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Submitted By thecrow73

Words 1158

Pages 5

Words 1158

Pages 5

A. Create a story problem using one of the above real-world scenarios as a basis, including realistic numeric values, by doing the following:

1. Describe the real-world problem.

I was looking into phone plans and stumbled upon T-Mobile, and I decided that I needed a cell-phone and took a look at the plans. T-mobile had one plan that was 50 dollars a month and is unlimited talk, text and web, T-Mobile also has a plan for 30 dollars a month for 1,500 talk and text minutes. After you go through your allotted 1,500 talk and text time was up, the cost skyrockets up to 10 cents a minute. 10 cents a minute comes out to 6.00 per hour, I thought in my head. I decided that instead of jumping into a decision about phone plans, that I should first go home and do the math. I wanted to figure out which plan was going to be the most cost effective, and which plan would suite my needs the best.

2. Explain all needs (e.g., financial, non-financial, situational) of the hypothetical consumer.

The needs include many different factors:

• The first and most important factor how much do you use your phone? The breaking point on the problem today is 200 talk or text above the 1500 minute plan and I will be paying less up front but more on the back end which is no good. If I chose the 1500 minute plan, I will not want to be going over the 1500 minutes as then the cost would go up to 10 cents a minute or 6.00 per hour.

• Is this replacing a work or office phone? If I am going to use this phone for several purposes it is more valuable to me and it is easier to justify higher costs.

• What should I do right now if I am unsure but need a phone? I would say the best starting point unless I use my phone all the time is to try out the 30 dollar a month plan. Saving 20 dollars right off the bat and then closely monitoring your minutes over the next couple…...

... even a small amount of inadequate sleep, resulting in an increase in the hunger hormone, will make it even harder. Physical Performance The average person can learn to understand just how important a role sleep has in their fitness by taking a look at most athletes. Athletes must maintain a high level of fitness in order to consistently perform well and inadequate sleep can have a significant negative impact on that physical performance. Sleep deprivation has been shown to decrease stamina leading to increased fatigue, slow reaction times making split-second decisions more difficult, and even effect mood which can kill an athletes drive. An increase in physical performance is often thought to go hand in hand with an improvement in fitness. This is particularly important when it comes to athletics. An athlete is constantly training and perfecting the skills of their respective sport, so investigating anything that might hurt or help that effort is always being looked into. To determine if sleep is something that may impact performance, various sports and exercise research centers in the United Kingdom conducted a study to investigate Insufficient Sleep: The Silent Enemy of Fitness 5 whether the athletic skills of rugby players were effected by sleep deprivation. They also tested if a dose of caffeine (for energy and focus) or creatine (to aid in preventing muscle fatigue) remedied any loss in the sleep deprived players. The results showed a significant......

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...Part A: A couple is comparing two daycares to determine the best option for their 1 year old son. A home-based daycare charges a flat rate of $5 per hour. A center-based daycare charges a fixed rate of $185 per week, providing 40 hours of childcare. Above 40 hours, the center-based daycare then charges a fixed rate of $8 per hour. The couple determines that the driving distance to each daycare is the same, thus driving expenses do not need to be considered. The couple will require 50 hours of childcare per week and are looking for the cheapest daycare, as they are soon expecting their second child. Part B: 1. “y” represents total cost per week in dollars “x” represents hours Home based daycare: y=5x Center based daycare: y=185+8(x-40), x≥40 hours 2. For the home based daycare, they charge a flat rate of $5 per hour. Thus the couple can calculate their cost by multiplying $5 by the number of hours they need for childcare each week. For the center based daycare, the couple can calculate their weekly cost by adding the $185 fixed rate to the cost of any additional hours needed after 40. Thus, if they are going over 40 hours, they would subtract 40 hours from the total number of hours needed and multiply that by the $8 the center charges for each additional hour. 3. y=5x y=185+8(x-40) y=185+8(x-40) 5x=185+8x-320 5x=-135+8x 5x-8x=-135+8x-8x -3x=-135 -3 -3 x=45 y=5x y=5(45) y=225 Thus, both the center based and the home...

