Index Introduction ………………………….……………………………………….……3 Industry analysis ……………………………..………………….……...…......4 Competitors strategy ……………………….……………………………………. Microsoft – A differentiator………………………….…......7 Sony – A differentiator ……………………….…………………9 Analysis of competition………………………………………………………11 Nintendo’s strategy …………………………………..……………………….14 SWOT ………………………….…………………………………………………….17 Recommendations …………….………………………………………………18 References ……………………………..………………………………………….20 Introduction The
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TECHNICAL REPORT PARAMETER ESTIMATION OF SIR MODEL FOR THE SPREAD OF DENGUE DISEASE HAZWANI BINTI AHMAD (2009224096 - TR12/20) NURUL HAMIZAH BINTI MOKHTAR (2009283442 - TR12/20) SITI ATIQAH BINTI RAMLI (2009652882 - TR12/20) UNIVERSITI TEKNOLOGI MARA TECHNICAL REPORT PARAMETER ESTIMATION OF SIR MODEL FOR THE SPREAD OF DENGUE DISEASE HAZWANI BINTI AHMAD (2009224096 - TR12/20) NURUL HAMIZAH BINTI MOKHTAR (2009283442 - TR12/20) SITI ATIQAH BINTI RAMLI (2009652882 - TR12/20) Report
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CATECHISM OF THE CATHOLIC CHURCH Table of Contents PROLOGUE I. The life of man - to know and love God nn. 1-3 II. Handing on the Faith: Catechesis nn. 4-10 III. The Aim and Intended Readership of the Catechism nn. 11-12 IV. Structure of this Catechism nn. 13-17 V. Practical Directions for Using this Catechism nn. 18-22 VI. Necessary Adaptations nn. 23-25 PART ONE: THE PROFESSION OF FAITH SECTION ONE "I BELIEVE" - "WE BELIEVE" n. 26 CHAPTER ONE MAN'S CAPACITY FOR GOD nn. 27-49 I. The
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This is page i Printer: Opaque this A Mathematical Introduction to Fluid Mechanics Alexandre Chorin Department of Mathematics University of California, Berkeley Berkeley, California 94720-3840, USA Jerrold E. Marsden Control and Dynamical Systems, 107-81 California Institute of Technology Pasadena, California 91125, USA ii iii A Mathematical Introduction to Fluid Mechanics iv Library of Congress Cataloging in Publication Data Chorin, Alexandre A Mathematical Introduction
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University of Aberdeen, UK Andrew Whitaker, Queen’s University Belfast, UK For further volumes: http://www.springer.com/series/8902 Péter Hraskó Basic Relativity An Introductory Essay ´ Emeritus Professor at University of Pecs, Hungary 123 Péter Hraskó University of Pécs H-7633 Pécs Szántó Kovács János u. 1/b Hungary e-mail: peter@hrasko.com ISSN 2191-5423 ISBN 978-3-642-17809-2 DOI 10.1007/978-3-642-17810-8 Springer Heidelberg Dordrecht London New York Ó Péter Hraskó 2011
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This page intentionally left blank A Course in Financial Calculus A Course in Financial Calculus Alison Etheridge University of Oxford CAMBRIDGE UNIVERSITY PRESS Cambridge, New York, Melbourne, Madrid, Cape Town, Singapore, São Paulo Cambridge University Press The Edinburgh Building, Cambridge CB2 8RU, UK Published in the United States of America by Cambridge University Press, New York www.cambridge.org Information on this title: www.cambridge.org/9780521890779 © Cambridge University
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University of Florence Faculty of Economy Master’s Degree in Bank, Insurance and Financial Markets Thesis in Applied Statistics for Banks and Insurances Credit Risk Models: Single Firm Default and Contagion Default Analysis Supervisor: P rof essor Fabrizio Cipollini Student: Marco Gambacciani Academic Year 2009/2010 Contents Introduction . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1 Structural Models 1.1 Terminal Default . . . . . . . . . . . . 1.2 First Passage Models
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y(x)的函数，J=J[y(x)]。 图 2.1.1 两点间任一曲线的长度 例 2：历史上著名的变分问题之一——最速降线问题，如果 2.1.2 所示。设在不同铅垂线上 的两点 P1 与 P2 连接成某一曲线，质点 P 在重力作用下沿曲线由点 P1 自由滑落到点 P2，这 里不考虑摩擦作用影响，希望得到质点沿什么样的曲线滑落所需时间最短。 图 2.1.2 最速降线问题 选取一个表示曲线的函数 y(x)，设质点从 P1 到 P2 沿曲线 y=y(x)运动，则其运动速度为： v 1 y 2 ds dx dt dt 其中，S 表示曲线的弧长，t 表示时间，于是： dt 1 y 2 dx v 1 设重力加速度为 g，则 v 2 gy 。 因为 P1 和 P2 点的横坐标分别为 x1 到 x2，那么质点从 P1 到 P2 所用时间便为： J [ y ( x)] x2 1 y 2 x1 2 g[ y ( x 1 ) y ( x ) x2 dx 1/ 2
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19-1. Intrinsic temperature is reached when the intrinsic carrier density ni equals the lowest doping density in the pn juinction structure (the n-side in this problem). Thus È q Eg 1 1 ˘ Ï ¸ ni(Ti) = Nd = 1014 = 1010 exp Í - 2k ÌT - 300˝˙ Î Ó i ˛˚ Solving for Ti using Eg = 1.1 eV, k = 1.4x10-23 [1/°K] yields Ti = 262 °C or 535 °K. 19-2. 1 1 N-side resistivity rn = q m N = -19)(1500)(1014) = 43.5 ohm-cm (1.6x10 n d 1 1 P-side resistivity rp = q m N = = 0.013 ohm-cm p a (1.6x10-19)(500)(1018)
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MATH 275: Calculus III Lecture Notes by Angel V. Kumchev Contents Preface . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . Lecture 1. Lecture 2. Lecture 3. Lecture 4. Lecture 5. Lecture 6. Lecture 7. Lecture 8. Lecture 9. Lecture 10. Lecture 11. Lecture 12. Lecture 13. Lecture 14. Lecture 15. Lecture 16. Lecture 17. Lecture 18. Lecture 19. Lecture 20. Lecture 21. Lecture 22. Lecture 23. Three-Dimensional Coordinate Systems . . . . . . . . . . .
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