligation. You are an employee at a nice paper mill and want to impress the boss by burning the midnight oil (but not too close to the wood pulp). For four consecutive weeks, you work forty-five, forty-two, thirty-nine, and thirty-one hours. If you are a nonexempt employee covered by the Fair Labor Standards Act, how many hours of overtime pay, if any, would you be entitled to? What would be the rate? Initially knowing that an non-exempt employee under the Fair Labor Standards Acts of 1938 must be paid up to $7.25 a hour and work up to 40 hours a week. Also knowing that any hours worked after 40 hours per week must be paid 1.5 times to that individuals regular pay rate. So in this scenario the worker is qualified for his or her week by week compensation of $290 every week for two weeks. Likewise, he or she is qualified for additional time pay of $54.40 (5 hours x $10.88) for the first week, for an aggregate of $344.40; for the second week, utilizing the same figuring his or her pay is $290 (consistent pay) and $21.76 (2 hours extra time), for a sum of $311.76. For the second two weeks, on the other hand which the representative does not work the standard 40 hour week, his or her compensation depends on 39 and 31 hours at $7.25 an hour. https://everest.vitalsource.com/#/books/9781285415253/pages/78955679 Cengage Advantage Books: Business Law: Text and Exercises, 7e, 7th Edition...

Words: 610 - Pages: 3

Premium Essay

Week 3 Homework

...Architect, Real Estate Consultant, and General Contractor.(2) Recruit and train managers for the plant.(3) Create pre-production and production plans.(4) Create building concept and design(5) Procure building site, all required permits and approvals(6) Construct building(7) Landscape Site(8) Recruit Operations Personnel(9) Equipment, materials and fleet purchases(10) Equipment Installation(11) Create product and pre-production plans(12) Begin production and distribution | Project Product | The following are the project product that are necessary in order for the project to have a successful outcome. * Select resources such as: Architect, Real Estate Consultant, and General Contractor. * Recruit and train managers for the plant. * Create pre-production and production plans. * Create building concept and design * Procure building site, all required permits and approvals * Construct building * Landscape Site * Recruit Operations Personnel * Equipment, materials and fleet purchases * Install Equipment * Create Product Distribution Plan and Pre-production Plan * Start Up Production and Distribution | | Project Deliverables | The following are the expected deliverables this project expects to accomplish upon completion. (1) Double Total Sales within the next 10 years (2) Develop and market new products based on the company’s plastics experience (3) Reduce dependence on equipment suppliers (4) Reach first or second in regional......

Words: 304 - Pages: 2

Premium Essay

Ec301 Week 3 Homework

...Rose Sandeen Week 3 Homework Chapter 8 You are given the following equations for the aggregate demand (AD) and short-run aggregate supply (SAS) curves: AD: Y = 1.25Aᴩ + 2.5Mˢ/P SAS: Y = 11,250 - 20W + 1,000P where Y is real GDP, Aᴩ is the amount of autonomous planned spending that is independent of the interest rate, Mˢ is the nominal money supply, P is the price level, and W is the nominal wage rate. Assume that Aᴩ equals 5,000, Mˢ equals 2,000, W equals 50, and natural real GDP, Yᴺ, equals 11,250. Use the values for the amounts of autonomous planned spending that is independent of the interest rate and the nominal money supply to derive the equation for the aggregate demand curve. Compute the amount of aggregate demand when the price level equals 2.0, 1.25, 1.0, 0.8, and 0.5. Graph the aggregate demand curve. Answer: The equation for aggregate demand is Y = 6,250 + 5,000/P. See below graph for aggregate demand curve. Price Level |2.0 |1.25 |1.0 |0.8 |0.5 | |Aggregate Demand |8,750 |10,250 |11,250 |12,500 |16,250 | | Derive the equation for the short-run aggregate supply curve, given that the nominal wage rate equals 50. Compute the amount of short-run aggregate supply when the price level equals 2.0, 1.25, 1.0, 0.8, and 0.5. Graph the short-run aggregate supply curve. Answer: The equation for the short-run aggregate supply curve is Y = 10,250 + 1,000P. See below graph for short-run aggregate supply curve. Price Level |2.0 |1.25 |1.0 |0.8 |0.5 |......

Words: 796 - Pages: 4