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...x 0 45 30 Y = (-2/3)x + 30 30 0 10 Y intercept: (0,30) Y = -2/3(x) + 30 Y = 0 + 30 Y= 0 X intercept: (45,0) 0 = -2/3 (x) + 5 0 – 30 = -2/3 (x) +30 -30 -30 = -2/3 x 2/3(x) = 30 X = 30 ● 3/2 X = 45 Height of the beam 30 ft. away from the face of building is 10 ft. Y = -2/3 (x) + 30 Y = -2/3 30 + 30 Y = -20 + 30 Y = 10 Y represents the height above the ground in feet. 35 Y intercept (0, 30) 30 25 The graph depicts a visual representation of the path of the laser beam using only quadrant I. Quadrants ll, lll, and lV are not needed to show the direction of the laser beam. Y = (-2/3)x + 30 Y = (-2/3)x + 30 20 When the laser beam is shined at the ground at 30 ft. up it will hit the ground at 45 ft. from the face of the building using the equation Y=(-2/3)x + 30. 15 10 (30, 10) 5 X Axis 0 0 Y Axis 10 20 30 The height of the beam 30 ft. away from the face of the building is 10 ft. X intercept (45, 0) 40 50 X represents the distance from face of bldg. in ft. The laser beam hits the side of the building at 30 ft. which is the Y intercept (0, 30) and the laser beam hits the ground at 45 ft. from the face of the building at the X intercept (45, 0). X intercept (45, 0). ...

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...000278346/Arpe/QLT1 Task 212.1.2: Task 1 A. Complete the following graphs: 1. Graph the following values on a single number line. Value 1: 1 Value 2: 0 Value 3: -6 Value 4: ¾ Value 5: -1.7 B C E D A Page 1 of 6 000278346/Arpe/QLT1 Task 212.1.2: Task 1 2. Graph the following points on a single coordinate plane. Make sure to include labels for each quadrant of the coordinate plane. Point 1: (3,-2) Point 2: (0.0) Point 3: (-1,7) Point 4: (3,5) Point 5: (-4,-5) (-1,7) (3,5) (3,-2) ) (0,0) (3,-2) (-4,-5) Page 2 of 6 000278346/Arpe/QLT1 Task 212.1.2: Task 1 3. Graph the following functions on separate coordinate planes. In each graph, label each axis of the coordinate plane. Additionally, label each intercept as “x-intercept” or “y-intercept” and include the ordered pair. Whenever applicable, label the vertex as “vertex” and include the ordered pair Function 1: y = 2x – 1 (3,5) (2,3) ( ½ ,0) (0,-1) x-intercept y-intercept (-1,-3) Page 3 of 6 000278346/Arpe/QLT1 Task 212.1.2: Task 1 Function 2: y = (-3/4)x + 5 (-4,8) x-intercept (0,5) (4,2) y-intercept (6 ½,0) (8,-1)) Page 4 of 6 000278346/Arpe/QLT1 Task 212.1.2: Task 1 Function 3: y = x2 – 4 (-3,5) (3,5) (-2,0) x-intercept (2,0) x-intercept (-1,-3) (1,-3) (0,-4) Vertex Page 5 of 6 000278346/Arpe/QLT1 Task 212.1.2: Task 1 Function 4: y = -3x2 – 6x –......

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...A1) A parent is looking for the best option for daycare for a child. A home-based option charges a flat rate of $10 per hour. A center-based option charges a fixed fee of $332.50 per week for 35 hours and then a fixed rate of $11 per hour for any hour provided over the set amount. Determine which option is most advantageous for the parent based upon the parents’ needs. A2) The parent works a 40 hour work week. Each of the daycare options is a half an hour away from the parent’s office. This means that the child is there for a total of 45 hours a week. The parent has federal holidays (10 holidays in 2014), the day after Thanksgiving, and Christmas Eve off so there will be weeks that the child will not be in daycare for the full week. The parent also receives two weeks of vacation each year. Other situations to consider are that the child and/or parent could get sick or they could take a short vacation and the child will not have to attend the daycare for the full week. A3) If the parent chooses to go with the home-based option, the parent will be charged a flat rate of $10 per hour. This option gives the parent the freedom to either take the child to daycare or to not and only be charged for the hours the child is there. If the child is there for 45 hours a week, the parent will pay $450 for that week; if the child is there for only 20 hours a week, the parent will pay $200 for that week. If the parent chooses to go with the center-based option, the parent will be charged...

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...QLT1 Task 5 Daycare Cost Analysis A.) Basic information: The Depp family is seeking child care for their 2 year old son Jack. The family needs care for approximately 42-50 hours per week. They have interviewed several care providers and have selected two providers in the vicinity of their employers and now need to decide between: one is family day care home that charges $5 per hour per child and the other is a child care center that charges $200 per week for 40 hours with an additional $10 per hour over 40 hours. Additional factors considered are that both facilities provide lunch and snacks, other facilities did not; as well the center will provide a 25% discount on a second child. Although the Depps have only one child however will be adding to their young family. 1.) Rates: i. Daycare rates: Home care $5/hour ii. Center $200/week for 40 hours + $10/hour over 40 hours 2.) Other expenses iii. Meals included with both facilities iv. Both located within 10 blocks of employer, transportation costs are negligible 3.) Other considerations v. Parents are state employees 37.5 hours per week + 1 hour lunch = 42.5 hours @ employer per week minimum vi. Currently have one child in need of care, but is considering another child in the next 1-2 years vii. Family day care home is 1 employee, no coverage for sick days/vacation; center has multiple staff members to...

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...BGA1 Task 4 308.1.8-05,12 The weighted average cost of capital for this company is 9.48%. Cost of capital is often used in net present value analysis as the discount rate, which is the rate that other investments would return that have similar risks. Cost of capital is the total of all of the actual costs of a company’s debts and equities. These costs include such factors as interest, tax expense, and equity costs. It is what percentage it costs the company to tie up its capital, so in order for an investment to be desirable, it must return a percentage greater than what it takes for the company to cover its capital costs. In a net present value analysis, the cost of capital is used to locate the factor from the present value table that will be multiplied by the cash flow to determine the present value of that cash flow. The present values of all of the cash flows will then be compared to the total investment to determine if it is an acceptable investment. If the present value is equal to or greater than the total investment, then the investment will likely be accepted. If the present value is less than the total investment, the investment should not be accepted. Cost of capital is used in the internal rate of return analysis by comparing the internal rate of return calculation to the cost of capital calculation. If the internal rate of return figure is equal to or greater than the cost of capital figure, then the investment is acceptable. If the......

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...QLT1 – Task 1 Competency 212.1.2: Solving Algebraic Equations A. 1. Graph the following values on a single number line • Value1: 1 • Value 2: 0 • Value 3: -6 • Value 4: ¾ • Value 5: -1.7 [pic] 2. Graph the following points on a single coordinate plane. Make sure to include labels for each quadrant of the coordinate plane. • Point 1: (3,-2) • Point 2: (0,0) • Point 3: (-1,7) • Point 4: (3,5) • Point 5: (-4,-5) Quadrant II Quadrant I [pic] Quadrant III Quadrant IV 3. Graph the following functions on separate coordinate planes. • Function 1: y= 2x − 1 y=2(0) – 1 0=2x – 1 y= 0 – 1 +1 +1 y= -1 1 = 2x /2 /2 ½ = x [pic] • Function 2: y= (–3/4)x + 5 y=(-3/4)0 + 5 0=(-3/4)x + 5 y= 0 + 5 -5 -5 y = 5 (0,5) -5 = (-3/4)x *4 *4 -20 = -3x /-3 /-3 6.67 = x (6.67,0) [pic] • Function 3: y=x2 – 4 y=02 – 4 0=x2 – 4 y=(-2) 2 – 4 y=(3)2 -4 y=(-3)2-4 y=-4 +4 +4 y = 4 – 4 y=9-4 y=9-4 4= x2 y = 0 y = 5 y = 5 √4 = √x2 2 = x [pic] • Function 4: y= –3x2 – 6x – 5 If x=0 then If x=-1 then y= –3(0)2 – 6(0) – 5 y= –3(-1)2 – 6(-1) – 5 y = 0 – 0 – 5 y...

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...A. 1. A. 2. Savings Plan A y= $20x + $400 10x+600=20x+400 -10x-400=-10x -400 200=10x /10 /10 20=x (# 0f months) Savings PlanB y= $10x + $600 y=10(20)+600 y=200+600 y=800 ($ saved) Savings Plan A X-intercept y=0 0=20x+400 -400=20x -400/20=x -20=X Savings PlanB X-intercept y=0 0=10x+600 -600=10x -600/10=x -60=x Solution A. 3. Both plans yield identical balances after 20 months at $800. Months Plan B Plan A -60 0 -20 0 0 600 0 400 2 620 2 440 Solution 3 630 3 460 1000 4 640 4 480 (20,800) y-intercept Quadrant II 5 650 5 500 800 (0,600) 6 660 6 520 600 Quadrant I 7 670 7 540 400 8 680 8 560 x-intercept (0,400) y-intercept x-intercept 200 9 690 9 580 (-60,0) (-20,0) 10 700 10 600 0 -70 -60 -50 -40 -30 -20 -10 0 10 20 30 11 710 11 620 X-Axis Months 12 720 12 640 13 730 13 660 Plan B y=10x+600 Plan A y=20x+400 14 740 14 680 Linear (Plan B y=10x+600) Linear (Plan A y=20x+400) 15 750 15 700 16 760 16 720 17 770 17 740 A.3a1. Plan B yields more at $740 vs. Plan A at $680. 18 780 18 760 A.3ac. Plan A yields more at $860 vs Plan B at $830. 19 790 19 780 A.4. The solution lies in quadrant 1 where the savings 20 800 20 800 begins until the intersection at (20,800). 21 810 21 820 x & y coordinates are all positive from month 1 through month 20 22 820 22 840 which means its Quadrant 1. 23 830 23 860 Y-Axis (Total Savings in $) ...

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...Why entrepreneurial organizations seek opportunities for innovation. In today’s business world, the organizations that fair the best in business society are often those organizations that strive to be more creative and innovative. These organizations do not follow in the footsteps of other companies; instead, they often use innovative ideas from others as a way to birth new ideas, products, or services of their own. Entrepreneurial organizations often distance themselves from their competition rather than compete with them. If another organization duplicates their ideas, products, or services—an entrepreneurial organization that is rich with innovation won’t back down, instead they create something new and better, adding a creative twist to what was old or duplicated. This level of creativity and strong determination allow these organizations to achieve long-term success. With that said, there are many reasons why entrepreneurial organizations seek opportunities for innovation. These reasons are: 1. Competitive Advantage: Organizations that maximize their creative and innovative skills often gain a competitive edge against their competitors. Developing a new edge or making a product or service better can mean survival or a way to stay ahead of the competition. The main element for staying ahead of the rest is innovation. Organizations that become more innovative, see things from a new perspective, take calculated risks, and become more agile. Gaining a competitive...

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...A1 Andrew has just moved to Los Angeles and bought a car and is looking for the best parking option that will allow him to save the most money. There are two parking garages by his work. One charges $40 per month and the other charges 20 cents per hour. Which option will be less costly for him? A2 Since Andrew is new to the area it is necessary that he find the cheapest parking option possible in order to cut down on expenses in the new city as he has just purchased a new car and had high moving costs. A3 Andrew’s two options are the monthly parking garage which charges $40 per month or the hourly parking garage which charges 20 cents per hour. B1 A work day has 8 hours A is the number of days the car will be parked. T will be the total price Monthly parking garage: (A-A)+40=T Hourly parking garage: (0.2 x 8)A=T B2 The monthly parking garage doesn’t charge by the day so having the days at zero just leaves the $40 charge. The hourly parking garage multiplies the rate by 8 hours since there are 8 hours in a work day. That is then multiplied by the total number of days in a month that the car will be parked. B3 We set both equations equal to each other in order to find the solution for the number of days. Set both equations equal to each other (A-A)+40=(0.2 x 8)A Subtract (A-A) 40=(0.2 x 8)A Multiply inside the parentheses (0.2 x 8) 40=(1.6)A Multiply (1.6)A 40=1.6A Divide both sides by 1.6 25=A A=25 days solution We...

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...Task 5 Moving Truck Cost Analysis The Thompsons have lived in Canada all their life but recently Mr. Thompson got a job offer he could not refuse. The new job will require they move to the west coast of the United States. This is going to require they move across the country from New Brunswick, Canada to Seattle, WA. Which is a total of 3200 miles. Although the company Mr. Thompson will be working for will reimburse them for the move, they still have a budget they need to stay under so they can have enough money for hotel stays, stocking the house with food, cleaning supplies etc. when they arrive. They are planning on leaving early and site seeing on the way but still arrive at least two weeks early so they have time to settle in. Arriving early though means there will be a big gap between paychecks so budgeting is very important. They narrowed it down to two companies, Acme Moving which charges $2.00 per mile and Lightening Moving that charges $1500 for the first thousand miles and $2.25 for each mile over 1000. They have to analyze the costs and figure out which one is going to be the best deal. The Equation: Lightening Moving Co. Lightening Moving charges $1500 for the first 1000 miles and then $2.25 for each mile over 1000. Let X = Amount of miles traveled 1500 = the initial cost of the first 1000 miles 3,200 = the total amount of miles traveled $2.25 per mile over 1000 miles therefore; 1500 + 2.25(X-1000) = Cost of moving over 1000 miles 1500...

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...Biochemistry Task 5 Lipids A. Adipose tissue stores fat in the body. The fat storage molecule is called a triglyceride. Triglycerides are composed of a glycerol attached to three fatty acids. In order to use a triglyceride for energy, the fatty acids are broken away from the glycerol. These fatty acids are considered free fatty acids. Free fatty acids are broken down, two carbons at a time by beta oxidation. Each two carbon unit becomes Acetyl CoA, which then enters the citric acid cycle. Also, during beta oxidation there are electrons and hydrogens that are removed from fatty acid. They are carried by NADH and FADH2 to the electron transport chain. They are used to form ATP from ADP and a phosphate. B. There are two types of fatty acids, saturated fatty acid and unsaturated fatty acid. Saturated fatty acids are saturated with hydrogen, meaning all the carbons in the chain are filled with hydrogen. Saturated fatty acid chains all look similar which makes it easy for them to build on one another. The force that holds them together is known as hydrophobic interactions. This allows fatty acids to be solid at room temperature. Saturated fatty acids are mainly from animal food sources. Unsaturated fatty acids will not be saturated with hydrogen, instead there is a double bond that lessens the amount of hydrogen in a chain. This double bond bends the tail and the structure becomes irregular. This irregularity doesn’t allow them to stack well, therefore unsaturated fatty...

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...Biochemistry Task 5 March 6, 2016 A. Triglycerides are the main make up of body fat in animals and humans as well as vegetable fat. Triglycerides are made up of glycerol and three fatty acids. Fats or lipids as a whole are not bad for you as they are used for energy, always in moderation, but there are different types of fats that you do need. Your body utilizes saturated fat very fast as opposed to other fats that has to go through different stages to be used. Triglycerides in food are digested and are processed in the liver combining it with a protein and then travel through your blood stream to your cells where they are then used for energy. Glycerol enters into the pathway through the Pyruvate and then onto Acetyl-CoA where it enters the Cori-cycle. From there it is transported to the electron transport chain where the end product is ATP. ATP is the body’s energy. Through beta oxidation fatty acids enters the pathway through the Acetyl-CoA. From here it moves the Cori cycle where they are then broken down into sugars and transported to the electron transport chain where ATP is the end product. Low fat diets are dangerous in that they strip the body of the process of this breakdown. Reduces energy stops the breakdown of fat for use in the digestive system gallbladder and liver. With this reduction the decrease of bile also stops the production of CCK or Cholecystokinin which signals the pancreas to release bile to breakdown the lipids. Simply the product will...

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...Stacy Raudman 000202145 JET2 Task 5 Introduction Custom Snowboards has been continually growing and is now considering expansion into Europe. There are a variety of options for expansion that the company can consider. The CEO, as should be, is concerned about the risks of expansion. He is specifically concerned about the affect on internal operations of the entity and how the company will react to external issues. The two options for expansion are building a new manufacturing facility to facilitate the expansion or merging with or acquiring a like company called European SnowFun. The options will be discussed in this report to the CEO as, in order for the expansion to move forward, a loan for one million dollars will be needed. A1Key Points Before moving forward, there are a few key points that could impact the bank officer's decision whether to approve or deny the loan. The bank officer needs to gather sufficient information to ensure the company can pay back the loan. An analysis of the financial statements will tell the company's profitability, liquidity, and also their solvency. Income Statement Net Sales – Net sales in year 12 were $6,520,500 and increased to $6,729,800 in year 13. This is an increase of $209,300 or 3.21%. In year 14, sales again increased to $6,858,600 which is a difference between year 13 and 14 of $128,800 or 1.91%. Increasing sales from year to year is a sign of strength and shows the company is in a good position to...

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